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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ach case:4.) - 2 = – 53x– 156x + 5 = 2x +1 |
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| 2. |
Co.921)+ 30-78511:713 X (2-683)2 |
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Answer» 0.033076161=(0.321)^3; 3V0.789=2.6677 ; V1.713=1.03881; (2.683)^2=7.198; 0.033076+2.6677/1.03881×7.198=2.70076/7.47735438=0.3611919222 |
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| 3. |
A car is travelling at a speed of 55 km/h. How far will it travel in 2 hours and 12 minutes? |
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| 4. |
ach diagonal of a square is 12 cm long. Its area is |
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Answer» 24cm is carried answer |
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| 5. |
4. If a point lies between two points andach that POOR.prove that |
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| 6. |
EXERCISEach1. Fill in the blanks with correct from ofPronoun:(1) are you? |
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Answer» correct answer is (How) |
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| 7. |
The radius of a sphere is measured to be5.3+-0.1 cm. The percentage error in volumeis- |
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Answer» Secondary School Physics 10 points The radius of a sphere is measured tobe (5.3+-0.1)cm.calculate the percentage error in volume Ask for details Follow Report byQassim976601.08.2017 Answers  Launeticfringe Helping Hand The volume is given as V = (4/3)πr3 so, V = (4/3) x 3.14 x 5.33 thus, V = 623.30 cm3 now, the error equation ΔV/V = 3(Δr/r) or ΔV = V x 3(Δr/r) thus, ΔV = 623.30 x 3x(0.1/5.3) or error in surface area ΔV = +/- 35.28 cm3 thus, ΔV/V x 100 = (35.28/623.30) x 100 so, ΔV/V x 100 = 5.66 % |
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| 8. |
On increasing the radius of a sphere by 10%, find the percentageincrease in its volume. |
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| 9. |
Find the percentage increase in volume of acube if its each side is increased by 50%. |
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Answer» edge of cube = x cm, surface area = 6x^2______(1), edge=50°\°=x+ 50\100x= X + x/2=3x\2, surface area =6(3x\2)^2=6(9x^2/4)= ÷27x^2/2____________(2), increase in s.a= 27x^2/2-6x^2=27x^2-6x^2/2=15x^2/2,;, increase in SA/original SA x 100=15x^2/2/6x^2 x 100 =125°\° Explanation: Let the edge = a cm So increase by 50 % = a + a/2= 3a/2 Total surface Area of original cube =6a26a2 TSA of new cube =6(3a2)263a22=6(9a24)69a24= 13.5a213.5a2 Increase inarea =13.5a2−6a213.5a2-6a2=7.5a27.5a2 7.5a27.5a2Increase % =7.5a26a2×1007.5a26a2×100= 125% |
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| 10. |
6. Covert 785 piase into Rupees? |
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Answer» We know,1 rupee = 100 paise Then,785 paise = 785/100= 7.85 rupees= 7 rupees 85 paise > 1 Rupee = 100 Piase> 785÷100 = 7.85 > 7 Rupees 85 Piase |
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| 11. |
9. Express 8 hours as a percentage of 2 days. |
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Answer» in 2 days we have 48 hours.so, %= (8/48)*100=16.67% |
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| 12. |
7. Yogesh studied for 2 hours 55 minutes in the morning and 1 hour50 minutes in the evening. For what time did he study in all ? |
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| 13. |
PE--ĐŁ35 |
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Answer» According to the given questionL.C.M. of two numbers = 3H.C.F of two numbers = 105Then,L.C.M. × H.C.F. = 3 × 105X × Y = 3 × 105 [Because we know that, If X and Y are two numbers then (L.C.M. of X and Y) × (H.C.F. of X and Y) =X × Y]X × Y = 315 ______________ (1) Also given in the question X + Y = 36 _______________ (2) ( X + Y )/(X × Y) =36/315 X/(X × Y) + Y/(X × Y) = 36/315 1/Y + 1/X = 4/35 |
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| 14. |
34. The pendulum of a certain clock has time period 204 s.How fast or slow does the clock run during 24 hours?35 A pendulum cloek n |
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| 15. |
DaPe |
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Answer» For 1st:16.x^2.y^3.z^2(2xy - 3z^2) For 2nd:xy(ax+by)+cxyzxy{(ax+by) + cz}xy(ax+by+cz) |
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| 16. |
4. In a circle of radius 7 cm, tangent PT is drawnfrom a point P such that PT = 24 cm. If O is theCentre of the circle then OP ?(a) 30 cm(c) 25 cm(b) 28 cm(d) 31 cm944 |
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| 17. |
Concert each part of the ratio to percentage:a)3:1b)2:3:5 |
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| 18. |
16) What percentage is(i)ă15 of 120? |
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Answer» The value is = 15and total value is = 120 By formula , = (15/120 )* 100 = ( 0.125)*100 = 12.5% Like if you find it useful but what meaning about (15/120)*100 I am not understand =15×100÷120=150÷12=75/6=12.5% |
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| 19. |
1fset A-(2, 3, 5, 71,B-(1,s,Convert the following ratio in the percentage. 12 : 20. |
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Answer» ratio is 12/20=6/10=3/5hence percentage will be 3/5*100=60% |
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| 20. |
Convert the following ratios into percentage.(a) 2:5(b) 15:16 |
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Answer» 2×100/5 = 40% 15×100/16 = 93.75% |
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| 21. |
covert 4/15 in percentage |
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Answer» 4/15 *10026.6 will be the answer |
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| 22. |
factorization problems x²+2x-24 |
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Answer» factorization problems |
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| 23. |
Express 8 hours as a percentage of 2 days.Find 15% less than 75. |
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Answer» we have 24 hours in a dayso number of hours in 2 days will be 48 so percentage will be (8/48)*100=(1/6)*100=16.67% ring answer |
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| 24. |
9. (a) What is 24 hour clock?(b) Name two organisations which use 24 hoclock.(c) The time on 24 hour clock is(i) 08 h 37 min(ii) 23 h 48 min. Express the time on 12 hclock |
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Answer» The 24-hour clock is the convention of time keeping in which the day runs from midnight to midnight and is divided into 24 hours, indicated by the hours passed since midnight, from 0 to 23. This system is the most commonly used time notation in the world today, and is used by international standard ISO 8601 Military, some airlines, train companies, taxi offices. uses 24 hrs clock |
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| 25. |
19. Find the angle between the hour andminute hand of a clock showing the time7 hours 35 minutes. |
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Answer» aθ= |30H-11M/2| where H= Hour, M= Minute = |30×7-11×35/2| = |210-192.5| = 17.5 degree |
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| 26. |
5. If PT is a tangent to a circle with centre Oand PQ is a chord of the circle such thatLQPT = 70°, then find the measure of 40Q.Oo0 |
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| 27. |
The hour hand of a circular clock is 10cm long. How much distance willit cover in 2 days or 48 hours? |
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Answer» thanks |
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| 28. |
\frac { f ( x + h ) - f ( x ) } { h } , \text { where } ( a ) f ( x ) = 2 x + 3 \quad ( b ) f ( x ) = \frac { 1 } { x + 1 } \quad ( c ) f ( x ) = x ^ { 2 } |
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Answer» where is B if i may ask |
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| 29. |
From a point P, 10cm away from the centre of a circle , a tangent PT of length 8cm isdrawn . Find the radius of the circle. |
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| 30. |
2. Convert into percent |
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| 31. |
2. Express as a percentage32b.C.410 |
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Answer» a) 2/5 × 100 = 2 × 20 = 40% b) 3/4 × 100 = 3 × 25 = 75% c) 9/10 × 100 = 90% |
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| 32. |
3/8 into percentage. |
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Answer» Fraction to percentage3/8 × 100 = 37.5 % |
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| 33. |
3. Convert 34 into percentage |
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Answer» 34 is 34th part of 100 so, in percentage it will be 34% |
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| 34. |
Factorization of the polynomial |
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Answer» 😀 thanx |
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| 35. |
factorization of 9x2-64 |
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Answer» 9x^2-64(3x)^2-(8)^2(3x+8)(3x-8)thanks please like the solution 👍 ✔️ |
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| 36. |
convert 08:15 P.M in 24 - hour clock |
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Answer» 8 : 00 PM will be 20 hours15 minutes will be sameSo, 8 : 15 PM will be 20 : 15 hours |
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| 37. |
convert into percentage 15\25 |
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Answer» Percentage=(15/25)*100=15*4=60% |
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| 38. |
A sells an object to B on 30% loss and B sells that object again to A on 30% profit. Find outoverall profit/loss percentage to A.ų,倆功飒前团癩30%an卂硎き阿T: , |
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Answer» Let Cost price of object = CPA sell object to B at price = CP(1 - 30/100)= CP(1 - 3/10) = (7/10)CP B sell object to A at price = (7/10)CP( 1 + 30/100)= (7/10)*(13/10)CP=( 91/100)CP Overall loss percentage for A= [(91/100 - 7/10)/7/10]*100=[( 91-70/100)*10/7]*100= (21/70)*100= 30 % |
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| 39. |
14. X bought a certain quantity of oranges for anamount of'äš1,800. He sold two-fifths of those at aloss of 20%. He earned an overall profit of 15%.At what approximate profit percentage did X sell therest of the oranges?(1) 30.33%(3) 38.33%(5) 46.33%(2)(4)34.67%42.67% |
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Answer» Total C.P = Rs 1800 Overall Profit = 15% of 1800 = 15*1800/100 = Rs 270 Total S.P = 1800 + 270 = Rs 2070 C.P of 2/5 oranges = 2/5 of 1800 = 720 Loss = 20% of 720 = Rs 144 S.P of 2/5 oranges = 720 - 144 = Rs 576 Now C.P of remaining 3/5 oranges = 1800 - 720 = Rs 1080S.P of 3/5 oranges = 2070 - 576 = Rs 1494 Profit = 1494 - 1080 = 414 Profit% = 414*100/1080 = 38.33% thanks |
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| 40. |
Convert 5-15 PM into the time of a 24 hours clock. |
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Answer» 17 hour 15 minutes is the answer of this question |
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| 41. |
Q13(b). If f(x)= log (1+x), show that:f(x)+F(%) = r * |
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Answer» It's simple f(x) is given and you put on f(y) in given x conditions and put value of f(x) and f(y) in equation |
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| 42. |
14. Two cross roads, each of width 5 m, run at right angles through the centre of a rectanquląrpark of length 70 m and breadth 45 m parallel to its sides. Find the area of the roads. Also, indthe cost of constructing the roads at the rate of Rs 105 per m |
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| 43. |
(11H25P - RS 1200 R - 12% 1 = 2 yrsTwo cross roads, each of width 5m, ran at right angles through the centre pt rectanlength 70 m and breadth 45 m and parallel to its sides. Find the area of the roads. Alsocost of constructing the road at late of 105 per m.11 |
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| 44. |
8% convert following percent into ratio : |
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Answer» 8%=8/100=8:100=2:25 2:25 is your answer by simplyfy 2:25 is the correct answer of the given question 8%means 8/1004/502/25ie ratio is 2 :25 8% 8/1008:1002:25 Solution :- 8%= 8÷100 =2/25= 2:25 Ans. 8%means 8/1004/502/25ie ratio is 2:25 8%=8/100=2/25=2:25 8 °\° = 8 / 100 = 0 . 08 8%=8/100=8:100=2:25 8/1008:100 is the correct answer |
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| 45. |
ample 6 Express the following in the form a + ib5+v2i(1)(ii) i-35 |
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Answer» (1) 5 + root(2)i/1 - root(2)i = (5 + root(2)i)(1 + root(2)i)/ (1)^2 - (root(2)i)^2 = 5 + 6root(2)i - 2/ 1 + 2 = 5 + 6root(2)i/3 = 5/3 + 2root(2)i (2) i^-35=i^-34-1=(i^2)^-17×(i^-1)=(-1)^-17*(1/i)=1/(-1)^17*(1/i)=(-1)(1/i)=-1/i=0+i(-1/i^2)=0+i(-1/-1)=0+i.1where a=0, b=1 |
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| 46. |
convert the ratio 4:6 in percentage |
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Answer» Given ratio=4:6 Percentage=(4/6)*100=66.67 thanks |
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| 47. |
1.Convert the ratio into percentage 3:4 |
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Answer» 3×100/4=75%{please like answer |
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| 48. |
2. Convert each part of the ratio to percentage:(b) 2:3:5 |
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| 49. |
Sanjay bought a machine for ₹ 95000. After using it for 2 years , he sold it. if it's value gets depreciated by 20% and 15% annually respectively , what will he get for machine ? |
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Answer» it will be after first year 95000*20/100=1900095000-1900076000now after second year76000*15/100=1140076400-1140065000 will be the final value |
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| 50. |
2i) 4x +11x-20-0 (By factorization metho |
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