The radius of a sphere is measured to be5.3+-0.1 cm. The percentage er

1.	The radius of a sphere is measured to be5.3+-0.1 cm. The percentage error in volumeis-
Answer» Secondary School Physics 10 points The radius of a sphere is measured tobe (5.3+-0.1)cm.calculate the percentage error in volume Ask for details Follow Report byQassim976601.08.2017 Answers Launeticfringe Helping Hand The volume is given as V = (4/3)πr3 so, V = (4/3) x 3.14 x 5.33 thus, V = 623.30 cm3 now, the error equation ΔV/V = 3(Δr/r) or ΔV = V x 3(Δr/r) thus, ΔV = 623.30 x 3x(0.1/5.3) or error in surface area ΔV = +/- 35.28 cm3 thus, ΔV/V x 100 = (35.28/623.30) x 100 so, ΔV/V x 100 = 5.66 %

The radius of a sphere is measured to be5.3+-0.1 cm. The percentage error in volumeis-

Answer»

Secondary School

Physics

10 points

The radius of a sphere is measured tobe (5.3+-0.1)cm.calculate the percentage error in volume

Ask for details

Report

byQassim976601.08.2017

Answers

Launeticfringe

Helping Hand

The volume is given as

V = (4/3)πr3

so,

V = (4/3) x 3.14 x 5.33

thus,

V = 623.30 cm3

now, the error equation

ΔV/V = 3(Δr/r)

ΔV = V x 3(Δr/r)

thus,

ΔV = 623.30 x 3x(0.1/5.3)

or error in surface area

ΔV = +/- 35.28 cm3

thus,

ΔV/V x 100 = (35.28/623.30) x 100

so,

ΔV/V x 100 = 5.66 %