1.

Find the percentage increase in volume of acube if its each side is increased by 50%.

Answer»

edge of cube = x cm, surface area = 6x^2______(1), edge=50°\°=x+ 50\100x= X + x/2=3x\2, surface area =6(3x\2)^2=6(9x^2/4)= ÷27x^2/2____________(2), increase in s.a= 27x^2/2-6x^2=27x^2-6x^2/2=15x^2/2,;, increase in SA/original SA x 100=15x^2/2/6x^2 x 100 =125°\°

Explanation:

Let the edge = a cm

So increase by 50 % = a + a/2= 3a/2

Total surface Area of original cube =6a26a2

TSA of new cube =6(3a2)263a22=6(9a24)69a24= 13.5a213.5a2

Increase inarea =13.5a2−6a213.5a2-6a2=7.5a27.5a2

7.5a27.5a2Increase % =7.5a26a2×1007.5a26a2×100= 125%


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