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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the roots of equation 16x-10/x=27 |
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Answer» Given 16x - 10/x = 27⇒ (16x²- 10)/x = 27⇒ 16x² - 10 = 27x⇒ 16x² - 10 - 27x = 0⇒ 16x² - 27x -10 = 0⇒ 16x² - 32x + 5x - 10 = 0⇒ 16x(x - 2) + 5(x - 2) = 0⇒ (x - 2) (16x +5 ) =0⇒ (x-2) = 0 or (16x + 5) = 0⇒ x = 2 or 16x = -5⇒ x = 2 or x = -5/16∴ x = 2 , -5/16 |
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| 2. |
If f(x) = (xx2-16x +20(x-2)22 is continuous of x-2, then find Îťx |
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| 3. |
plx) = 3x +48 +5x-13.9(x) - 38 40, 4x)=16x-43find g(x)? |
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| 4. |
find the value of (1+w-w²)3. |
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| 5. |
Find the area of sector of a circle havingradius 4 cm and angle 40(a) 5.59 cm2(c) 5.5 cm2b) 6.2 cm(d) of these |
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Answer» 5.59cm^2 |
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| 6. |
lementaxy w{_\& 3 |
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Answer» When the sum of the measures of two angles is180°, such angles are called supplementary angles and each of them is called a supplement of the other. Given 25°180°-25°=155° |
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| 7. |
w+3=4? |
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| 8. |
The anglusJnd the measu |
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| 9. |
46. In the given figure, DE and DF are tangents froman external point D to a circle with centre A. IfDE 5 cm and DE L DF then the radius of thecircle is(a) 3 cm(c) 5 cmCBSE 2013](b) 4 cm(d) 6 cm |
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| 10. |
. The ratio of areas of circle A to circle B is 5:4. If the radius of circle Bis 28 cm, what is the area of circle A? |
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| 11. |
A survey conducted on 20 households in a locality by a group of students resulted in the followingfrequency table for the number of family members in a household. 2aFamily sizeNo. of families1-33-55-77-99-11722Find the mode of this data. |
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| 12. |
The sum of first, third and seventeenthterms of an AP is 216. Find the sum of thefirst 13 terms of the AP |
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| 13. |
Find the smallest positive integer n for which[(1+i)/(1-i)]^n=1 |
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| 14. |
13. Find the smallest positive integer with which 1445 has to bemultiplied to get a perfect square. |
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Answer» 1445 = 17 x 17 x 5 Here 5 occur only once. So we have multiply by 5 to get a perfect square. |
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| 15. |
which of the following is the smallest positive integer which gives the remainder 3 when divided with 4.08, and 10?(A) 73(B) 103(C) 123(D) 243 |
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Answer» c) 123 is the answer D is answer answer is both (c) and (d) |
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| 16. |
The sum of first 9 terms of an A.P. is 162. The ratio of its 6th term to its 13thterm is 1:2. Find the first and fifteenth terms of the A.P2. / |
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Answer» If you like the solution, Please give it a 👍 |
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| 17. |
42.) The sum of first 9 terms of an A.P. is 162. The ratio of its 6th term to its 13thterm is 1:2. Find the first and fifteenth terms of the A.P. |
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| 18. |
Find the mean size.The mean age of 5 children of a family is 12 years. If four of them are respectively 6, 11, 13 and 16age of the fifth child.l5. |
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Answer» Average=Sum/number12=6+11+13+16+x/512*5=60=46+xx=60-46=14 |
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| 19. |
ChH which are inclined to each other at anlaking A as centre, draw a circle of radius 4 cmjnd uaking B as centre, draw another circle of radius 3 cm. Construct tacircle from the centre of the other circle. |
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| 20. |
Whatis the smallest integer? |
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Answer» Larger the no of a negative integer ,the smaller it is As there is no largest positiveinteger,there is nosmallestnegativeinteger. Thesmallestnegativeintegerdoes not exist. It is infinity -infinity.well it cannot be calculated.. |
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| 21. |
What is the smallest integer ? |
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Answer» As there is no largest positiveinteger,there is nosmallestnegativeinteger. Thesmallestnegativeintegerdoes not exist. It is infinity it is 1.and start focusing on ur studies it is unknown( -infinity) yo Mohitbesi pubg khelyo vaneh aestai huncha amazing copy pasting skills👏👏👍👍 |
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| 22. |
The least perfect square number, which is divisible by 21, 36 and 66 is:(H 213444 (2) 214344 (3) 214434 (4)231444 |
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Answer» LCM of 21, 36, 66 is 3^2,2^2, 7,11. So the smallest perfect square should be 3^2x2^2x 7^2x11^2=213444. 213444 is right answer perfect square number of 21,36,66. LCM of 21,36,66 is 3^2,2^2,7,11.so smallest perfect square should be 3^2x2^2x7^2x11^2=213444 |
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| 23. |
Section-D(3questions x 4 marks each 12 marpQues. 10) The angles of quadrilateral are in the ratio 3:5:7:9. Find the measure of each of these angles.5 2 4 h2 + 28 bc 49 c.sao |
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| 24. |
find the first 13 terms of an ap if 7th term is 40 |
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| 25. |
7th term of an AP is 40, then the sum of first 13 terms is |
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| 26. |
24. The sum of first 20 terms of an AP is 400 and sum of first 40terms is 1600. Find the sum of its first 10 terms. |
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| 27. |
If x is an integer satisfying x2 - 6x +5 s 0 andx2 - 2x > 0 then the number of possible valueofx is |
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Answer» For the first equation, x belongs [1,5] and for the second equation, x comes to be (-infinty,0) union (2,infinity) And so integers in their intersection will be 3,4 and 5 |
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| 28. |
D = \left| \begin{array} { c c c } { 1 } & { - 1 } & { 1 } \\ { 2 } & { 1 } & { - 3 } \\ { 1 } & { 1 } & { 1 } \end{array} \right| = 10 |
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Answer» Thnx... |
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| 29. |
Ex. 13. Find the smallest positive values of x and y satisfyingx _ y-, and cotx + coty-2.4'[Roorkee 2000] |
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| 30. |
28Thesumofthefirst9termsofanAPis81andthatofitsfirst20termsis400 Find the first term and the common difference of the AP. (cBSE 2009 |
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| 31. |
e sum of 3yd and 7th terms of an A P is 6 and their product is 8. Find the sum of first 20 terms of theA.PTh |
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| 32. |
9-119Family size5-71-33-522Number of familiesFind the Mode of this data |
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| 33. |
Find the perimeter of the adjoining Figure (b). (Take T 3.14)Figure (a)7. A wheel has radius 42 cm.(a) Find the distance covered in 700 revolutions.(b) In how many revolutions will it cover a distance of 3 km 960 m?&The ratio of areas of circle A to circle B is 5:4. If the radius of circle B4 cmis 28 cm, what is the area of circle A?What is the area of the shaded part of Figure (c)?Figure (by |
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| 34. |
R R .(1) 12075 (2) 12000 ~ (3) 16000 (4) 180006. सौरभ अपनी मासिक आय का द भाग खर्च कर देता है। यदि वहएक महीने में 624 रु. बचाता है, तो उसकी वार्षिक आय क्या है?(7) बब928 रु. (2) 45028 रु. (3) 44900 रु. (4) 44950 .It agile * il L L8 1 “पु 2. पर कि LRS- |
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Answer» सौरभ की आय महिने की x मानते है। 5/6 खर्च करता है तो 1/6 बचेगा x/6 = 624 x = 3744 एक महिने की आय 3744 है वार्षिक आय 3744 × 12 = 44928 है। If you find this answer helpful then like it. |
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| 35. |
7. Find the sum of first 20 terms of an A.P. 1,3,5,7,9... |
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Answer» =n(n+1)n=20s20=20(20+1) =20*21 =420 sum of first odd numbers =n*n n=20s20=20*20 =400 |
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| 36. |
47. The greatest number which diviues 0exactly is 312. Find the smallest number whiohis divisible by 624 and 936. |
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Answer» To find the smallest number which is divisible by 624 and 936, we need to find the LCM of these numbers. We can write these numbers as a factor of 312 as follow: 624= 2 x 312 936= 3 x 312 Now, LCM(624,936)= 312 x 2 x 3 => 1872 Like my answer if you find it useful! |
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| 37. |
) 624Pind the least perfect square number which is exactly divisible by 8, 9 and 10.(ii)2925(111) 3903. |
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Answer» L.C.M. of 8,9,10 is 2*2*2*3*3*5=360Since 2 and 5 are not in pairs multiply by 2 and 5 to make it a perfect square.The required number=360*2*5=3600The smallest square number divisible by 8,9,10=3600. |
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| 38. |
The rationalising factor of%2b3c4Al 3,2is(D) Va b c(c)la'b2c3 h2CLASS 9 |
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Answer» Y 1 - 2/5= 3/5 ksa aaya |
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| 39. |
Let A be the sum of the first 20 terms andB be the sum of the first 40 terms of theseries12+2.22+32+2-42+52+2-62 +....If B-2A-100A, then N is equal to(1) 232(2) 248(3) 464(4) 496 |
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| 40. |
पक a 0 1ठ 5|b पं a Va Va6) \." aप्रश्न 15. यदि ८ और | द्विघात' समीकरण2+* + 5: -6 -0 के मूल हैं तो प्प्छि + (L‘P)A का मानज्ञात कीजिए। (2016)=0 |
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| 41. |
6. The nth term of an A.P is given by (-4n 15)Find the sum of first 20 terms of this A.P |
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| 42. |
30. Which is the smallest integer?(A) 1(B) 0(C)-1(D) 2(E) of these |
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Answer» If you find this solution helpful, Please like it. |
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| 43. |
.Find the absolute value of the smallest integer satisfying the equation 2/x+2 -12x+1 -119x+1 |
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Answer» 0 is the right answer to this question. 0 is the right answer to this question. the correct ans is 0... 0 is the correct answer |
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| 44. |
The areparallel sides are in the ratio 3: 4 andthe perpendicular distance betweenthem is 11 cm. Its longer side is:(a) 35 cnm(c) 40 cma of a trapezium is 385 cm2. Its(b) 30 cm(d) 60 cm |
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Answer» Given > height of trapezium = 11cmLet the common multiple be x ; thenthe sides will bea = 3xb = 4x Area of trapezium = (1/2)×(sum of parallel sides)×h385 = (1/2)×(3x+4x)×11 x = 10 The length of the longer side= 4x= 4×10= 40 cm |
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| 45. |
19. If of a number exceeds itsby 44, find the number3527 |
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| 46. |
De ratio of the length of the parallel sides of a trapezium is 5:3 and the distance betweenremis 16cm. If the area of the trapezium is 960 cm", find the length of the parallel sides |
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Answer» Let the side be 5x and 3xgiven height =16 cmarea =960960=1/2×16×(5x+3x)960=8×8x64x=960x=960/64x=15 |
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| 47. |
ודור רוזוודור רוזווז : ז זזה הזזה רוחThe sum of first 8 term of an AP is 100 and sum of first 19 terms is 551. Find AP. |
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| 48. |
Define the field of quotients of anintegra. domain. |
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Answer» Afieldwhose elements are pairs of elements of a given commutativeintegral domainsuch that the second element of each pair is not zero. Thefieldof rational numbers is thefield of quotientsof theintegral domainof integers. Thanks bhai |
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| 49. |
STT EXERA. Find the estimated quotients :1. 624 16 2. 482 - 46 |
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Answer» 1=39,2=241/23 just division Your correct answer is1-- 392-- 52/5 1-392-10.47 is the right answer please like my answer |
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| 50. |
5.Find three consecative numbers such that if theyare divided by 10, 17, and 26 respectively, thesam of their quotients will be lo.Soilo |
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Answer» Let X, (X+1), (X+2) are 3 consecutive numbers. X/10 + (X+1)/17+ (X+2)/26 =10 L.C.M = 4420 (442(X) +260(X+1) +170(X+2))/4420=10 (442x+260x+260+170x+340)= 4420×10 (442x+260x+170x+260+340)=44200 872x + 600= 44200 872x= 44200- 600 872x= 43600 X= 43600/872 X= 50_____________________________Ist no. (X)= 502nd no.(x+1)= 50+1= 513rd no.(x+2)= 50+2= 52____________________________The 3 consecutive numbers are 50, 51, 52_____________________________ |
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