1.

The areparallel sides are in the ratio 3: 4 andthe perpendicular distance betweenthem is 11 cm. Its longer side is:(a) 35 cnm(c) 40 cma of a trapezium is 385 cm2. Its(b) 30 cm(d) 60 cm

Answer»

Given > height of trapezium = 11cmLet the common multiple be x ; thenthe sides will bea = 3xb = 4x

Area of trapezium = (1/2)×(sum of parallel sides)×h385 = (1/2)×(3x+4x)×11

x = 10

The length of the longer side= 4x= 4×10= 40 cm



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