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Find the roots of equation 16x-10/x=27 |
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Answer» Given 16x - 10/x = 27⇒ (16x²- 10)/x = 27⇒ 16x² - 10 = 27x⇒ 16x² - 10 - 27x = 0⇒ 16x² - 27x -10 = 0⇒ 16x² - 32x + 5x - 10 = 0⇒ 16x(x - 2) + 5(x - 2) = 0⇒ (x - 2) (16x +5 ) =0⇒ (x-2) = 0 or (16x + 5) = 0⇒ x = 2 or 16x = -5⇒ x = 2 or x = -5/16∴ x = 2 , -5/16 |
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