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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
232 An aeroplane when flying at a height of 3125 mfrom the ground passes vertically below anotherplane at an instant when the angles of elevation ofthe two planes from the same point on the groundare 30° and 60° respectively. Find the distancebetween the two planes at that instant. |
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| 2. |
3+2V2V2+12 -18. Show that= |
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Answer» By rationalization property |
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| 3. |
\begin{array}{l}{\text { Find the inverse Laplace transforms of: }} \\ {\quad(i) \tan ^{-1}\left(\frac{2}{5}\right)}\end{array} |
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| 4. |
Frequency | 179 | 150 157- 149 111s IFind the probability of getting each outcome.T H)22. The sides of a triangle are in the ratio 13:14:15 and its perimeter is 84 cm. Find the area of thetriangle.SECTION-D |
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| 5. |
26. The sides of a triangle are in the ratio 15 13 14 and its perimeter is 168 cm. Findthe area of the triangle. |
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| 6. |
side of triangle is 13 , 14 , 15 then area |
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Answer» By Heron's formula, A = √(s*(s-a)(s-b)(s-c)) where s is half the perimeter. s = (13+14+15)/2 = 21 s-a = 21-13 = 8 s-a = 7 s-c = 6 A = √(21*8*7*6) = √(7056) = 84 |
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| 7. |
-7 %2B 21 |
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Answer» -3 is the correct answer -3 is the right answer -3 is the correct answer. -3 is the right answer.... Divide 21/-7 = -3 i hope my answer will help you😊😊😊 -3 is the correct answer of the given question 3 is the answer because +,+=- ,- -= - ,+ - = + ,- + = + divide -7 by 21.21÷(-7)=-3 -3 is answer it is correct Your correct answer is-3 -3 is the best answer 💥 |
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| 8. |
-8 %2B 21 |
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Answer» 13 12 is the right answer 1312 is the correct answer 13,12 is the correct answer of the given question 1) 132) 12 is the following answer 13 and 12 is the right answer... 13 12 is the right answer 1. 21 - 12 ÷ 3 × 2=21 - 4 × 2=21 - 8=13 2. 16 + 8 ÷ 4 - 2 × 3=16 + 2 - 2 × 3=16 + 2 - 6=16 + (-4)=16 - 4=12 1.) 21 - 12 ÷ 3 × 2= 21-4×2=21-8=13 answer 2.) 16+8÷4-2×3=16+2-2×3=16+2-6=12 answer 13 is right answer.... 13 and 12 are the answer of the following |
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| 9. |
S. What is the positive value of m forwhich the roots of the equation12x2 + mx + 5 = 0 are in the ratio3: 2?(a) 5√10 (b)5√10 /12 (c) 5/12 d) 12/5 |
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Answer» Let the roots beα,β αβ=32 α+β=−m12 αβ=5/12 α=3/2β⇒3/2β²=5/12 |
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| 10. |
4(3x+1)=15x-7 |
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Answer» 12x + 4 = 15x - 74+7 = 15x - 12x11 = 3x11/3 = xis correct answer |
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| 11. |
1) x2 + 15x +50 |
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Answer» x² + 15x + 50 x² + 5x + 10x + 50 x ( x + 5) + 10 ( x + 5) ( x + 5) ( x + 10) |
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| 12. |
gross(a) 5(e) 10(a) 5% वृद्धि(b) 5% हास।(c) 10% वृद्धि(d) 10% हास. • किसी विद्यालय में लड़के तथा लड़कियाँ 3:2के अनुपात में हैं। यदि20%लड़के तथा 30%लड़कियाँ छात्रवृत्ति लेने वाले विद्यार्थी हैं, तो उनविद्यार्थियों का प्रतिशत जो छात्रवृत्ति नहीं लेते हैं, होगा।(a) 50b) 7246. TheIf 20holdescho |
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Answer» It's 72 answer is correct |
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| 13. |
-4 respectively Find gexlground and at tbe sasR4. A vertical stick of length 6 m casts a shadow 4 m long, on thetower casts a shadow 28 m long Find the height of the towerncn interect each oher at O such that AS |
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Answer» AB is the pole and BC is the shadow of pole. Given, AB = 5 m and BC = 2 m. PQ is the tower and QR is the shadow of tower. Given, QR = 9 m Let the height of tower behm. Since the length of shadow of pole and tower area measured at the same times, so the angle of elevation of source of light for both is same at that moment of time. ∴ ∠C = ∠R In ΔABC and ΔPQR, ∠B = ∠Q (90°) ∠C = ∠R ∴ ΔABC= ΔPQR (AA similarity) ab/pq = bc/qr 5/h = 2/9 h = 45/2 = 22.5 Thus, the height of tower is 22.5 m. Like my answer if you find it useful! |
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| 14. |
8th term of the series 2√2+√2 +0+..... will be(a)-5√2(c) 10√2(b) 5√2(d) -10√2 |
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Answer» a = 2√2 d = √2-2√2 = -√2 8th term = 2√2 + (8-1)(-√2) = 2√2-7√2 = -5√2 |
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| 15. |
tan inverse 2x / 1+15x^2 find dy/dx |
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| 16. |
(1) x2-15x + 54 = 0 |
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Answer» x² - 15x + 54 = 0 x² -6x -9x + 54 x( x - 6) -9( x - 6) (x -9)(x -6) So, x = 6 and x = 9 Please hit like if you find my useful |
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| 17. |
âSolve: 15x/7+9-1/5/ |
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| 18. |
(1) x2-15x + 5 = 04 |
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Answer» =x²-9x-6x+54=x(x-9) -6(x-9) =(x-6) (x-9) |
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| 19. |
(11-5)×(12+(3+11-14)) |
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| 20. |
a vertical stick 20m long casts a shadow 10m long on the ground.at the same time a tower casts a shadow of 50m long on the ground.what is the height of the tower |
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| 21. |
-47 %2B 11 %2B 21 |
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| 22. |
22. A vertical pole of length 6 m casts a shadow 4 m long on tand at the same time a tower casts a shadow 28 m long. Fheight of the tower. |
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| 23. |
A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the sametime a tower casts a shadow 28 m long. Find the height of the tower. |
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Answer» Length of the vertical pole = 6m (Given) Shadow of the pole = 4 m (Given) Let Height of tower =hm Length of shadow of the tower = 28 m (Given) In ΔABC and ΔDEF, ∠C = ∠E (angular elevation of sum) ∠B = ∠F = 90° ∴ ΔABC ~ ΔDEF (By AA similarity criterion) ∴ AB/DF = BC/EF (If two triangles are similar corresponding sides are proportional) ∴ 6/h= 4/28 ⇒h= 6×28/4 ⇒h=6 × 7 ⇒h= 42 m Hence, the height of the tower is 42 m. |
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| 24. |
2*x^2 %2B 11*x %2B 12 |
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Answer» let the constant number be added and =2+11+12=25 2+11+12 =25 is the correct answer |
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| 25. |
11/12 %2B 3 %2B 7 |
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Answer» 22/12 is the right answer |
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| 26. |
(x^4-x^3-6x+10)/(x+1) |
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| 27. |
3x + 54x - S6x - 10B5. Solve for x in each parallelogram. |
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Answer» opposite side of parallelogram are equal 3x + 5 = 6x - 10 3x = 15 x = 5 |
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| 28. |
QUESTIOme a solid withonly one curved face |
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Answer» Cone |
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| 29. |
15. x^5 + x^4 +x^3+ x^2 + x +1 by x ^3+1 |
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| 30. |
1. Which of the following is equal to x3 -225x(a) x(1-15x) (1 + 15x)(c) x(1 15x) (1-15x)(b) x(x - 15) (x +15)(d) x(1 +15x) (1-15x) |
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Answer» thanks😀😂😁 |
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| 31. |
RCISE 6 (G)3. 2x2 +11x +12T. 13x2 +37x - 611. 1-t-66213. 12m² +6m² - 6m(c) - b(462-1) (36(db(1 - 2b) (1 + |
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Answer» 13x²+37x-613x²+39x-2x-613x(x+3)-2(x+3)(x+3)(13x-2) 13x²+37x-6=13x²+39x-2x-6=13x(x+13)-2(x+3) =(x+3)(13x-2)x= -3,2/13 hope this will help you like my answer |
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| 32. |
((8/12)*a)*(7/9 %2B 11/13) |
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| 33. |
(3*12)/11 %2B 4 |
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Answer» 4+12*3÷11Using BODMAS4+12*3/1144+36/11=80/11 |
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| 34. |
An express train 80 metres long is running at a rate of 45 km/h. How much time will it take tocross a platform 220 metres long? |
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Answer» ss where is the answere |
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| 35. |
9. A train is running at a speed of 48 km/h. How long will it take to reach a signal at a distance of80 metres from the starting platform? |
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Answer» 48km/h = 48×1000/3600 m/s = 48×5 /18 = 24×5/9 = 8×5/3 = 40/3 m/s.for 80m, time= 80÷40/3 = 80×3/40 = 6s |
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| 36. |
Point G is the centroid of Δ ABC(1) If I(RG) 2.5 then I(GC) -enc and I(GP) |
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| 37. |
rg1. f two tangents inclined at an angle of 90°, are drawn to a circle of radius 3 cm,and then find the length of each tangent. |
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Answer» thanksss alot |
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| 38. |
x ^ { 2 } - 5 x + 1 = 0 , \text { then } \frac { x ^ { 10 } + 1 } { x ^ { 5 } } |
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| 39. |
Show that the rectangle of maximum perimeter which can be inscribed in a circle ofradius r is the square of side rV2. |
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| 40. |
4. Name the one solid from your environment whicwill cast the following shadow:(a) Square(b) Circle(c) Triangle(d) Rectangle.ct by looking at it from different andifferent angles. Example is shown here of a b |
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Answer» Square - DieCircle - AppleTriangle - Ice cream coneRectangle - Brick |
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| 41. |
= 9 z %2B z i |
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Answer» 12+26=38 |
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| 42. |
Vtan x. dxsın χ .cos χ |
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| 43. |
Vtan x23.dxINCERT]sin x cOS X |
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| 44. |
T. An express train 180 metres long is running with a speed of 72 km/h. In what time will atelectric pole? |
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Answer» where is the answere where is the answer |
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| 45. |
3. An express train 80 metres long is running at a rate of 45 km/h. How much time will it tuecross a platform 220 metres long? |
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Answer» where is the answer |
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| 46. |
25 x^{2}+4 y^{2}+9 z^{2}-20 x y+12 y z-30 x z |
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| 47. |
3^z=9^z+5 |
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Answer» 3z-9z =5-6z=5z=5/6 3^z-9^z=5; -6z = 5; z = 5/6 |
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| 48. |
Exercise 14.3the following, find the length of the third sideInso that the three sideTake C 90°)(0) a 1 cm, 2.6 cms make a right triangle. |
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Answer» Let third side be bUsing pythagoras theorem,a²+b²=c²1²+b²=(2.6)²b²=(2.6)²-1²b²=(2.6+1)(2.6-1)b²=3.6*1.6b=2.4cm |
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| 49. |
Q2. A vertical pole of length 6 m casts a shadow 4 m long on the groundand at the same time a tower casts a shadow 28 m long. Find theheight of the tower. |
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Answer» Angle of sun will be same for both the objects so, tan∅ = 6/4 = x/28=> x = 28*6/4 = 42m |
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| 50. |
olace the blank with an integer to make it a true statement.R -2 (b) 5x -- © 8= 56 . |
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Answer» a.-9 b.-7 c.7 d. -11 |
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