Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
3) Put the sign to make the statement true. (use the sign +, -i) 10 1 5 .5_ 7 = 20 |
| Answer» | |
| 2. |
may take ν.ngth of the flagstaff and the distance of the b00869Prove that, sing-cos0-11using the idens. In fig, two circular flower br0-tan。, using the identify sect.-1+ tanao30 38. In figside 56m. If the |
| Answer» | |
| 3. |
one thiard of anumbers when deczeaincreased Find the numbeas. |
|
Answer» answer is 75 then question might be incomplete The question should be"one fifth of the number increased by 8" no the question is one-third of number when decreased by 2 equals one-fifth of the number increase find the number |
|
| 4. |
(1)When the sun is at an elevation of 40°, the length of the shadow ofatree is 18 metres. What is the height of the tree? |
|
Answer» do it on your own |
|
| 5. |
15. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same timea tower casts a shadow 28 m long. Find the height of the tower. |
| Answer» | |
| 6. |
Find the angle of elevation of the sun when the shadow of a pole3 h metres long.s.h metres high i |
| Answer» | |
| 7. |
If y = log vtan x, then find the value of dy/dx at x = 14.X = "74. |
|
Answer» y=log√tanxdy/dx=(1/√tanx)×(1/2√tanx)×(sec^2x)dy/dx=sec^2x/2tanxdy/dx=1/2[1/coax sinx]dy/dx=1/2[1/cos(π/4)sun(π/4)]dy/dx=(1/2)×(2)dy/dx=1 |
|
| 8. |
17. Find the fraction which becomes to when the numerator is increased by 2 and equal to when the denominator is increased by4. Ans â |
| Answer» | |
| 9. |
ला 0 Dy, P, Dy, By 5८: फैल [Ng —» Find 4ho pootobilily Wex B, Lol— & numboy QWC\\UW% o0 Vns ok Oy, bfi-&&g—» |
|
Answer» Fix the number on D4. The probability of the event that D1 has a different number then the one on D4 is5/6, and this probability is same for D2 and D3. Therefore the event in which D1 D2 D3 has a different number than the one on D4 has a probability(5/6)³=125/216 Hence the event that we are interested in has a probability1−125/216=91/216 Like my answer if you find it useful! |
|
| 10. |
-11/4 %2B 2/15 %2B 3/8 |
|
Answer» bracket open krke 3no ka lcm nikal ok |
|
| 11. |
EXERCISE 8.1122.e angles of quadrilateral are in the ratio 3+9÷9-13. Find all the angles of thequadrilateralfn narallelogram are equal, then show that it is a rectangle. |
| Answer» | |
| 12. |
(b) When is subtracte lrFill in the blanks to make following statement true:D is the mid-point of BC. |
| Answer» | |
| 13. |
1. A vertical stick 10cm long casts a shadow 8cm long. At the same time, a tower casts a shadow30m long. Determine the height of the tower. 137.5m] |
| Answer» | |
| 14. |
ABCD is quadrilateral E, F, Grespectively. Prove that EFGH is a parallelogram.and H are the midpoints of AB, BC, CD and DA |
|
Answer» GIVEN, quad ABCD E,F,G,H are mid pointsTo Prove, EFGH is a parallelogram. Proof, Join AC and BD,In ∆ADC H is mid point of AD and G is mid point of DC.So by mid point theorem, HG || AC and HG= AC/2.......(1) Similarly, EF ||AC and EF =AC/2........(2) By (1) & (2), HG || EF and HG=AF We know,If in a quad opposite sides are equal and parallel then it is a parallelogram. Hence proved |
|
| 15. |
Exercise9.31. ABC is a right angled triangle in which LA -90° and AB AC. Find 4B and LC. |
|
Answer» AB = AC so opposite angles are also same B = C A + B + C = 180 90 + B + B = 180 2B = 90 B = 45 = C If you find this answer helpful then like it. |
|
| 16. |
A tree casts a shadow 18 metres long at a time when a pole of 8 metres casts a shadoN6 meters. What is the height of the tree ?9. |
| Answer» | |
| 17. |
rertical pole of length 6 m casts a shadow 4 m long on the gTOat the same time a tower casts a shadowht of the tower.28 m long. Find th |
| Answer» | |
| 18. |
EXAMPLE 5If y =log cos z Find dy |
| Answer» | |
| 19. |
dydxIf y = sin/costhen find |
| Answer» | |
| 20. |
3*(5*z - 7) - 2*(9*z - 11)=4*(8*z - 13) - 17 |
|
Answer» 2 is the right answer please mark me the best answer |
|
| 21. |
L one -thiard of anumbes whendecznymberincreased Find the numbers |
|
Answer» but answer is 75 |
|
| 22. |
itu can row downstrcam 20 km in 2 hours, and upstream Akm in 2 honsrs.peed of rowing in still water and the speed of the current.atibhs, and hence tina theit solulions.hours.Fnd her㣠|
|
Answer» Let speed of stream be y km/hand speed of boat be x km/hso speed of boat in downstream bex+ykm/hand speed of boat in upstream be x-y km/haccording to question,20/x+y=2=x+y=10......(1)and4/x-y=2x-y=2.....(2)(1)+(2)=x+y+x-y=10+2=2x=12=x=6km/h......(3)now putting value of (3)in (1)6+y=10y=4km/h |
|
| 23. |
sum of probability of all events of a trail is (a) less than 1(b) greater than 1(c) lines between 0 and 1 (d)1 |
|
Answer» lies between 0 and 1 because 0 means a impossible event and 1 means sure event |
|
| 24. |
F9. 11.307. ABCD is a rectangle (Fig. 11.31) in whichDDP and BQ are perpendiculars from D and Brespectively on diagonal AC. Show that-(i) AADP ACBQ-(i) ZADP CBQ(i) DP-BQA.Fig. 11.31 |
|
Answer» (i)In triangle ADP and CBQ,AD = BC (opposite sides of a rectangle are equal)angle DPA = angle BQC(both are right angles)angle DAP = angle BCQ (since AD || BC)Therefore the two triangles are congruent by AAS criterion.(ii) Thus, angle ADP = angle CBQ (by congruent triangles property)(iii) DP = BQ (by congruent triangles property) |
|
| 25. |
2. ABCD is quadrilateral E, F, G and H are the midpoints of AB, BC, CD and DArespectively. Prove that EFGH is a parallelogram |
|
Answer» Given, quadrilateral ABCD E,F,G,H are mid pointsTo Prove, EFGH is a parallelogram. Proof, Join AC and BD, In ∆ADC H is mid point of AD and G is mid point of DC. So by mid point theorem, HG || AC and HG= AC/2.......(1) Similarly, EF ||AC and EF =AC/2........(2) By (1) & (2), HG || EF and HG=AF We know,If in a quadrilateral opposite sides are equal and parallel then it is a parallelogram. Hence proved. |
|
| 26. |
18. ABCD is a rhombus. P, Q, R and S are mid-points of AB, BC, CD and DA respectivelyProve that PQRS is a rectangle. |
| Answer» | |
| 27. |
(a)Distance = 90 km, time = 2 hours |
|
Answer» speed = distance/ time = 90 / 2 = 45 km/hr |
|
| 28. |
the given figure of square ABCD, P9. R and S are the midpoints of AB,BC. CD and DA respectively. Find thearea of unruled portion.914 cm |
| Answer» | |
| 29. |
ABCD is a rectangle and P Q. R and S are mid-points of the sides AB, BC, CD and DArespectively. Show that the quadrilateral PORS is a rhombus. |
| Answer» | |
| 30. |
(z+5)(z-5) |
|
Answer» the answer is:Z²-25 (z+5)(z-5)=z²-25²=z-25 z²_25=0z=√25z²=5×5z=5 by the formula of(a+b)(a-b)a²-b²iis isZ²-5² on solving these questions we. get z²-25² |
|
| 31. |
z ( 5 z ^ { 2 } - 80 ) \text { by } 5 z ( z + 4 ) |
| Answer» | |
| 32. |
(1) Select the correct answer from the givenalternative.D) The common ratio for the G.P. 0.12,0.24,0.48- uptoA) 0.12B) 0.2C) 0.02D) 2. |
|
Answer» 2 is the right answer....0.24./0.12=0.48/0.24=2 0.24/0.12=0.48/0.24=2 0.24/0.12=0.48/0.24=2 d 2 is correct anwer of your question. 0.12 is the right answer ushsbsjmansbdbvdbbdns 0.02 is the correct answer 2is the best answer for ur questions 2 answer is right... |
|
| 33. |
) Select and write the most appropriate alternative from those provided in the bracket.) The differense between the highest and the lowest observation in the given data is called. (average, median, medc- range) |
|
Answer» Difference between highest and lowest observation is called as Range. |
|
| 34. |
5 5 °,£/,z 5 5 o_-’,.<{(/,z'0(,J ,{%& /?éé |
|
Answer» Tan35°×Tan55°=Sina......(1)now Tan55°=Tan(90°-35°)=Cot35°And Cot35°=1/tan35°From (1)tan35×tan55=Sina put the value of tan 55tan35×1/tan35=SinaThis shows that 1 = Sinahence Sina =sin 90hence a =90° tan (35°) tan(55°) tan (35°) tan(90 - 35°) tan(35°) cot (35°) tan(35°) × 1/(tan(35°)) 1 So, sin a = 1a = 90° option (c) is correct |
|
| 35. |
\left. \begin{array} { l } { 6 x + y - 3 z = 5 } \\ { x + 3 y - 2 z = 5 } \\ { 2 x + y + 4 z = 8 } \end{array} \right. |
| Answer» | |
| 36. |
ABCD is a rectangle and P. Q, R and S are mid-points of the sides AB, BC, CD and DArespectively. Show that the quadrilateral PQRS is a rhombus. |
| Answer» | |
| 37. |
426+2222-826×923÷567 |
|
Answer» The answer of the above is 1303.38 |
|
| 38. |
Select the correct option from the givenalternativeis equal toA) 2465B) 264"C) 224"D) 426 |
|
Answer» 426vbzbnjdk BBC CNN m if c (22 ×90/15)=1980/15 = 132 |
|
| 39. |
(०) [26 37H1314-23| |
|
Answer» (26/9 * 3/7) - (13/14 * - 2/3) = 26/21 - (-13/21) = (26 + 13)/21 = 39/21 = 13/7 correct answer is 13/7 |
|
| 40. |
0.Asahumanitarianeffort,food ration is distributed to refugee in refugee camp. If a day's ration is 284packets of biscuits, 426 packets of sandwiches and 710 bottles of water, how many refugees are therein the camp. |
|
Answer» The number of refugees will be the HCF of 284, 426 and 710.284=142×2426=142×3710=142×5 ∴Number of refugees will be 142. |
|
| 41. |
9^(3/2)/((343^((-2)/3)*(i*i))) |
| Answer» | |
| 42. |
EXERCISE 8a = 2 and b = 3, find the value of2+ ab(iv) 2a -3b(v) 5a2- 2abif x 1, y 2 and z 5, find the value of2 |
|
Answer» a+b=2+3=5a^2+ab=4+6=102a-3b=4-9=-55a^2-2ab=20-12=8 |
|
| 43. |
parallelogram.TI.ABCD is a square E. F. G. H are points an AB. BC, CD and DA respectively, sach thatAE-BF-CG-DH. Prove that EFGH is a square. |
| Answer» | |
| 44. |
5. ABCD is a square. E, F, G and H are points on AB, BC, CD and DArespectively, such that AE BF CG-DH. Prove that EFGH is a square |
| Answer» | |
| 45. |
re, AC | BD and AE | BF. Find the values of x, y and z.115°85- |
| Answer» | |
| 46. |
If 15 oranges cost ? 110, what do 39 oranges cost? |
|
Answer» Cost of 15 oranges=₹110Cost of 1 oranges =₹110÷15=7.33so find the cost of 39 oranges =39×7.33=₹286 so thright answer is=₹ 286 |
|
| 47. |
If15 oranges cost 110, what do 39 oranges cost? |
|
Answer» 15 oranges cost ₹110so cost of one orange ₹110/15 cost of 39 oranges is ₹110/15 × 39 = ₹286 |
|
| 48. |
26-46 40-6o 60-80 80-106 100-120 120-142 13 343 |
|
Answer» please post complete question |
|
| 49. |
rite in columns and sua) 758 -426e) 6842 -4512 |
|
Answer» 1. 758 426=3322. 6842 4512= 2330 |
|
| 50. |
E)1. () a'b- ab +3a-3bz) mx -24. a +2- 3a + |
| Answer» | |