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If y = log vtan x, then find the value of dy/dx at x = 14.X = "74. |
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Answer» y=log√tanxdy/dx=(1/√tanx)×(1/2√tanx)×(sec^2x)dy/dx=sec^2x/2tanxdy/dx=1/2[1/coax sinx]dy/dx=1/2[1/cos(π/4)sun(π/4)]dy/dx=(1/2)×(2)dy/dx=1 |
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