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ला 0 Dy, P, Dy, By 5८: फैल [Ng —» Find 4ho pootobilily Wex B, Lol— & numboy QWC\\UW% o0 Vns ok Oy, bfi-&&g—» |
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Answer» Fix the number on D4. The probability of the event that D1 has a different number then the one on D4 is5/6, and this probability is same for D2 and D3. Therefore the event in which D1 D2 D3 has a different number than the one on D4 has a probability(5/6)³=125/216 Hence the event that we are interested in has a probability1−125/216=91/216 Like my answer if you find it useful! |
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