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-4 respectively Find gexlground and at tbe sasR4. A vertical stick of length 6 m casts a shadow 4 m long, on thetower casts a shadow 28 m long Find the height of the towerncn interect each oher at O such that AS |
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Answer» AB is the pole and BC is the shadow of pole. Given, AB = 5 m and BC = 2 m. PQ is the tower and QR is the shadow of tower. Given, QR = 9 m Let the height of tower behm. Since the length of shadow of pole and tower area measured at the same times, so the angle of elevation of source of light for both is same at that moment of time. ∴ ∠C = ∠R In ΔABC and ΔPQR, ∠B = ∠Q (90°) ∠C = ∠R ∴ ΔABC= ΔPQR (AA similarity) ab/pq = bc/qr 5/h = 2/9 h = 45/2 = 22.5 Thus, the height of tower is 22.5 m. Like my answer if you find it useful! |
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