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9×1 = 9 integers which end in exactly one 0(2 digit numbers)

990.without hundred s

990.without hundred s

the correct answer is 990

990 because it is less than zero

990 is the right answer

990 because it has one zero and it is less than 1000

990. is the answer. understood

0 is right ans bcz it's less than 1000 and its non negative numbers both two conditions are satisfy ANS = 0 THANKS ALL

why an issue it's right ans jiskoo challenge krnaa h vo Kroo 0 hi right ans h call me I explaine 9713193107 ya what's app

ok see in next time zero

990is the answer of your questions

10,20,30,40,50,60,70,80,90,110,120,130,140,.....................920,930,940,950,960,970,980,990.

90 integers

non negative integers should be zero

990. without hundred

990 is my answer because it is less than 1000 with only one zero

990,because it is less than 1000 and with only one zero.

0 itself is a non negative integer

9×1=9 integers which end in exactly one 0( Two digit no)

9×9×1 =81 integer's which ends in exactly one 0(Three digit number)

Thus, 91 are there which satisfy this condition,

hope it helps.

Numbers with single trailing zero = 90Numbers with zero in the middle = 81Zero is to be considered as it is non-negativeTotal = 90 + 81 + 1 = 172Thus, the number of non-negative integers which are less than 1000 and with only one zero is 172.

990 Is right answer for this.

Answer will be 990 as it less than 1000 and have one 0as well

10 is the correct answer

The answer is infinite

Answer is infinite because there are infinite numbers less than - 1000 are -1110 and so on infinite

10 is the answer of this question.

1000/0=0 it will be zero

10 is your correct answer

10 is the best answer

10 is the answer for the question

172 is the right answer

non negative integers less than 1000 with only one zero is 172

I also say 172 is correct ans

100,10 and this are the only non -negative integers less than 1000 and consist o

I answer it before sir

10 is the answer.

first note that an integers digits add up to a multiple of thee if and only if the integer itself multiple of three

zero itself is the non negative integers

simply by AP calculate the no. of terms with d=10 a=0 and an=990 then subtract number of germs with 2 zeros like 900,800,700,600,500,400,300,200 and 10091 including zero

172 is the best answer

172 is the answer by using ap and also adding no of terms with 0 in middle

10.

101 to 110......

Option- Aplease like the solution 👍 ✔️

Assume that the given real number is rational. This means that the number can be expressed in the form p/q where p and q belong to integers as well as are co-prime. So, 3 + 2root5 = p/q Or, 2root5 = p/q - 3 = (p -3q)/q Or,Root5 = (p-3q)/2q ....... (i)

Now, (p-3q)/2q is a rational.

So, irrational number ≠ rational number. This means root5 is rational.

But, root5 is an irrational.

How??

Assume root5 as rational. So, Root5 = a/b Where a and b are integers and co-primes. So, Squaring both sides:-5 = p²/q²So, p² =5q² ...... (ii) So, p² has 5 as a factor. So, p also has 5 as its factor for some integer c.

Now,p =5c Or, p² =25c² Putting it in (ii)

5q² =25c² Or, q² = 5c²

So, q² is a multiple of 5 So, q is also a multiple of 5.

Now, Both p and q have a common factor 5 This means they are not co-primes but it is given that they are co-primes.

Hence, it's a contradiction which has risen because of taking root5 as rational.

So, root5 is irrational.

Now,

Back to the question. From (i) :-

Root5 = (p-3q)/2q

So, This is not possible as root5 is irrational and RHS of the equation is rational.

As irrational ≠ rational.

Hence, it is a contradiction.

This has risen because of taking the given number (3 + 2root5) as rational number.

This implies that 3 + 2root5 is an irrational number.

a)-2p+2q will be simplified form

Sin 30° = √1-cos60/2= √1-1/2/(2)√1/4= 1/2

p(x)=2x+1,; x=-1/2; p(-1/2)=2(-1/2)+1=0; p( x)=5x-x ; x=(-3/2); p(-3/2)=5(-3/2)-(3/2)=-15/2-3/2=-18/2=-9,; (iii)p(x)= x^2-1; x=+-1; p(+-1)= x^2-1=(+-1)^2-1=1-1=0; 1-1=0; (iii) p(x)=( x-1)( x+2);; x=-1, -2; p(-1)=( -1-1)(-1+2)=(-2)(1)=-2, p(-2)=(-2-1)(-2+2)=(-3)(0)=0; p(x)=y^2; y=0; p(0=(0)^2=0; (v)

(vi)p(x)=ax+b; x=-b/a; p(-b/a)=a(-b/a)+b=-b+b=0; f(x)=3x^2-1; x=-1/V3, 2/V3, ; f(-1/V3)=3(-1/V3)^2-1=3(-1/3)-1=-2, f(2/V3)=3(2/V3)^2-1=3(4/3)-1=4-1=3

thanks

X=62°,Y=54°x+y+z=180°62°+54°+z=180°116°+z=180°z=180°-116°z=64°then,bisectors of angle xyz andangleXZO.So, half of angle y and zxyo=oyz=27°and xzo=ozy=32°oyz+ozy+yoz=180°27°+32°+yoz=180°yoz=180°-59°yoz=121°

x=3+2√2

1/x=1/(3+2√2)

rationalising the denominator we get,

1/x=3-2√2/(9-8) [here (a+b)(a-b)=a2-b2; a= 3+2√2; b=3-2√2]

x+(1/x)=(3+2√2)+(3-2√2)

=6

6 can be written as 6/1

Thus 6 is a rational number

it is rational number

area of square -area of four semicircle

measure of the angles is (1,5)

First of all, find value of x % of y

so, x % of y = x/100 × y = xy/100

hence, x% of y = xy/100

again find y % of x

so, y % of x = y/100 × x = yx/100

hence, y% of x = xy/100

now, ratio of x % of y to y % of x = x% of y/y% of x= (xy/100)/(xy/100)= 1

Like my answer if you find it useful!

option b is the correct answer of the given question

option a is the answer for this question

option b is the right answer.

b is the correct ans

a is the answer of the following sum

Is it an incomplete answer?

the above answer is wrong......

plzzz don't write it......

Proof- In triABC AB = AC angACB=angABC(by opposite side eql to opposite ang)-(1) and, 1/2 AB = 1/2 AC BD = CE (eqn 1)

Nosolution

is x = -7y = 3.5

4)sides of squares are equal.PQ=3x-7QR=x+3QR=PQthen 3x-7=x+3then 2x=10; x=5PQ=3(5)-7=8..then QS=8

di sorry samaj nahi aaya

square ka side equal hota h na...to PQ will be equal to QR...isse x ki value nikl jaayegi..

m⁴ - 256

(m²)² - (16)²

(m² - 16) ( m² + 16)

(m - 4) ( m+4) ( m² + 16)

multiple of 3=3,6,9,12,15,18 total 6multiple of 5=5,10,15,20 total 4multiple of 15=15 total 1so probability of 3 or 5=(6+4-1)/20=9/20

Like my answer if you find it useful!

64 is the right answer

64 is the right answer to this question.

now....256+(3/42)(256*42+3)/42(10752+3)/4210755/42correct

If one pen cost =5 rupeesthen 10 will cost 5*10= 50 rupees

℃ to kelvin= K=C+273.15= -40+273.15=233.15K℃to fahrenheit= F=C×1.8+32=-40×1.8+32=-40°F

1st jump = 3/5 m: 2nd jump = 3/4 m; 3rd jump = 7/10; total = 3/5 + 3/4 + 7/10 = 3(4) + 3(5) + 7(2)/20 = =12+ 15 + 14/20=27+14/20 = 41/20

41/20 is the correct answer of the given question