\left(\frac{b^{3} c^{-2}}{b^{-4} c^{3}}\right)^{-3} \div\left(\frac{b^ – InterviewSolution

1.	\left(\frac{b^{3} c^{-2}}{b^{-4} c^{3}}\right)^{-3} \div\left(\frac{b^{-1} c}{b^{2} c^{-2}}\right)^{5}=b^{x} c^{y},
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