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17. In Fig 3, ΖΧ-62"..ΟΖ #34". If yo tind zo are the bisectorsofXYZ andzzi, respectively of Δ XYZ,Fig 3 Yy Questions 18 to 20 carry 4 marks each : |
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Answer» X=62°,Y=54°x+y+z=180°62°+54°+z=180°116°+z=180°z=180°-116°z=64°then,bisectors of angle xyz andangleXZO.So, half of angle y and zxyo=oyz=27°and xzo=ozy=32°oyz+ozy+yoz=180°27°+32°+yoz=180°yoz=180°-59°yoz=121° |
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