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Area of four walls = 2h(l+b)= 2*35*(40+30)= 70*70= 4900 m²Cost of whitewashing = 4900*2.5= ₹ 12250

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answer

the product of two rational numbers is -12 .if one of the numbers is _8 find the other.

Given thatXY= -12now if -8x= -12x= 12/8= 3/2

-4/3 is rhe other number

1st method

Let, the number=x

Then, the spectors=2/7x

Therefore,

X-2/7x=15000

7x-2x/7=15000

5x=15000*7

X=15000*7/5

X=2100

2nd method

Let, the number=x

Then, the spectors=2/7x

2/7x+15000=x

2/7x - x= -15000

2x-7x/7= - 15000

-5x/7= -15000

-5x= -15000*7

X= - 15000*7/-5

X=2100

I hope you understood. Don't copy plz stood then you solve

Thanks

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Let the cost price of one article is Rs. 100Then cost price of 11 article is Rs. 100 X 11 = Rs. 1100

According to questionSelling price of 10 article = Cost price of 11 article(Rs 1100)Selling price of 1 article = Rs. 1100/10 = Rs 110

Gain % = 110 -100 = 10%

Let x = selling price of 10 articles = cost of 11 articlesgain percent = (selling price / cost per item -1)* 100%

x/10 = selling price of each articlex/11 = cost per article

gain percent = ((x/10)/(x/11)-1)*100% = ((11/10)-1)*100% = 10%

Let number be x x-(16/100)*x=378,x - 4x/25 = 378,25x - 4x/25 = 378,21 x /25 = 378, x =378 *25/21 =450

C ) 84 is the answer

1. Acurvethat represents thecumulative frequency distributionof grouped data on agraphis called aCumulative Frequency Curveor anOgive.

2. Whentwo coins are tossed simultaneouslythen the possible outcomes obtained are {HH, HT, TH, and TT}. Here H denotes head and T denotestail.=3/4

(-1/6)³ the correct answer of the given question

Area of path = (8.5*6)-[ (8.5-2(2))* (6-2(2))]= 51 - (4.5*2)= 51-9= 42 m²Cost = Rate*Area of path= 25*42= ₹ 1050

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Option -a

L=20 mb= 15mh= 4 m

First we find the area of floor=>20x15=>300 m²Then, we find area of walls=>2(20x4) + 2(15x4)=>2(80 + 60)=>280 m²

Add both to get total area=>300+280= 580 m²

Multiply total area and cost per m²=>580x 12=>Rs. 6960

For 20% profit on selling price means 1/5 of 1500 i.e. Rs. 600Now, let the CP = Rs. 100, Then,SP with 20% profit = Rs. 120For 20% profit on selling price means cost is 100+ profit is 20 = selling price is 120.Means selling price is 120% of cost price.Now selling price is 120% ie 3000 then find 100% amount which will be cost.Cost = 1500/120%= 1500/(6/5)Because, 120% = 6/5= 1500 x 5/6= 2500Cost is 2500Thus profit is 20% i.e. 1/5 x 2500 = 500Thus,Difference is 600-500 = Rs.100.

20% profit on sp = 1500 of 20/100= 300₹cp. sp100. 120x. 1500120x= 1500×100x= 1500×100/120= 1250cp = 1250sp = 1500profit= 1500-1250= 250₹ in case of sp profit = 300₹in case of cp profit = ₹ 250in case of sp ₹ 50( 300-250)get more.

Education policy consists of the principles and government policies in the educational sphere as well as the collection of laws and rules that govern the operation of education systems. The National Policy on Education(NPE) is a policy formulated by theGovernment of India to promote education amongst India's people. The policy covers elementary education to colleges in both rural and urban India. The first NPE was promulgated in 1968 by the government ofPrime Minister Indira Gandhi, and the second by Prime Minister Rajiv Gandhi in 1986.

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We know∠BCD = 43°and∠BAE = 62°

And In∆AEC we get from angle sum property of triangle∠CAE +∠CEA +∠ACE = 180°Here∠BCD =∠ACE = 43°( Same angles )And∠BAE =∠CAE = 62° ( Same angles )And given∠CEA = d , Now we substitute values , we get

62°+ d + 43° = 180°SO,d = 75° ( Ans )

Quadrilateral AEDB is a cyclic quadrilateral , And we know in cyclic quadrilateral opposite angles are supplementary , So

∠AED +∠DBA = 180°, From diagram we substitute values , we get

d + a = 180°So,75° + a = 180° ( As we calculate d = 75°)

a = 105° ( Ans )AndAnd In∆BAF we get from angle sum property of triangle∠BAF +∠AFB +∠FBA = 180°Here∠BAE =∠BAF = 62°( Same angles )And∠FBA = a = 105° ( as we calculate )And given∠AFB = b , Now we substitute values , we get

62°+ b + 105° = 180°SO,b = 13° ( Ans )

And∠DEA and∠DEF are supplementary , as they are linear pair angles , So

∠DEA +∠DEF = 180° , Here∠DEA = d = 75° , So

75° +∠DEF = 180°

∠DEF = 105°In∆DEF we get from angle sum property of triangle∠DEF +∠EFD +∠FDE = 180°Here∠EFD = b = 13°( as we calculate )And∠DEF = 105° ( as we calculate )And given∠FDE = c , Now we substitute values , we get

105°+ 13°+ c = 180°SO,c = 62°

Given : scale of map = 1 : 10000001 cm represents to 1000000 cm on the ground.Therefore, 1 cm× 1 cm = 1 cm² (on the map)And, 1000000 cm× 1000000 cm = 1000000000000 cm² (on the ground)1 km = 100000 cm× 100000 cm = 10000000000So, the area on the ground = 1000000000000/10000000000= 100 sq kmAs the area of the forest on the map is 4.6 cm².So, the actual area of the forest = 100× 4.6= 460 sq m

the answer is not know because this is not in my chapter sorry

2.4/(2.4 + 3.6) = 2/x2.4/6 = 2/x0.4 = 2/xx = 5 cm

(2.4+3.6)/2.4=x/26/2.4=x/26/1.2=xX=5This is 100% correct answer

C get 275 of the work

200

Cdoes 4/11 part of worktotal payment=550,therefore 4/11 part of work =4/11 *550=200

5 tractors can miw a field in 10 days

One tractor mow the field in10*5 = 50 days

Then, 3 tractors can mow the field in50/3 = 16.6 days.

Total surface area of cylinder = 2πr(r+h)Here radius = 24/2 = 12 cm = 0.12mNow 2 * 3.14 * 0.12(0.12 + 3.5) = 2.72m^2

Length of parallel sides of a parallelogram are equal.

So, the sum of length of parallel sides= 2(x+4)

Altitude to the base= (x-3)

Area of parallelogram= 1/2*(sum of parallel sides)*(altitude between parallel sides)

Area of parallelogram= 1/2*2(x+4)*(x-3)

x^2-4= x^2-3x+4x-12

x^2 cancel out each other

-4= x-12

x= 12-4

x=8

So, area of parallelogram= x^2-4= 8^2-4= 60

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a=3b=5c=7 (1,2,4)

a). 3b). 5c). 0,1,2,4

a.= 1b. =3c. =11(6+4+1)

a.) 1b.) 5c.) 11 cuz 6+4+1=11

The answers are as follow:A)1B)3C)11

we have tan A – tanB = sin (A – B) / cosA cosB & cot B – cot A = sin (A – B)/ sinA sin B

1/x + 1/y = cosA cosB /sin(A – B) + sinA sinB / sin (A – B)

=(cosA cosB + sinA sinB) /sin (A – B)

= cos (A – B) / sin (A – B) = cot (A – B)

Ans: cot (A – B) = 1/x + 1/y

30°, 90°,60° is the correct answer of the given question

Both angles are on180 line we take both angle as a+a2=180

1 dozen has 12 fanshence 9 dozen has 12*9=108 fanshence total amount =1165.65*108=125,890.2 rupees

total ice cubes in a box = (4×4×4)/(2×2×2) = 2×2×2 = 8

15CP=20SPCP=20/15*SP=4/3*SP so SP=3/4CPso loss=(CP-SP)/CP=(CP-3/4*P)/CP=1/4*100=25%

L=20 mb= 15mh= 4 m

First we find the area of floor=>20x15=>300 m²Then, we find area of walls=>2(20x4) + 2(15x4)=>2(80 + 60)=>280 m²

Add both to get total area=>300+280= 580 m²

Multiply total area and cost per m²=>580x 12=>Rs. 6960