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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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15. Find three numbers a,b,c between 2 and 18 such that (i) their sum is 25 (i) the num2,a,b are consecutive terms of an A.P. (iilithe numbers b, c, 18 are consecutive terms of |
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Answer» 2 < a, b, c, < 18 a + b + c = 25 ……. (1) 2, a, b are AP ⇒ 2a = b + 2 ⇒ 2a – b = 2 …….. (2) b, c, 18 are in GP ⇒ c2= 18b …… (3) From (2) ⇒ a = b +2/2 (1) ⇒ b + 2/2 + b + c = 25 ⇒ 3b = 48 – 2c (3) ⇒ c2= 6 (48 – 2c) ⇒ c2+ 12c – 288 = 0 ⇒ c = 12, - 24 (rejected) ⇒ a = 5, b = 8, c = 12 |
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| 2. |
5 Find the value of k so that (8k+4), (6k-2) and (2k+7) form three consecutive terms cf arAR |
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Answer» hit like if you find it useful |
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| 3. |
58° o sin 22° cos 38° cosec 52°32° .cos68° \/_3 (tan 18° tan 35° tan 60° tan 72° tan |
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Answer» Question is incomplete please post the full question Assuming that you meancos 58/sin 32 + sin 22/cos 68- (cos 38 csc 52)/(tan 18*tan 35*tan 60*tan 72*tan 55) Use the cofunction identities (in degrees):sin(90 - t) = cos t, cos(90 - t) = sin t, and tan(90 - t) = cot t. This simplifies the expression in question tosin(90 - 58)/sin 32 + cos(90 - 22)/cos 68- (cos 38 csc 52)/(tan 18*tan 35*tan 60*cot(90-72)*cot(90-55)) = 1 + 1 - (cos 38 csc 52)/(tan 18*tan 35*tan 60*cot 18*cot 35) Now, use csc t = 1/sin t and cot t = 1/tan t:2 - (cos 38/sin 52)/(tan 18*tan 35*tan 60*(1/tan 18)*(1/tan 35))= 2 - (cos 38/sin 52)/tan 60= 2 - (cos 38/cos(90-52))/tan 60, via cofunction identity= 2 - 1/tan 60= 2 - 1/√3. Like my answer if you find it useful! |
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| 4. |
If k, 2k -1 and 2k + 1 are three consecutive terms of an A.P, tvalue of k is(A) 2(B) 3(C)3(D) 5 |
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| 5. |
how many consecutive terms starting fromthe first term of the series 3+9+27+...... would sum to 1092 ? |
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Answer» BY using A.P theorem an=a+(n-1)d by using A. P. theorem an =a+(n-1)d a^n=a+(n-1)d , A.P., theorem |
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| 6. |
Is PISUIn the given figure what is(a) AE + EC?(b) AC-EC?(c) 'BD - BE?(d) BD-DE?thore in the given figu |
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Answer» The answers are as follows :-(a) AC(b) AE(c) ED(d) BE AC AE ED BE is the correct answer of the given question correct answer is AC ,AE, ED, BE |
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| 7. |
9. Find a, so that 2x+1,a2+ x+1 and 3x2-3x 3 are consecutive terms of an A.P |
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Answer» Given, 2x+1, x^2 +x+1 and 3x^2 - 3x+ 3 are the consecutive terms of an A.P.As the terms are in ap, therefore common difference between the given consecutive terms will be equal.So,(x + x + 1) - (2x + 1) = (3x - 3x+ 3) - (x + x + 1)⇒ 2(x + x + 1) = (3x - 3x+ 3) + (2x + 1)⇒ 2x + 2x + 2 = 3x - x + 4⇒ 0 = x - 3x + 2⇒ x - 3x + 2 = 0⇒ x - 2x - x + 2 = 0⇒ x(x - 2) -1(x - 2) = 0⇒ (x - 2)(x -1) = 0⇒ x = 2 or x = 1 Like my answer if you find it useful! |
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| 8. |
in triangle ABC DE||BC AD=5.7cm BD=9.5cmEC=6cmfind AE |
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Answer» From the question.. using similar triangle properties AD/BD = AE/EC => 5.7/9.5 = AE/6=> 3/5 = AE/6=> AE = 3*6/5 = 18/5 = 3.6cm thanks 😀 |
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| 9. |
Nazima is fly fishing in a stream. The tip ofher fishing rod is 1.8 m above the surfaceof the water and the fly at the end of thestring rests on the water 3.6 m away and2.4 m from a point directly under the tip ofthe rod. Assuming that her string(from the tip of her rod to the fly) is taut,how much string does she have out(see Fig. 6.64)? If she pulls in the string atthe rate of 5 cm per second, what will bethe horizontal distance of the fly from herafter 12 seconds?10.1.8 m2.4 m1.2 mFig. 6.64 |
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| 10. |
17.-Noob agitIn a certain code KAMAL is written as 29894. VIJAY is written as 35196, then the word VIMAL Willcoded as(A) 29196(B)35894(C)35194(D) 35196Work.(A)8If mena |
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Answer» 35894is a write answer. the answer will be 35894 35894 is your correct answer V=3I=5M=8A=9 L=4 so,35894 this is the code of vimal |
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| 11. |
25. In Figure, DEFG is a square and 4BAC 90° Show that DEBD x EC. |
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Answer» Solution:-Given ; ABC is a triangle in which∠ BAC = 90° and DEFG is a square.Proof in : (1)InΔ AGF andΔ DBG,∠ AGF =∠ GBD (Corresponding angles)∠ GAF =∠ BDG = 90° eachSo,Δ AGF ~Δ DBG (ProvedBy AA similarity)(2)InΔ AGF andΔ EFC,∠ AFG =∠ FCE (Corresponding angles)∠ GAF =∠ CEF = 90° eachSo,Δ AGF ~Δ EFC (Proved by AA similarity)(3) InΔ DBG andΔ EFC,∠ DBG =∠ ECF = (Corresponding angles)∠ BDG =∠ CEF = 90° eachSo,Δ DBG ~Δ EFC (Proved by AA similarity)(4) InΔ AGF andΔ DBG,∠ AGF =∠ GBD (Corresponding angles)∠ GAF =∠ BDG = 90° each∴Δ AGF ~ΔDBG .....(1)Similarly,Δ AFG ~Δ ECF (AA similarity) ....(2)From (1) and (2), we getΔ DBG ~Δ ECF⇒BD/EF = BG/FC = DG/ECBD/EF = DG/ECEF× DG = BD× EC ....(3)Also DEFG is a square⇒ DE = EF = FG = DG ....(4)From (3)and(4), we getDE² = BD× ECHence proved. |
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| 12. |
Fig. 6.63Nazima is fly fishing in a stream. The tip ofr fishing rod is 1.8 m above the surfaceof the water and the fly at the end of thestring rests on the water 3.6 m away and2.4 m from a point directly under the tip ofthe rod. Assuming that her string(from the tip of her rod to the fly) is taut,how much string does she have out(see Fig. 6.64)? If she pulls in the string atthe rate of 5 cm per second, what will bethe horizontal distance of the fly from her10.he1.8 m2.4 m1.2mFig. 6.64after 12 seconds? |
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Answer» thanks |
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| 13. |
In Fig. 5, DEFG is a square and <BAC90°. Show that DE-BDEC.Fig. 5 |
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Answer» Given: DEFG is a square and ∠BAC = 90°.To Prove: DE² = BD × EC.Proof : In ∆ AFG & ∆DBG ∠GAF = ∠BDG [ 90°]∠AGF = ∠DBG [corresponding angles because GF|| BC and AB is the transversal]∆AFG ~ ∆DBG [by AA Similarity Criterion] …………(1) In ∆ AGF & ∆EFC∠AFG = ∠CEF [ 90°]∠AFG = ∠ECF [corresponding angles because GF|| BC and AC is the transversal]∆AGF ~ ∆EFC [by AA Similarity Criterion] …………(2) From equation 1 and 2. ∆DBG ~ ∆EFCBD/EF = DG /ECBD/DE = DE /EC [ DEFG is a square] DE² = BD × EC Like my answer if you find it useful! |
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| 14. |
1. For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P? |
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P2.For what value ofk will theFind the 9th term from the end (towards the fst terml of the A.P. 5,9,13.. . 185 (1531ltvide of k WIllK+9,2k -1 and 2k + 7 are the consecutive terms of an AP (k-18)consecutive terms 2k + 1, 3k + 3 and 5k-1 form an A.Prk-6)3. |
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Answer» a2k + 1 = a3k + 3 = b5k - 1 = c To form an AP,a + c = 2b2k + 1 + 5k - 1 = 2( 3k + 3)7k = 6k + 6k = 6 So, k = 6 |
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| 16. |
300×123+12345 |
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Answer» 300×123+12345 =36900+12345 =49245 |
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| 17. |
13.Find the area of a parallelogram in a polynomial expression from the given figaAB = (x+3), DE =(x-4)-(x+3) |
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Answer» area of parallelogram = b×h = AB×DE = (x+3)(x-4) = (x^2-x-12 ) sq unit base of parallelogram,AB=x+3height of parallelogram,DE=x-4therefore area of parallelogram=ABxDE=(x+3)(x-4)=x²-4x+3x-12=x²-x-12 |
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| 18. |
TRIANGLESI. In AABC, DE | BC, find the value of x.x+ 3X+ 1X+5 |
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Answer» DE || BC x/(x+x+1) = (x+3)/(x+3+x+5) x/(2x+1) = (x+3)/(2x+8) 2x*x + 8x = 2x*x + 7x + 3 x = 3 |
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| 19. |
In Fig. 5, DEFG is a square and <BAC90°. Show that DE-BD × EC. |
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| 20. |
In AABC, DE//BC, then find x if AD=X, AE=X+3, EC=X+5 and BD=x+1. |
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| 21. |
(i) (101)2 |
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Answer» thank you very much |
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| 22. |
100+101+108 |
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Answer» 100 + 101 + 108= 309309 is the right answer . on adding 100+101+108 it equals to 309 |
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| 23. |
How many consecutive terms starting fro1 11 + 111 +Would sum to 12345 |
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Answer» 1+11+111+1111+11111=12345 observe that to get 5 in last digit you need five 5, so sum will be 5 digits number can satisfy it. |
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| 24. |
41.संख्या 12345 में 3 के स्थानीय मान तथा ।अंकित मान में अन्तर है।(A)0(B) 295(C) 297(D) 405 |
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| 25. |
The difference of the place value and face value of the number 3in 12345 is |
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Answer» Place value of 3 in 12345= 300 Face value of 3 in 12345= 3. Therefore,Difference of place value and face value of 3 in 12345= 300 - 3 = 297 |
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| 26. |
The difference of the place valueand the face value of the number3 in 12345 is |
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| 27. |
, DEFG is a square and LRAC = 90°. Prove that :in figure(i) MGP-ADBG)ADBG AEFC(ii) AAGF AEFC(iv) DE- BD x EC.G900EC |
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Answer» Given ; ABC is a triangle in which∠ BAC = 90° and DEFG is a square.Proof in : (1)InΔ AGF andΔ DBG,∠ AGF =∠ GBD (Corresponding angles)∠ GAF =∠ BDG = 90° eachSo,Δ AGF ~Δ DBG (ProvedBy AA similarity) (2)InΔ AGF andΔ EFC,∠ AFG =∠ FCE (Corresponding angles)∠ GAF =∠ CEF = 90° eachSo,Δ AGF ~Δ EFC (Proved by AA similarity) (3) InΔ DBG andΔ EFC,∠ DBG =∠ ECF = (Corresponding angles)∠ BDG =∠ CEF = 90° eachSo,Δ DBG ~Δ EFC (Proved by AA similarity) (4) InΔ AGF andΔ DBG,∠ AGF =∠ GBD (Corresponding angles)∠ GAF =∠ BDG = 90° each∴Δ AGF ~ΔDBG .....(1)Similarly,Δ AFG ~Δ ECF (AA similarity) ....(2) From (1) and (2), we getΔ DBG ~Δ ECF⇒BD/EF = BG/FC = DG/ECBD/EF = DG/ECEF× DG = BD× EC ....(3)Also DEFG is a square⇒ DE = EF = FG = DG ....(4) From (3)and(4), we getDE² = BD× ECHence proved. |
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| 28. |
.A nd b o 0ddCo. 20\//j ) | Psoduch , q.a - o¥ b then dum 4> 96822S t = |
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Answer» Product of a and b is a*bit is added to a and b hencea*b+a+b thanks |
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| 29. |
i MWW 250 W%_q( :के$ मा मा . s wadoL {,(J/MJ(:‘ ) “”g,;fj idum ? |
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Answer» a=17l=350d=9l=a+(n-1)d350=17+(n-1)9350-17=(n-1)9333=(n-1)9333/9=(n-1)37=(n-1)n=38sum of terms=s nsn =n/2(a+l) =38/2(17+350) =19(367) =6973like if it is correct |
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| 30. |
I 3170S¿=b+8++61 = 9+9+hgr=9+h+E2 + 3 + 4 = 11HAI DUM |
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Answer» the correct answer is 29. 28 is the correct answer of this question the correct answer is 292+3+4+extra2=113+4+5+extra3=154+5+6+extra4=19then7+8+9+extra5=29 31 is the correct answer 24 is the correct answer 31 is right answer... 31 is the correct answer 2+3+4=9+2=113+4+5=12+3=154+5+6=15+4=197+8+9=24+5=29so we will add the series of 2(2,3,4,5) in every sum . 31 is the correct answer 2+3+4=113+4+5=154+5+6=197+8+9=31 this is the right answer of the followingso, accept me as best. please like my answer 31 is the correct answer |
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| 31. |
Find the area of a parallelogram in a polynomial expression from the given figure.AB=(x +3), DE =(x-4)(a-b) (a+b)E- (213) |
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| 32. |
2. Renuka earns Rs 24,000 per months. She spends14,000. Whatper cent of her income does she save? |
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| 33. |
5*(2*1234) |
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Answer» this question answer is 12340 the answer of following question is 12340 12340 is the answer of the following 12340 is the answer of your question 12340 is correct answer 2×1234×5=12340is solve them 12340 is the correct answer the answer to this question is 12340 =2×1234×5=2468×5=12340 2x1234x5=12340 I am solve them 1230 is the right answer |
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| 34. |
-1234 %2B 101*1234 |
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Answer» 123400 is the correct answer 1234 × 101 - 1234124,634 - 1234 = 123,400 please like and accept as best answer 123400 is the correct answer 123400 is the best answer Your correct answer is 123400 123400 is the right answer 123400 is the correct answer. 123,400 |
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| 35. |
438 58 141234 23-837 |
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| 36. |
–नलिखित संख्याओं के वर्गों के इकाई के अंक क्या होंगे?) 81(ii) 272(iii) 799) 1234 (vi) 26387(vii) 52698| 12796(v) 55555 |
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Answer» i. 1ii. 4iii. 1iv. 6v. 9vi. 4vii. 6viii. 5 |
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| 37. |
What will be the one digit in the square 1234? |
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Answer» 6 will be the answer |
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| 38. |
1234:24 - 4512:2(A) 20(B) 36(C)50(D) 84 |
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Answer» 1234/24=4512/x; ; x=4512×24/1234=32 32 is a correct answer 32 is the currect answers 32 is the correct answer |
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| 39. |
5. °CAl Bua 31 U4 Al नराभर डोप छे ? |
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Answer» nCr = n!/((n-r)!×r!) If you find this answer helpful then like it |
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| 40. |
What is the number from which 1234 mustbe subtracted to get 12345? |
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Answer» hope it helps u |
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| 41. |
Q1. Prove thatcossin A1+tan A-1 +cot A =cos A-sin ABeard Term-1, 2016, Set-MV98HN3] |
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| 42. |
ClassFrequency 150 500 300 50Cumulative 150 650950 10008-10 10-12 12-14 14-16Median = L + L- × h500-150710+35010+1=10+1.4=11.4= |
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| 43. |
dimensionalFormula of EEis :-2-27 de |
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| 44. |
3/ A rectangular courtyard is 18 m 72 cm long and 13 m 20 cm broad. It is to be paved withsquare tiles of the same size. Find the least possible number of such tiles. |
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| 45. |
in a mathematics exam dum of marks of ravan and ramu is 30 and their marks difference is 10. find the marks of ramu |
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Answer» 20 and 10 as. let us suppose marks of Ramu are' x and Ravan ' y '.x+y=30x-y =10 Let marks of Ravan be xThen marks of Ramu = 30 - x As per given conditionx - (30 - x) = 102x - 30 = 102x = 40x = 40/2 = 20 Therefore,Marks of Ravan = 20Marks of Ramu = 10 |
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| 46. |
Rahim's father earns Rs. 5,500 and JaVed's father earns 30% more than Rahim' s fathmuch does Javed's father earn?7, |
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Answer» 30% of 5500=30/100*5500=1650rupees morehence Javed father earns 5500+1650=7150rupees thank |
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| 47. |
33. A rectangular courtyard is 18 m 72 cm long and 13 m 20 cm broad. It is to be paved withsquare tiles of the same size. Find the least possible number of such tiles |
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| 48. |
3/A rectangular courtyard is 18 m 72 cm long and13 m 20 cm broad. It is to be paved withsquare tiles of the same size. Find the least possible number of such tiles.4. Find the HCF of |
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| 49. |
huhewhetherother whichad theyoofThree40 and long have to be divided into plansWhat is the greatest posible length of each platicontanLand of milk respectively. Find the capacitysit the contes inmeasure the milk of all the containers incer whichumber of times6 pers and songs These are to be wronged in heapsFind the seatest number of fruits possible m eactsconcontainTheThere are 27 apps, 64in the same numberbap How many heaps are formedDetermine theSom and 12 m 95 cmich can be used tomeexactly the lengths 7 mall thetheorem and then take the HCPA regular courtyard is 1 m 72long and 13 m 20 em broad. It is to be puvent willes of the same size. Find the least possible number of such tesquare files of thenad the HCP oftwo prime numbers( two co-primescu two consecutive numbersIV) 2 and an even number |
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Answer» 29.ans=HCF of 42,49,63 = 7 1st plank i.e 42/7 = 6 2nd plank i.e 49/7 = 7 3rd plank i.e 63/7 = 9 Planks formed are = 6 + 7 + 9 = 22 sorry sir I don't see your question. |
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| 50. |
(v)Find the sum of odd numbers between 0 and 50. |
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