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9. Find a, so that 2x+1,a2+ x+1 and 3x2-3x 3 are consecutive terms of an A.P |
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Answer» Given, 2x+1, x^2 +x+1 and 3x^2 - 3x+ 3 are the consecutive terms of an A.P.As the terms are in ap, therefore common difference between the given consecutive terms will be equal.So,(x + x + 1) - (2x + 1) = (3x - 3x+ 3) - (x + x + 1)⇒ 2(x + x + 1) = (3x - 3x+ 3) + (2x + 1)⇒ 2x + 2x + 2 = 3x - x + 4⇒ 0 = x - 3x + 2⇒ x - 3x + 2 = 0⇒ x - 2x - x + 2 = 0⇒ x(x - 2) -1(x - 2) = 0⇒ (x - 2)(x -1) = 0⇒ x = 2 or x = 1 Like my answer if you find it useful! |
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