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TRIANGLESI. In AABC, DE | BC, find the value of x.x+ 3X+ 1X+5 |
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Answer» DE || BC x/(x+x+1) = (x+3)/(x+3+x+5) x/(2x+1) = (x+3)/(2x+8) 2x*x + 8x = 2x*x + 7x + 3 x = 3 |
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