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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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43. Find five rational numbers betweenand |
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4Find five rational numbers betweenand |
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BUMPLE &the sectors of a pair of corresponding angles formed by ahasersalt to give lines are parallel, prove that the given |
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| 4. |
The dimensions of a cuboidal box are 6 m x 400 cm x 1.5 m. Find the cost ofpainting its entire outer surface at the rate of 22 per m2. |
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Answer» Step-by-step explanation: l=6m b=400cm=4m h=1.5m TSA of cuboid = 2 (lb+bh+lh) = 2(6*4 + 4*1.5 + 6*1.5) = 2(24+6+9) = 2*39 =78m convert it into cm So 78*100 = 7800 At the rate of rupees 22 = 7800 *22 =171600rupees l=6mb=400cm=4mh=1.5m TSA of cuboid = 2 (lb+bh+lh)= 2(6×4 + 4×1.5 + 6×1.5)= 2(24+6+9)= 2×39=78m convert it into cmSo 78×100 = 7800At the rate of rupees 22= 7800 ×22 =171600rupees Answer: Rs 1323960000 Step-by-step explanation: L = 6m B = 400m H = 1.5 m Surface area = total surface area = 2( LB + BH + LH) = 2 ( 6 × 400 + 400 × 1.5 + 6 × 1.5) = 2 ( 3009 ) = 6018 m^2 or 60180000 cm^2 Cost of painting per cm^2 = rs 22 So price = 22 × 60180000 = rs 1323960000 171600 is the right answer the price is : 171600.... |
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The cost of painting the surface of sphere is 1526 at the rate ofof sphere.6 per m2. Find the radius |
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Answer» Surface area of sphere ×6=15264πr^2×6=15264πr^2=1526÷64πr^2=254.33r^2=254.33÷4×3.14r^2=20.24r=4.49r=4.5m(approximately) thx |
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3. "The areas of two sectors of two different circleswith equal corresponding arc lengths, are equal".Is this statement true? Why? |
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16. Find the area of an isosceles triangle wiouthe third side is 12 cm.81017. Find the area of the polygon ABCDE whose measurements812 12recrecain metre are given in the following figure.10 |
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ind the base of the triangle whose a) area 40 m2, height- 8 m) area 210 cm2, height 21 cm) area 82.5 m2 ,height-10 m |
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Answer» base=2A/hi) 2×40/8=10mii)2×210/21=20miii) 2×82.5/10=16.5m |
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| 9. |
Prove that a cyclic parallelogramrectangle |
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| 10. |
Prove that a cyclic parallelogram is a rectangle |
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7. A building has 25 cylindrical shaped polesEach has a radius of 28 cm and a height of 4cm. Find the cost of painting curved surfaceof all poles at the rate of 8 per m2 . |
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Answer» Given,Radius of each pillar= 28 cmHeight of each pillar=4 m= 400 cmSo, as we all knowCSA of a cylinder= 2(22/7) rh= 2 (22/7) (28) (400)= 70400 sq cm = 7.04 m sqCSA of one pillar =7.04= (24) = 168.96 sq mSince, cost of painting 1 sq m= Rs. 8∴Cost of 168.96 sq m =Rs. 8 ( 168.96) = Rs. 1315.68 |
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8. The cost of painting the surface of sphere is 1526 at the rate of 6 per m2. Find the radiusof sphere.le |
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Answer» Surface area of sphere ×6=15264πr^2×6=15264πr^2=1526÷64πr^2=254.33r^2=254.33÷4×3.14r^2=20.24r=4.49r=4.5m(approximately) |
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21.In a building, there are 24 cylindricalpillars. The radius of each pillar is 28 cmand height is 4 m. Find the total cost ofpainting the curved surface area of allpillars at the rate of 8 per m2(A) 1352.68 (B) 351.68(C) 1353.68 (D)1340.68 |
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Answer» Radius of cylinderical pillars = r = 28cm =0.28m height ,h=4m curved surface area of a cylinder =2πrh curved surface area of a pillar= 2×22\6×0.28×4=7.04metresq. Curved surface area of 24 such pillars = 7.04×24=168.96metresq. cost of cementing an area of 1metresq. =Rs8 so,cost of painting 1689.6metresq. =168.96×8=Rs1,351.68 Like my answer if you find it useful! |
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| 14. |
The exterior <PRS of ΔPQR is 1 050. If Q = 70°, find <P. Is <PRS ><P ? |
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Prove that a cyclic parallelogram is a rectangle. |
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15. Find the value ofPRS.3040 |
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In fig if POR=50° angle PRS =130°find the measure of angle QPR |
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Answer» by exterior angle theoremangle P + angle Q = angle PRSangle P + 50° = 130°angle P = 130° - 50° = 80° Thank you. |
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17. In figure, <PRS-1100, <PTQ-80, Find x and y1100800x |
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7. Simplify :互堮1.44 592a) 13b)81c) 1817 |
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Answer» 7) Ans:b) 8 1/7...... |
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. In the above fig., if PQ = PT and angleTPS=angle QPR, prove that ∆PRS is isosceles. |
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Simplify by rationalising the denominator.\frac{7 \sqrt{3}-5 \sqrt{2}}{\sqrt{48}+\sqrt{18}} |
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10. In a building, there are 24 cylindrical pillars.For each pillar, radius is 28 cm and height is4 m. Find the total cost of painting thecurved surface area of the pillars at the rateof ? 8 per m2. |
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Answer» R=28cm =0.28mh =4marea of curved surface =2πrh =7.04mcost per m square = 8cost for 7.04m = 7.04 x 8 =56.32m square x 24 = 1359.36Rs |
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sxample 6: In a building there are 24 cylindrical pillars.28 cm and height is 4 m. Find the total cost of painting the curvedall pillars at the rate of 8 per m2.The radius of each pillar |
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4. A flooring tile has the shape of a parallelogram whose base is 24 cm and thecorresponding height is 10 cm. How many such tiles are required to cover a floor ofarea 1080 m2? (If required you can split the tiles in whatever way you want to fill upthe corners) |
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A flooring tile has the shape of a parallelogram whose base is 24 cm and thecorresponding height is 10 cm. How many such tles are required to cover a floor of4.1080 m2? (If required you can split the tiles in whatever way you want to fill upthe corners). |
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| 26. |
In a building there are 24 cylindrical pillars. The radius ofeach pillar is 28 cm and height is 4 m. Find the total costof painting the curved surface area of all pillars at the rateof Rs 8 per m2. |
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Answer» Radius of cylinderical pillars = r = 28cm =0.28mheight ,h=4mcurved surface area of a cylinder =2πrhcurved surface area of a pillar= 2×22\6×0.28×4=7.04m^2Curved surface area of 24 such pillars = 7.04×24=168.96m^2cost of cementing an area of 1m^2. =Rs8so,cost of painting 1689.6m^2.=168.96×8=Rs1,351.68 |
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9. In a building there are 24 cylindrical pillars. The radius ofeach pillar is 28 cm and height is 4 m. Find the total costof painting the curved surface area of all pillars at the rateof Rs 8 per m2 |
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Answer» Curved Surface Area of a cylinder.= 2πrh So CSA of one cylinder = 2×π×(0.28)×4Putting π=22/7, we get,=2×22×(0.4)×4 = 70.4 So for 24 cylinders, csa = 24×70.4 = 1689.6 m sq.So cost = 8×1689.6 = 13516.8 Rs. |
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20 m4. A flooring tile has the shape of a parallelogram whose base is 24 cm and thecorresponding height is 10 cm. How many such tiles are required to cover a floor Oarea 1080 m2? (If required you can split the tiles in whatever way you want to fill upthe corners).attered on the floor. |
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Answer» Mensuration: Mensuration is the branch of mathematicswhich concerns itself with the measurement of Lengths, areas & volume ofdifferent geometrical shapes or figures. Plane Figure: A figure which lies in aplane is called a plane figure. For e.g:a rectangle, square, a rhombus, a parallelogram, a trapezium. Perimeter: The perimeter of a closed plane curve isthe total length of the curve. Unit of perimeter is a unit of length. Area: the area of the plane figure is thesurface enclose by its boundary. A square centimetre (cm²) is generallytaken at the standard unit of an area. We use square metre (m²) also for theunits of area. ========================================================== Solution: Given : base= 24 cm Height= 20 cm Area of floor= 1080 m²= 1080×100×100cm² [1m²= 10000cm²] Area of the Parallelogram = base xheight = 24 x 10 = 240 cm² Area of1 tile = 240 cm² [Tiles are in the shape of a parallelogram] Number of tiles required= Area of theFloor/Area of the Tiles = 1080 X100 X100/240 =45000 Number of tiles required to cover a Floor=45000 ========================================================= |
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Find the curved surface area of cylinder, whose radius is 7 cm. and heightis 10 cm |
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Answer» CSA= 2*22/7*10*7= 440cm^2as CSA= πr^2h A=2πrh+2πr^2=2×3.14×7×10+(2×π×7^2)=747.6 99cm^2 |
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58. यदि in A-ल और sing58. यदि in A=osinB =-जहाँ A और B न्युनकोण हैं, तो (A+B) ।।बराबर हैं।| (A);(A)(B);18(C) ।(इनमें से कोई नहीं |
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Answer» D is the best answer d is the right answer explanation do d is right answer because we cannot right as above values option d is the correct answer option d is the correct answer option d is the right answer option d is the right answer option D is the right answer option d is the right answer option d is the right answer option d is the right answer option d is the right answer option d is the right answer sin(A+B)=SinACosB+CosASinBsin(A+B)=1/√10*1/√3+1/√3*1/√10=1/√30+1/√30=2/√302/√30 is not a value of any number in sin series |
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(f . g) o h = (foli)Find gof and fog, if"Uff(x) = 1 x l and g(x) =15x-21f(x) = 8x3 and g(x)-z? |
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Answer» part 1 part 2 |
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6. Which of the two rational numbers is greater in the given pair?8th 3 or 7ONGS(iv)9 or 7(v) 4-13° -127. Fill in the blanln mitu(5 ºf 10(vi) |
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Radius of a circle is 3 meter, what would be the radius of a circle whose area is 9times the area of the first circle? |
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Answer» area of circle with radius 3marea=πr^2=9πcm^2hence nine time the area =9*9π=81πcm^2hence radius will.be 81π/9π=9cm |
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(a) 58(b) V58 (c) 40 |
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find the radius of a circle whose area is 616cmsqare |
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Answer» thanks |
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a pout S.H ihe bisetos of PoR andlPRS nvei at poar , thet prove thatwFigă6.44 |
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What is the radius of a circle whose area is 154 cm2? |
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Answer» A=Pi×r^2r^2=A/Pi = 154÷22/7 = 154×7/22=49r=7Ans) The radius of the circle is 7cm. |
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ang20. In the given20. In the givenPgure, peiSR, < PRs-70°, LSRT = 35°. Find thetriangle.而市70* |
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Answer» thqnku |
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4. Find the diameter of a circle, whose area is: (i) 50.24 m^2 |
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Find the height of cylinder whose radius is 7 cm and the total surface area is 968 cm |
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Answer» pls read the question carefully |
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| 41. |
~ XU M Lp =X g |
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Answer» hit like if you find it useful |
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1 LP+2Q = 90° 71, UK Casincos-sin cos Q = cos P |
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Answer» P+Q=90Q=90-PLHS = √sinp/cosQ- sinpcosQ = √sinp/cos(90-p)- sinP×cos(90-P)= √sinP/sinP-sinP×sunP=√1-sin^2P√cos^2P= cosP= RHS proved |
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Find ten rational numbers between 3/5 and 3/4 |
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13. Find the missing number, if same rule is followed inall the three figures813TOA.58C116B.D174232 |
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Answer» d) 232 is the best answer d)232 is the right answer d is the right answer plz like my answers I like yours answer 232 is the correct answer me to in fig a1+2+3+4=10×3=30in fig b7+8+9+10=34×3=102in fig c13+14+15+16=58×3=174 is Right answer please select my answer as best 232corrct answer jau 232 is the right answer B answer 232 this answer right D'232 right answer me 232 is right answer pllz like my answer 174 Ansar hai........ 174 is correct answer. d) 232 is the best answer 174 is correct answer first u add all the numbers in first box 1+2+4+3 then answer is 10 then multiply by 3 so answer is 30 then to confirm 7+8+10+9then answer 34 ×3 102so 13+14+16+15 =58×3=174 the right option is B 232 is the correct answer |
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12. Prove that a cyclic parallelogram is a rectangle. |
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| 46. |
Find the radius of a circle whose area is 38.5 m2 |
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| 47. |
Simplify 20-(18/(7-2+1) |
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Answer» correct answer is 20-(18/(7-2+1)) 20-(18/6) 20-317 17 is the right answer... correct answer is 17 correct answer is 17 17 is right answer ...... 17 is the correct answer |
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20 - 13 - 2 %2B 1 %2B 7 %2B 35 |
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Answer» = 20 – (13-(7+7×5 – (2–1) )= 20 – ( 13 –( 14+5 –(1)= 20 – ( 13 – (70 - (1)subtracting... = 20 – ( 56 )= 20 – 56 = –36 -36 is the correct answer of the given question -36 is the correct answer |
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| 49. |
3five rational numbers betweenand52 |
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| 50. |
343Find ten rational numbers betweenand |
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