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The dimensions of a cuboidal box are 6 m x 400 cm x 1.5 m. Find the cost ofpainting its entire outer surface at the rate of 22 per m2. |
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Answer» Step-by-step explanation: l=6m b=400cm=4m h=1.5m TSA of cuboid = 2 (lb+bh+lh) = 2(6*4 + 4*1.5 + 6*1.5) = 2(24+6+9) = 2*39 =78m convert it into cm So 78*100 = 7800 At the rate of rupees 22 = 7800 *22 =171600rupees l=6mb=400cm=4mh=1.5m TSA of cuboid = 2 (lb+bh+lh)= 2(6×4 + 4×1.5 + 6×1.5)= 2(24+6+9)= 2×39=78m convert it into cmSo 78×100 = 7800At the rate of rupees 22= 7800 ×22 =171600rupees Answer: Rs 1323960000 Step-by-step explanation: L = 6m B = 400m H = 1.5 m Surface area = total surface area = 2( LB + BH + LH) = 2 ( 6 × 400 + 400 × 1.5 + 6 × 1.5) = 2 ( 3009 ) = 6018 m^2 or 60180000 cm^2 Cost of painting per cm^2 = rs 22 So price = 22 × 60180000 = rs 1323960000 171600 is the right answer the price is : 171600.... |
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