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could you explain me again only last step

Volume of cylinder Vc = pi*r*r*hGiven r = 14 cm, h = 196 cm

Vc = 22/7*14*14*196 = 22*14*14*28 = 120736 cm^3

Volume of Dice Vd = side*side*side = 14*14*14 = 2744 cm^3

Let no. Of Dice can be made is n

Thenn*Vd = Vcn = 120736/2744 = 44

Diameter of the vessel = 4 cm

Radius of the vessel = 2 cm

Rise in water level = 0.8 cm

Volume of the increased water level = πr²h

= 22/7 × (2)²× 0.8 = 10.06 cu cm.

Volume of 300 lead balls = 10.06 cu cm

But, volume of 300 balls = 300 × 4/3 × 22/7 × (r)³

⇒ 300 × 4/3 × 22/7 × (r)³= 10.06

⇒ (r)³ = 10.06 × 1/300× 3/4× 7/22

⇒ (r)³≅ 0.008

⇒ r = 0.2

So, the radius of each ball is 0.2 cm

Plant cells have cell wall because plants do not move from one place to another and hence they require rigidity which is provided by the cell wall.The major function of cell wall is to provide rigidity and strength and also providesmechanisms for plants to take up water.Cell wallsare supporting structures that help theplantto have a fixed shape and protect it from injury. Other than that, it helps to keep the plant turgid so that it can stay firm and upright. Because when it enters a high water potential solution, as water moves in, the water exertsturgor pressureon the cell wall and the cell wall thus exerts an opposing pressure to keep water out. Hence cell wall is needed for the plant.

solid possesrigidityandliquidand gases posses fluidiy .

Here n=4 it lies in d-block

The symbol[Ar]in the condensedelectron configurationof this element resembles the electron configuration of a ground-state argonAratom. It represents all inner shell electrons of this atom. (seethis problemfor details about condensed electron configurations.)

On the top of that, a ground-state atom of this element would containvalence electrons3d74s2. It would lie in the period right underneath the one containing argon. Argon is the last element of the third period. As a result, this element is in the fourth period ofthe periodic table. (And hencen=4)

The block on the periodic table an element belongs to is dependent on the type of the occupied electron orbital of highest potential energy.

part 1 of solution

part 2 of ailution

the answer of the question is given below the question.and it is 12%

option B is the correct answer of the given question

I like the answer is 8%

2500-2200=300then u doit

15 is the right answer

15 is the right answer

the answer is the i thing 12

B. 12% is the right answer

nice question 12is the right answer

12 is 100% guaranteed correct answer

2500-2200 = 300.300 kitna % hai 2500 ka?(300 x 100) ÷ 2500 = 12.iska matlab haani 12 pratishad hui hai.

option B is the right answer

thanks

(c) if 7/13 = 5/11

then on cross multiplication 7*(11) = 5*(13)=> 77 = 65

but this is not true as 77≠ 65..so, 7/13 ≠ 5/11

A= P(1+R/100)^n= 6000(1+9/100)^26000*109/100*109/1006*109*109/107128.6

rs 1128.6 is correct answer

i) 2/8=4/16=6/24=8/32=10/40ii) 6/7=12/14=18/21=24/28=30/35

1) 2/3 = 4/6 = 6/9 = 8/12 = 10/15 = 12/182) 4/5 = 8/10 = 12/15 = 16/20 = 20/25 = 24/303) 5/8 = 10/16 = 15/24 = 20/32 = 25/40 = 30/485) 3/7 = 6/14 = 9/21 = 12/28 = 15/35 = 18/42 6) 6/11 = 12/22 = 18/33 = 24/44 = 30/55 = 36/667) 7/9 = 14/18 = 21/27 = 28/36 = 35/45 = 42/54

five equivalent fraction of 3/5 are 6/10, 9/15, 12/20, 15/25, 18/30

3*2/5*2=6/10,9/15,12/20,15/25,18/30

Equivalent fractionsarefractionsthat look different but show exactly the same amount. You can make Equivalent fractionsby multiplying or dividing the numerator and denominator by the same number. You can simplifyfractionsby dividing the numerator and denominator by the same number. This is called cancelling.

So equivalent fractions of 3/5 are6/109/1512/2015/2518/30

1/22/4 = 1/23/6 = 1/24/8 = 1/2

Yes, all the fractions are equivalent.

2 by 1,4 by 2,6 by 3,8 by 4

que's-1solution :- 1/2 = 2/4 3/6 4/8

55) (46)^2-(?)^2=4398-3066 => 2116 - (?)^2= 1332 => (?)^2 = 2116 -1332 => (?)^2 =786 => (?)^2 =28^2 => (?) = 28Ans: (b) 28

=144°

if length and breadth of a rectangular field are in teacher the ages numerical in 9 more than the perimeter the perimeter is 32

Reactivity - Reactivity refers to how likely or vigorously an atom is to react with other substances. This is usually determined by how easily electrons can be removed (ionization energy) and how badly they want to take other atom's electrons (electronegativity) because it is the transfer/interaction of electrons that is the basis of chemical reactions.

MetalsPeriod - reactivity decreases as you go from left to right across a period.Group - reactivity increases as you go down a groupWhy? The farther to the left and down the periodic chart you go, the easier it is for electrons to be given or taken away, resulting in higher reactivity.

Non-metalsPeriod - reactivity increases as you go from the left to the right across a period.Group - reactivity decreases as you go down the group.Why? The farther right and up you go on the periodic table, the higher the electronegativity, resulting in a more vigorous exchange of electron.

a=factors of 12=1,2,3,4,6factors of 16=1,2,4,8,16common factors are 1,2,4highest common factor=4

it will react with oxygen to form magnesium oxide

2Mg + O2 → 2MgOOxygen and magnesium combine in a chemical reaction to form this compound. After it burns, it forms a white powder of the magnesium oxide. Magnesium gives up two electrons to oxygen atoms to form this powdery product. This is an exothermic reaction

The magnesium atoms in the ribbon combine with oxygen atoms in the air, to produce a compound, magnesium oxide, which is a white solid, and the reaction also gives off lots of heat and light. It's a bright white light, that is so dazzling that you really must view it only through a piece of dark blue Bristol glass.

The white magnesium oxide reacts slightly with water to produce the basic magnesium hydroxide. This is neither like magnesium nor like oxygen, and so indicates that a new chemical substance was produced by the burning.

The chemical equation,Mg+ O2MgO shows this reaction but it needs to be balanced to make 2Mg + O22MgO.

Like my answer if you find it useful!

When Calcium oxide i.e.quick limeisaddedtowaterfilled in a bucket, it reacts vigorously withwaterto produceslaked lime(calcium hydroxide) releasing a large amount of heat.

21-(12÷4)-(3×-7)=21-3+21=39

Chapter 1 has many pages. Sorry!

(x^2+5x)(X+5)(X+12)+150=0x^3+5x^2+5x^2+25x(X+12)+150=0x^4+12x^3+5x^3+60x^2+5x³+60x²+25x²+300x+150=0x⁴+22x³+145x²+300x+150=0

The concept oflogical operatorsis simple. They allow a program to make a decision based on multiple conditions.Eachoperand is considered a condition that can be evaluated to a true or false value. ... The &&operatoris used to determine whether both operands or conditions are true and.pl

x( x+5)( x+7)( x+12)+150; x( x^2+7x+5x+35)( x+12)+150); x( x^2+12x +35 )( x+12)+150; x(x^3+12x^2+35x +12x^3+144x+ 420 + 150)= x^4+12x^3+12x^3+35x^2+144x + 570= x^4+24x^3+35x^2+144x +'570

0 is the correct answer

Let the investment be Rs xGiven SP of the machine is Rs 2040That is (x -15% of x) = Rs 2040

Hence, (85/100)x = 2040 2040 x (100/85) = 2400

Hence the investment on the machine is Rs 2400

Given gain should be 10%Hence 10% of Rs 2400 = Rs 240

Therefore the selling price should be Rs (2400 + 240) = Rs 2640

SP = 2040 LOSS = 15% CP = 2040/0.85 = 2400 GAIN = 10% SP = 2400*1.1 = 2640

Let initial rupees be Xhencex-105=spent

cost of two mobiles is ₹16,000

Cost of one mobile is ₹ 16000/2= ₹8000

Total money requried for 13 mobiles is

= ₹ 8000 × 13 = ₹ 104,000

8min= 152m1min=152/8=19mHalf hour=30min=30*19=570mSo,rate of decending =-570mC)-570m

the answer os -570 okk

8 min = 152 m1min = 152/8=19 mHalf hour = 30minSo 30*19=-570 mThus, the ans is - 570m

-570 is correct answer

Here ia the list of all roman numerals from 1 to 100

seventy six is the correct answer of the given question

seventy six is the right answer

It will written as seventy six in words

seventy six is your answer😊....

C

7 - 12- 21 - 29 - 36

option: C 7 <12 <21 <29 <37

The answer will be 12

The mode of the data is the most recurring frequency. Here 25 appears 5 times. Therefore, the mode of the given data is 25.