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Let the digits be x and y.

Then, x+y = 9

the original number =10x+y.

Reversed= 10y+x

The new number is greater than the old number by 27, i.e.

(10y+x) - (10x+y) = 27 9y-9x = 27y-x = 3 x+y = 9

Adding the two equations, we get 2y = 12 or y = 6.

Thus, x = 3.

Therefore, the original number is 36.

Diagonal 6cm = 3cm + 3cm = legs of right triangle within rhombus.

Diagonal 8cm = 4cm + 4cm = legs of right triangle within rhombus.

We need to find the side of the rhombus using the Pythagorean Theorem.After that, we use the formula P = 4s to find your perimeter.

Let s = side of rhombus.3^2 + 4^2 = s^29 + 16 = s^225 = s^25 = s

Therefore,The side of rhombus is 5cm

I don't know u tell me answer

X+6=13X+6-6=13-6X=7

area 1st /area 2nd = 36/121(1 St side)^2/(2 ND side)^2 =36/121side 1st/side 2nd =√36/121 = 6/11option C is right

a is the right answer..

triangle

A triangle has 0 diagonal.

a triangle has zero daigonal

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answer

-3/5 and 3/4-12/20 and 15/20hence 10 numbers can be-11/20,-10/20,-9/20,-8/20,-7/20,-6/20,-5/20,-4/20,-3/20,-2/20,-1/20

Actinides show a variety of oxidation states from +3 to +6. This is due to the very small energy gap between5f, 6d and 7s sub shells. The principal oxidation states are +3 and +4 and +3 oxidation state is the most stable. The +4 oxidation state is the most stable in Th andPu.

For the numbers 30,40,45 and 60 to be in continued proportion,(a:b::c:d);As, 30×60=40×45=1800

Hence, the numbers are in continued proportion.

swimmer can swim in still water with a speed of 5m/s whilecrossing a river his average speed is 3m/s

so then the speed of the water flow is 2m/s

Discount= 650-58565percentage= 65/650*100= 10thanksplease like the solution 👍 ✔️

Discount percentage 400-300/400*(100)25 percentage

s. p = 2800; m.p=3500; Gst=3500-2800=700; GST=700/3500×100= 7/35 × 100=100/5=20°\•

SP of the cooler is 2800.MP is 3500.Discount =MP-SP 3500-2800 =700Discount =700Discount%=DISCOUNT/MP×100700÷3500×100=20%But MPof

(3,500-2,800)700/3500*10020% is the correct answer

MP = 1000Discount % = 12% discount price = 12% of 1000 = 120so SP = MP - discount priceSP = 1000-120 = 880

2NaHCO3+ H2So4= Na2So4+2H2O +2CO2

Let ABC is the metallic cone and DECB is the required frustum.

Let the radii of frustum are r1and r2.

i.e. DP = r1and BO= r2

Now from ΔADP and ΔABO,

r2= h1*tan30

=> r2= 10* 1/√3

=> r2= 10/√3

r1= (h1+ h2)tan30

=> r1= 20* 1/√3

=> r1= 20/√3

Now volume of the frustum DECB = (Π *h2/3)*(r12+ r1* r2+ r22)

=(Π *10/3)*{(20/√3)2+ 10/√3 * 20/√3+ (10/√3)2}

=(Π *10/3)*{400/3 + 200/3 + 100/3 }

= Π *10/3 * 700/3

= Π *7000/9

Now let l is the length of the wire.

Given diameter of the wire d = 1/16

So radius of the wire R = d/2 = 1/16 * 1/2 = 1/32

Now volume of the frustum = volume of the wire drawn from it

=> (Π*7000)/9 = Π*R2*l

=> l = (Π*7000)/(Π*R2*9)

=> l = (7000/{(1/32)2*9}

=> l = (7000** 32*32)/9

=> l = 7168000/9

=> l= 796444.444 cm

=> l = 796444.444/100 m

=> l = 7964.444 m (since 100 cm = 1 m)

So length of wire is 7964.444 m

Let ABC is the metallic cone and DECB is the required frustum.

Let the radii of frustum are r1and r2.

i.e. DP = r1and BO= r2

Now from ΔADP and ΔABO,

r2= h1*tan30

=> r2= 10* 1/√3

=> r2= 10/√3

r1= (h1+ h2)tan30

=> r1= 20* 1/√3

=> r1= 20/√3

Now volume of the frustum DECB = (Π *h2/3)*(r12+ r1* r2+ r22)

=(Π *10/3)*{(20/√3)2+ 10/√3 * 20/√3+ (10/√3)2}

=(Π *10/3)*{400/3 + 200/3 + 100/3 }

= Π *10/3 * 700/3

= Π *7000/9

Now let l is the length of the wire.

Given diameter of the wire d = 1/16

So radius of the wire R = d/2 = 1/16 * 1/2 = 1/32

Now volume of the frustum = volume of the wire drawn from it

=> (Π*7000)/9 = Π*R2*l

=> l = (Π*7000)/(Π*R2*9)

=> l = (7000/{(1/32)2*9}

=> l = (7000** 32*32)/9

=> l = 7168000/9

=> l= 796444.444 cm

=> l = 796444.444/100 m

=> l = 7964.444 m (since 100 cm = 1 m)

So length of wire is 7964.444 m

from which book the question is

NCERT

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Thanks

Let ABC is the metallic cone and DECB is the required frustum.

Let the radii of frustum are r1and r2.

i.e. DP = r1and BO= r2

Now from ΔADP and ΔABO,

r2= h1*tan30

=> r2= 10* 1/√3

=> r2= 10/√3

r1= (h1+ h2)tan30

=> r1= 20* 1/√3

=> r1= 20/√3

Now volume of the frustum DECB = (Π *h2/3)*(r12+ r1* r2+ r22)

=(Π *10/3)*{(20/√3)2+ 10/√3 * 20/√3+ (10/√3)2}

=(Π *10/3)*{400/3 + 200/3 + 100/3 }= Π *10/3 * 700/3 = Π *7000/9

Now let l is the length of the wire.

Given diameter of the wire d = 1/16

So radius of the wire R = d/2 = 1/16 * 1/2 = 1/32

Now volume of the frustum = volume of the wire drawn from it

=> (Π*7000)/9 = Π*R2*l=> l = (Π*7000)/(Π*R2*9)=> l = (7000/{(1/32)2*9}=> l = (7000** 32*32)/9=> l = 7168000/9=> l= 796444.444 cm=> l = 796444.444/100 m=> l = 7964.444 m (since 100 cm = 1 m)

Bhai figure

Let cost price of 1 article be 1 rupeethen , cost of price of 4 articles = 4 rs

cost of 6 articles = sp of 4 articles = 6 rs

gain = sp - CP=> gain = 6-4 => 2 rs

gain % = gain/cp × 100=> gain % = 2/4×100=> gain % = 50%

3

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Gain percentage= 22400/140,000*100= 16 percentage

Cost of 8 book is ₹72 So, cost of 1 book is ₹ 72/8 = ₹9so cost of 20 books is ₹ 9 × 20 = ₹180

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Let the ratio of angles be x so angles are 2x and 3x .

Sum of angles in a triangle is 180°

2x + 3x + 60° = 180°

5x = 120°

x = 120°/5 = 24°

So, angles are 48° and 72°

40 x is the correct answer.

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In statistics, a central tendency (or measure of central tendency) is a central or typical value for a probability distribution. It may also be called a center or location of the distribution. ... The most common measures of central tendency are the arithmetic mean, the median and the mode