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Given

6x -3y + 10 = 0

2x - y + 9 = 0

Comparing coffecients

6/2 = 3/1

-3/-1 = 3/1

10/9

So, we see this is third case of parallel and there is no solution.

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hence a is 7 and b is -9

Ans :- In mathematics, the Pythagorean theorem, also known as Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.

a2+b2=c2

you can. use any other variable

Bro long answer

x+y =5 ----- 12x-3y=5 ------ 2

multiply equ 1 with 22x +2y=102x-3y = 5- + --------------------y =5y= -5

substitutein x+y =5x-5=5x =10

x= 10y= -5

It is correct answer

please check the comment in the above message

correct answer is x = 4, y = 1

it is correct answer

x+y = 5; 2x-3y=5;; 2(x+y=5); 2x+2y=10; 2x+3y=5/y=5 ;; 2x-3(5)=5; ; 2x=5+15=20; x=20/2=10

it is correct answer

the equationwill be x^2-(sum of roots)+ product of roots so it will be x^2+2x+1

hey thanks a lot for helping me out

Will u plzzz represent this on the number line for me plzzz....😯

2x-1/3=1/5-x2x+x=1/5+1/33x=3+5/153x=8/15x=8/45

We know,angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle .

Therefore,x = 2*60x = 120°

Let the speed of stream be x km/hSpeed downstream= (15+x)km/hSpeed upstream= (15-x)km/hTherefore, 30/15+x + 30/15-x =4½900/225-x²=9/29x²=225x²=25x= 5km/hr

120 degree (angle subtended by an arc at the centre is twice the angle subtended by it at any remaining part of the circle

Mean = sum of fixi / sum of fi 60 = (2800+640a)/(60+12a) 3600 + 720a = 2800 + 640a 720a - 640a = 2800 - 3600 80a = -800 a = -800/80 a = -10

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x=2*60°=120° because the angle subtended by an arc at the centre is twice the angle subtended by it on the circle.

from triangle ACF , the value of AC = CF/tan45° = 20.

and assume a perpendicular distance from F, parallel to CD then the value of CD = tan 60°*(DE-CF) = √3*10 = 10√3.

And at last the value of DB = DE/tan60 = 30/√3 = 10√3.

so , total distance AB = AC+CD+DB = 20+10√3+10√3 = 20(1+√3).

Perimeter of rectangle=2(l+b)b=12P=6060=2(l+12)60=2l+242l=60-242l=36l=36/2l=18

120 the correct answer of the given question

the answer is 120....

median is the n/2 + n/2 +1 th term if n is even.

x + x + 2 = 142x= 12x = 6

any doubt feel free to ask in chat but plz accept my answer as best

6 is the correct answer of the given question is

x=6 is the right answer

median n/2 + n/2 +1 ; x + x + 2 = 14; 2x = 12;; x = 12/2 = 6

x=6 is the correct answer

3/7 = 0.4284 5/9 = 0.556 1/3 = 0.333 1:3,3:7,5:9

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For equal roots discriminant is zerohenceb^2-4ac=0hence(3k)^2 - 4*4*9 = 0 k^2 - 16 = 0 k = √16 = 4

wrong

Let AO=HCD=OB=60mA'B=AB=(60+H)m

In triangke AOD,tan30'=AO/OD=H/OD

H=OD/√3OD=√3 H

Now, in triangle A'OD,tan60'=OA'/OD=(OB+BA')/OD√3=(60+60+H)/√3 H =(120+H)/√3 H=>120+H=3H 2H=120 H=60m

Thus, height of the cloud above the lake = AB+A'B =(60+60) = 120m

x^2 + 7x + 12 = 0x^2 + 4x + 3x + 12 = 0x(x + 4) + 3(x + 4) = 0(x + 3)(x + 4) = 0x = - 3, - 4

the smallest positive integer with sum of its digits being equal to2013 will be

6999...999...with the total of 2239's.

Mutliply it by55. It will turn into

34999...9995... having 2229's in the middle.

Finally, add 2013. Your number will turn into

35000...00012008... containing 21800's in between. The value ofSSbecomes

S(5N+2013)=19

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Given observation are:

29, 32, 48, 50, x, x+2, 72, 78, 84, 95

Total number of observation i.e n = 10

Given, median = 63

=> (5th value ofobservation + 6th value of observation)/2 = 63

[if number of observation is even then median = mean of (n/2)th value of observation + {(n/2) + 1}th value

of observation]

=> (x + x + 2)/2 = 63

=> (2x + 2)/2 = 63

=> 2x + 2 = 63*2

=> 2x + 2 = 126

=> 2x = 126-2

=> 2x = 124

=> x = 124/2

=> x = 62

Hence, the value of x is 62

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