Q.5. If thenecian of the data arranged in ascending order is 63, find

1.	Q.5. If thenecian of the data arranged in ascending order is 63, find the value of x in.6 A9, 32, 48, x -2, x,x+2,72, 78. 84, 95
Answer» Given observation are: 29, 32, 48, 50, x, x+2, 72, 78, 84, 95 Total number of observation i.e n = 10 Given, median = 63 => (5th value ofobservation + 6th value of observation)/2 = 63 [if number of observation is even then median = mean of (n/2)th value of observation + {(n/2) + 1}th value of observation] => (x + x + 2)/2 = 63 => (2x + 2)/2 = 63 => 2x + 2 = 63*2 => 2x + 2 = 126 => 2x = 126-2 => 2x = 124 => x = 124/2 => x = 62 Hence, the value of x is 62 Like my answer if you find it useful!

Q.5. If thenecian of the data arranged in ascending order is 63, find the value of x in.6 A9, 32, 48, x -2, x,x+2,72, 78. 84, 95

Answer»

Given observation are:

29, 32, 48, 50, x, x+2, 72, 78, 84, 95

Total number of observation i.e n = 10

Given, median = 63

=> (5th value ofobservation + 6th value of observation)/2 = 63

[if number of observation is even then median = mean of (n/2)th value of observation + {(n/2) + 1}th value

of observation]

=> (x + x + 2)/2 = 63

=> (2x + 2)/2 = 63

=> 2x + 2 = 63*2

=> 2x + 2 = 126

=> 2x = 126-2

=> 2x = 124

=> x = 124/2

=> x = 62

Hence, the value of x is 62

Like my answer if you find it useful!