1.

Let .SİM) denote the sum of the digits of a positive integer M written in base 10, Let N Dethe smallest positive integer such that S(N) 2013. What is the valve of S(5N +2013

Answer»

the smallest positive integer with sum of its digits being equal to2013 will be

6999...999...with the total of 2239's.

Mutliply it by55. It will turn into

34999...9995... having 2229's in the middle.

Finally, add 2013. Your number will turn into

35000...00012008... containing 21800's in between. The value ofSSbecomes

S(5N+2013)=19

Sorry but I didn't get it



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