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20 percentage पर 34% लाभ1 परसेंटेज par-----34/20%तब 15% पर लाभ =34/20*1535.5%

In order to find rational numbers between- 4/5 and -1/2 first make denominator same

Multiply and divide - 4/5 by 8Multiply and divide - 1/2 by 20

Now 10 rational numbers between- 32/40 and -20/40 are - 31/40, - 30/40, - 29/40, - 28/40, - 27/40, - 26/40, - 25/40, - 24/40, - 23/40, - 22/40

shyly brother there is -4/5

thank you

u have other methods

V=πr^2 h/3=3.14×(4)^2(14)/3=234.5 72

To find:10 rational number between -2/5 and 1/2

-2/5 multiply by the denominator of 1/2=-4/10

1/2 multiply by the denominator of -2/5=5/10

now the denominator's are same,but we don't have tenrational no.

between these two numbers.now the question is to find 10rational number

then multiply -4/10& 5/10 by 5u will get -20/50 & 25/50.

so, the required rational numbers are:- -19/50, -18/50, -17/50, -16/50, -15/50, -14/50,-13/50, -12/50, -11/50, -10/50...

Given

3/5 and 3/4

now

3/5 = 3/5 × 4/4 = 12/20 × 4/4 = 48/80

and

3/4 = 3/4 × 5/5 = 15/20 × 4/4 = 60/80

10 rational numbers are

49/80 , 50/80 , 51/80 , 52/80 , 53/80 , 54/80 , 55/80 , 56/80 , 57/80, 58/80

b^2 -4ac = 0(-2k+2)^2 - 4(k+1) =04k^2 -8k +4 -4k -4 =04k^2 -12k=04k^2 = 12k___k =3___

दिया गया: ABC एक त्रिभुज है जिसमें भुजाओं BC, CA और AB के मध्य बिंदु D, E और F हैं।

दिखाने के लिए: (i) BDEF एक समांतर चतुर्भुज है। (ii) ar (DEF) = 1 / 4ar (ABC) (iii) ar (BDEF) = 1 / 2A (ABC)

प्रमाण: i) चूँकि E और F AC और AB के मध्यबिंदु हैं।

BC || FE & FE = = BC = BD

(मध्य बिंदु प्रमेय द्वारा)

बीडी || FE और BD = FE

इसी तरह, BF || DE & BF = DE

इसलिए, BDEF एक समांतर चतुर्भुज है

[[विपरीत पक्षों की एक जोड़ी समान और समानांतर है]

(ii) इसी तरह, हम यह साबित कर सकते हैं कि FDCE और AFDE भी समांतर चतुर्भुज हैं।

अब, बीडीईएफ एक समांतर चतुर्भुज है, इसलिए इसका विकर्ण एफडी समान क्षेत्रों के दो त्रिकोण में विभाजित करता है।

∴ ar (∴BDF) = ar ((DEF) - (i)

समानांतर चतुर्भुज AFDE में

ar ((AFE) = ar ()DEF) (EF एक विकर्ण है) - (ii)

Parallelogram FDCE में

ar (FCDE) = ar ()DEF) (DE एक विकर्ण है) - (iii)

से (i), (ii) और (iii)

ar (ΔBDF) = ar (=AFE) = ar ()CDE) = ar ((DEF) ..... (iv)

ar (ΔBDF) + ar (FEAFE) + ar ()CDE) + ar (arDEF) = ar (CABC)

4 अर (arDEF) = ar ()ABC) (eq iv से)

ar (∆DEF) = 1/4 ar ()ABC) ........ (v)

3x+ty-6=03×1+t×1-6=03+t-6=0-3+t=0t=3

Let​∫sin^3x cosx.dx = ILet sinx=t implies cosx.dx =dtSo, I =​∫ t3.dt = 1/4 * t^4+c = 1/4(sin^4x) +c

break it at X= 5. and then solve it bro. plz like

tan^2x=

tan^2x+1=sec^2x

integral of sec^2x-1 from 0 to pi/4

I used the identities by starting from sin^2x+cos^2x=1 and dividing everything by cos^2x

integrate sec^2x which is tanx and integral of -1 is -x

integral of tanx-x

tan(pi/4) - pi/4

(1-pi/4)-tan(0) - 0

answer = 1-pi/4.

Like my answer if you find it useful!

Ni

no

modulus =√x^2+y^2=√1^2+(√3)^2=√1+3=√4=2

argument =tan^-1(y/X)=tan^-1(√3)=π/3

tan^-1((1-x)/(1+x))

Put x=tan A. ≈ tan^-1 x =A=tan^-1[(tan π/4-tan A)/(1- tan π/4×tan A)]

[Since,(tan A - tan B)/(1- tan A× tan B)=tan(A-B)

=tan^-1[tan(π/4-A)]

=π/4 - A

if we substitute A= π/4 - tan^-1 x

5/19+2/19=5+2/19=7/19 is correct answer

5/19+2/19 =7/19 is a right answer

5/19+2/195+2/197/19

7/19 is the best answer

=5/19+2/19=5+2/19=7/19

7/19 is the correct answer to this question

7/19 is the right answer according to your question

7/19

right ans like this answer

7/19 is the correct answer of this question

7/19 is correct answer.

5+2 =7 , and we don't have to add the denominator because the denominator remains same if the denominator were not same then we have to do the lcm of the denominator ... OK now it's clear

7/19 is the correct answer

7/19 is correctly anwer

7/19 is the right answer

a) 3 lies on real axis of complex plane having value = 3+0i b) 2i lies on imaginary axis of complex plane. having value 0+2i

ram ki age.. 4 year 7 manth 4 d

=1970-(-6)=1970+6=1976

(10000+10250+10790+9865+15350+10110)/6

= 11060.8333333

In ∆ ACB and ∆ ADCAC = AD (given)CAB = DAB ( given)AB= AB (common)so by SAS rule ∆ACB is congurent to ∆ADCso by CPCT BC = BD

5×3×5×3×7×7×7×9×9= 5²×3²×7³×9²= 5²×7³×3^6

7.5 ÷ 0.125 + 8.5 - 7.5 of 2.5 = 60 + 8.5 - 7.5×2.5/100 = 68.5 - 0.1875 = 68.3125

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