Q.No46: tan' x dx is equal to

1.	Q.No46: tan' x dx is equal to
Answer» tan^2x= tan^2x+1=sec^2x integral of sec^2x-1 from 0 to pi/4 I used the identities by starting from sin^2x+cos^2x=1 and dividing everything by cos^2x integrate sec^2x which is tanx and integral of -1 is -x integral of tanx-x tan(pi/4) - pi/4 (1-pi/4)-tan(0) - 0 answer = 1-pi/4. Like my answer if you find it useful! Ni no

Answer»

tan^2x=

tan^2x+1=sec^2x

integral of sec^2x-1 from 0 to pi/4

I used the identities by starting from sin^2x+cos^2x=1 and dividing everything by cos^2x

integrate sec^2x which is tanx and integral of -1 is -x

integral of tanx-x

tan(pi/4) - pi/4

(1-pi/4)-tan(0) - 0

answer = 1-pi/4.

Like my answer if you find it useful!

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