This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
find four rational number between 3/7 and 5/7 |
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| 2. |
Let A(3,-4) B(9,-4) C (5,-7) and D(7,-7).Show that ABCD is a trapezium |
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Answer» A(3,-4); B(9, -4)=(12, 16),B(9,-4)C(5,-7)=(14,,11); C(5,-7)D(7,-7); CD(12, 14) DA(7,-7)(3,-4)=(10,11) |
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| 3. |
(13) Karan borrowed 1.5 lakh from a bankat17% р.a. simple interest, what amountmust he pay back after 3 1/2 years? |
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Answer» Interest = 150000*17*7/2*100 = 89250 rupees |
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| 4. |
Let'srections for questions 1 to 10: Solve the following problems.Arrange the following integers in ascending order: 5.-12, -2, 18,-5, 7,-41.ctions for queWhich of |
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Answer» -12<-5<-4<-2<0<5<7<18 |
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| 5. |
29, Neha borrowed Rs. 25000 from a bank to buy a TV set at the rate of 16% compound interestWhat amount she has to pay to the bank after the period of 2 years and 3 months? |
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| 6. |
2) Que to off season, the price in a blanketis Meduced by 12% to 2.748. what wasit original puce. |
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Answer» Let original price of blanket be x After 12% discount Reduced price of blanket= 748 Then,x(1 - 12/100) = 748x(1 - 3/25) = 748x (22/25) = 748x = 748*25/22x = 34*25x = 850 Therefore, original price of blanket is Rs 850 first take out 12% of 748 .. then add the result to 748 |
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| 7. |
.What does the term 'tokens of myself mean? ( |
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Answer» When you give someone a flower or a friendship bracelet or something symbolic of the way you feel about them, you're giving them atokenof your affection. Atoken isnot only something sentimental (like a keepsake) or symbolic (like your friendship bracelet). |
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| 8. |
tomeanoffrornm anAP by inserting terms Il and-.Ifin an arithmetic progression the mean of pth and qand sth term then prove that p + q = r + s." term is equal |
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| 9. |
j15(x-9)-2(x-12) + 5(x + 6) = 0 |
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Answer» so intelligent |
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| 10. |
que Find the Five rational number betweenand 5 |
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| 11. |
Euclid belongs to the oluy.Que. 6. Find four rational number between 3/5 and 4/5. |
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Answer» 3/5 = 3×10/5×10 = 30/50 4/5 = 4×10/5×10 = 40/50 so, four numbers between 3/5 and 4/5 are 31/50, 35/50, 36/50, 38/50 |
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| 12. |
Que. 7 Show that 7-15 is irrational, give that 5 is irrational. |
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Answer» Let us assume, to the contrary, that 7-√5 is rational That is, we can find Coprime a and b (b≠ 0) such that 7-√5 = a/b Therefore, 7 - a/b = √5 Rearranging this equation √5 = (7b -a)/b since a and b are integers,so (7b -a)/b is an rational. And so √5 is rational But this contradicts the fact that √5 is irrational. This contradiction has arisen because of our incorrect assumption that 7-√5 is rational. Therefore we can conclude that 7-√5 is irrational. |
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| 13. |
Maths10.1 Give Five Example where the number of thing counted would be more than 6-Digit Numberir nanulation Find the distance in Kilometer between e |
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Answer» PopulationVotesPrice of carsParticles of sugar in 1 kgSand particles |
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| 14. |
Ram Prasad borrowed from co-operativesociety for 5 cartoon urea at Rs 230 per cartoonat 12% per annum. How much money will hepay to society at the end of year?5. |
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| 15. |
Ratansingh borrowed 16,000 at 12.5% rate ofinterest for 3 years to set up a motorpump on thewell from 'Gurudev Co-operative Society' at compoundinterest. If he would have taken this loan at simpleinterest, then what would be the difference in theinterest ?2. |
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| 16. |
4. Arvindbhai deposits 10,000 at 10% rate ofinterest for 3 years in a Co-operative Society atsimple interest and Pravinbhai deposits 10,000at 10% rate of interest for 3 years at compoundinterest in a bank. Find the difference betweeninterests obtained by Arvindbhai and Pravinbhai. |
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| 17. |
There are 3452 men, 2435 women and 1542children in a society. What is the populationof that society? |
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Answer» Total population=3452+2435+1542=7429 |
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| 18. |
1-cos χ-1V1+ cos x |
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Answer» 1+cosx=2cos^2(x/2)1-cosx=2sin^2(x/2)tan^-1(root(2sin^2(x/2)/2cos^2(x/2)))=tan^-1(root(tan^2(x/2))) ( now 0<x<pie so 0<x/2<pie/2so x/2 is in first quadrant so root(tan^2(x/2))=tan(x/2) ) =tan^-1(tan(x/2))=x/2 |
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| 19. |
1+ sin Ashow that sntan AV1-sin A |
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| 20. |
The sum of first 9 terms of an arithmetic sequence is 45 and the sum of first 18 terms is 171.(a) What is the sum of its 10th to 18th terms ?(b) What is its 5th term ?(c) Find its 14th term(d) Find the sum of 5th to 14th terms. |
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| 21. |
S.K. MATHEMATICSThe 5th term in the expansion of ( +2yfis(a) 10'y(b) 32,(c) 80y |
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Answer» 5th term is = 5C5 (2y)(2y)(2y)(2y)(2y) = 32y*y*y*y*y |
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| 22. |
Differentiate : cos-Differentiate : cos-1 v1+x?w.r.W.r.t. x |
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Answer» 3x. cos`1√1+x^2 is the right answer 3x cos 1√1+x^2 is right answer |
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| 23. |
Differentiate cOs t w.rt. x OR Differentiate inw .r t. x |
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| 24. |
factorize the following polynomials by splittigthe middle Aesmilij 22-32-4 |
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Answer» x^2 - 3x + 4 = x^2 - 4x + x - 4 = x(x - 4) + 1(x - 4) = (x + 1)(x + 4) |
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| 25. |
differentiate |
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Answer» what. g |
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| 26. |
differentiate |
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Answer» y= (√x)^y take log log y = y log√x differentiate both side wrtx 1/y. y' = y'log√x + 1/2√x. 1/√x .y 1/y. y'= y' log√x + 1/2x . y y'( 1/y - log √x) = y/2x y'= y/2x( 1/y - log √x) |
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| 27. |
(a) 64π cm3. The volume of a sphere is 38808 cubic cm. The curved surface area of the sphereis(a) 1386 sq. cm(b) 4158 sq. cm(c) 5544 sq. cm(d) 8316 sq. cm. |
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| 28. |
1.Find the capacity in litres of a conical vessel withradius 7 cm, slant height 25 cm (ii) height 12 cm, slant height 13 cm |
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| 29. |
In the given figure, AB is the diameter of the circle 38.with area Tt sq. units. Another circle is drawn withCas centre, which is on the given circle and passingthrough A and B. Find the area of the shaded region.в по(a) sq. units (b) sq. units(c) 1 sq. units (d) 1.2 sq. unitsure (not to scale) given below, G and 2os , and O2 |
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Answer» D) is the correct answer d) is the right answer of the following |
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| 30. |
If 1 m 39.37 inch, then conversion of1 sq cm in square inch is(a) 0.155 sq inch(b) 0.165 sq inch(c) 0.175 sq inch(d) 0.185 sq inch |
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Answer» Explanation : 1 m = 39.37 inch 1 sq cm = 0.0001 sq m = 0.0001 × 39.37 × 39.37 = 0.155 sq inch Answer : 0.155 sq inch If you find this answer helpful then like it. |
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| 31. |
28,The area formed by the coordinate axes and the straight line 2x + 3y-24-o s-a)Il sq. unit, b) 48 sq. unit,c) 12 sq unit, d) 10 sq. unit |
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| 32. |
The length of a side of a rhombus is 4.1 cm and one of its diagonals is 1.8cm long. Find the area of the rhombus.(1) 10.8 sq. cm(3) 7.2 sq. cm(2) 3.6 sq. cm(4) 8.1 sq. cm |
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| 33. |
11. OrangesTere bought ată8.50 per dozen and thetransport cost were 0.50 per dozen. At whatprice per hundred must these be sold so as to gain 12?2. A flask was sold ată72 incurring a loss of 100/ |
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| 34. |
ara prolit 01Z3%, Find what price did the deal e prSarita bought eggs at 8.40 a dozen. At what price per hundred must she sell them so as to earn a proft |
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Answer» Cost of a dozen eggs = 8.40 cost of 1 egg = 8.40/12 (since , 1 dozen = 12 eggs) => rs 0.7 cost of 100 eggs = 0.7 × 100 => rs 70 CP = rs 70gain % = 15% sp = (100+gain%)/100 × cp=> sp = (100+15)/100 × 70=> sp = 115/100 × 70=> sp = 115×7/10=> sp = rs 805/10=> sp = rs 80.5 thank you |
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| 35. |
6. Santa bought eggs at 8.40 a dozen. At what price per hundred must she sell them so as to earn aiprofit of 1 5% ? |
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| 36. |
Tick () the correct option.13. Oranges are bought at 7 for3. At what rate per hundred must they be sold to gain 33%?(a) 56(b) 60(c) R 57(d) 54 |
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| 37. |
If m α n and when m=154, n =7. Find the value of n, when n=14 |
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| 38. |
chased a table forthe table to have a profit of 16%?t What price per hundred must be seil them so as12 15 and spent? 35 on its transportation At what price should he sellAmarnan buys eggs at 5 for 6 rupees and sell th |
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| 39. |
i) given a= 2, d=8, S=90, find n and a,2) given a=8, an=62, S=210, find n and d.3) given an=4, d= 2, Sn=-14 find n and a-14, Iind n and |
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| 40. |
41 ^ { n } - 14 ^ { n } is multiple of 27 |
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| 41. |
a_{n}=4, d=2, S_{n}=-14, \text { find } n \text { and } a |
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| 42. |
n and when m-154, n-7. Find the value of m, when n-14 |
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Answer» Thanks |
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| 43. |
[1+\cot \theta-\sec (\theta+\pi / 2)][1+\cot \theta+\sec (\theta+\pi / 2)]=2 \cot |
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| 44. |
5740=7*n %2B 14*(n/2) - 7 |
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Answer» 5740 = n/2 * 14 + 7n - 7 7n + 7n - 7 = 5740 7(n + n - 1) = 5740 2n - 1 = 5740/7 2n = 820 + 1 n = 821/2 n = 410.5 |
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| 45. |
14. Show that n2 + n+ 1 is not divisible by 5 for any n, where n is a natural number. |
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Answer» Any natural number it's " n = 5k n = 5k±1 n = 5k±2 where k natural number k Case n = 5k then n^2+n+1 = 25k^2+5k+1 = 5k(k+1)+1 then not divisible by 5 (remainder 1) CAse n = 5k±1 then n^2+n+1 = 25k^2 ± 10k+1 + 5k±1+1 = 5k(5k±1) +2±1 then not divisible by 5 (remainder 3 or 1) CAse n = 5k±2 n^2+n+1 = 25k^2 ± 10k+4 + 5k±2+1 = 5k(5k±1+1) ± 2 then not divisible by 5 (remainder 2 or 3) Then n^2+n+1 not divisible by 5 |
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| 46. |
9. If S.D. of 1, 2, 3,n be sqrt 14, find n |
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| 47. |
x tan 4x1 - 005 42 g เคนเคฟ45. (i) lim |
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Answer» If we put x=0 we will get 0/0 form so using L'hospital rule lim x->0 (tanx + xsecx*secx)/(4sin4x) If we put x=0 we will get 0/0 form so using L'hospital rule lim x->0 (secx*secx+secx*secx+2xsecx*secx*tanx)/(16cos4x) = (1+1)/(16) = 2/16 = 1/8 If you find this answer helpful then like it. |
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| 48. |
Solve: Secâx= 1 + tanx |
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| 49. |
1 + tan2 A(1- tan A1 +cot A 1 cot A= tan-A |
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| 50. |
1-=0Xतब सिद्ध करो कि (1तब सिद्ध करो कि (1-2)1)32. यदि ==१ ।32. यदि 1 =dx1+(UP 1995)mint to. Se |
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