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1-cos χ-1V1+ cos x |
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Answer» 1+cosx=2cos^2(x/2)1-cosx=2sin^2(x/2)tan^-1(root(2sin^2(x/2)/2cos^2(x/2)))=tan^-1(root(tan^2(x/2))) ( now 0<x<pie so 0<x/2<pie/2so x/2 is in first quadrant so root(tan^2(x/2))=tan(x/2) ) =tan^-1(tan(x/2))=x/2 |
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