1.

x tan 4x1 - 005 42 g เคนเคฟ45. (i) lim

Answer»

If we put x=0 we will get 0/0 form so using L'hospital rule lim x->0 (tanx + xsecx*secx)/(4sin4x) If we put x=0 we will get 0/0 form so using L'hospital rule lim x->0 (secx*secx+secx*secx+2xsecx*secx*tanx)/(16cos4x) = (1+1)/(16) = 2/16 = 1/8

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