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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Example 8.22A cup is in the form of a hemisphere surmounted by a cylinder. The height of thecylindrical portion is 8 cm and the total height of the cup is 11.5 cm. Find the total surfaarea of the cup. ( Take π 22 ) |
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Answer» Like my answer if you find it useful! |
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| 2. |
A solid cylinder of radius 6 cm & height 15 cm is melted & recast into 12 toys in the shape of right circular cone mounted on hemisphere. Find the radius of hemisphere & the total height of toy if the total height of conical part is thrice it's radius . |
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Answer» r=6cm h=15cm volume of cylinder= volume of 12 toys volume of cylinder=pi r^2h volume of 12 toys=12(1/3pi r^2h+2/3pi r^3) since h=3r therefore pi r^2h=12(1/3pi 3r^3+ 2/3pi r^3) pi r^2h=12(5pi r^3)/3 pi cancels out r^2h=4x5r^3 36x15=20r^3 r^3=27 r=3 the radius of sphere and cone is 3cm |
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| 3. |
12. Building is in the form of a cylinder surmounted by a hemispherical vaulted dome and contains 41 19 m of air. If the intenidiameter of the building is equal to its total height above the floor, find the height of the building.21odalwhich is in the form of a cylinder with hemisnhericalends The total height of the |
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| 4. |
A cup is in the form of a hemisphere surmounted by a cylinder. The height of thecylindrical portion is 8 cm and the total height of the cup is 11.5 cm, find the totalsurface area of the cup. |
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| 5. |
A tert des culind(vical to a height oke18rn and conical about 9t. The YadiustHhe cone m an total heightthe tont i na find the canvas undtos the tent ua d |
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Answer» Canvas required = CSA of cone+ CSA of cylindercsa of coneis 22/7 ×r ×lcsa of cyl. is 2× 22/7× r× h h of cone = 10.8 - 4.8l=√(4.5)²+(6 )²= 7.5canvas used= 22/7× 4.5×7.5 + 2×22/7× 4.5× 4.8 =742.5/7 + 950.4/7 =106.07 + 135.77 = 241.84 cm² |
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| 6. |
1 1e — L a1L4y 4y Tarat ey |
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| 7. |
2७४ ey e (1) 22 ¥ |
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| 8. |
spare root of 25 |
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Answer» √(25)=√(5*5)=5 |
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| 9. |
“गा भी ल 08 हि +1 ‘1 kalt )—-‘«0(1 (RABUR T ey L |
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| 10. |
33. From the top of a building AB,60 m high, the angles of depression of thetop and bottom of a vertical lamp post CD are observed to be 30° and60° respectively. Find(i) the horizontal distance between AB and CD,(ii) the height of the lamp post,(ii) the difference between the heights of the building and the lamp[CBSE 2009]post. |
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| 11. |
2 g B 1\ Aही | ey 12Sl |
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| 12. |
EY. 1.18.Evaluate (1/3-( - 2 ) + ( 553 + 30) |
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Answer» (4/3-(-3/2)) + (-5/3×3/30)+(-12/4 × -27/16)= =(4/3+3/2)+(-6)+(-12(4)+(-27)/16)= =(2/1)+((-3)-6+(-48+(-27)/16==-6-6+26/16=-12(16)+26/16=192+26/16= 218/16=109/8=13.625 |
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| 13. |
सन, ,1 0 20e A cot’0)2० ey |
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| 14. |
By selling an almirah for 10,500, a man loses of its cost price. Find its cost price.6се |
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Answer» Let almirah cost price be xAlmirah sold at Rupees = Rs.10500Loss = 1/6xselling price = cost price - loss10500 = x - 1/6x10500 = x-x/610500 = 5x/610500 * 6/5 = xx = 12600 CP = Rs.12600 |
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| 15. |
8. Atent is cylindrical to a height of 4.8 m. and conical above it. The radius of the4.5m. and total height of the tent is 10.8 m. Find the canvas required for the tent inmeters. |
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Answer» canvas required = CSA of cone+ CSA of cylindercsa of coneis 22/7 ×r ×lcsa of cyl. is 2× 22/7× r× h h of cone = 10.8 - 4.8l=√(4.5)²+(6 )²= 7.5canvas used= 22/7× 4.5×7.5 + 2×22/7× 4.5× 4.8 =742.5/7 + 950.4/7 =106.07 + 135.77 = 241.84 cm² 241.84 centimetre square is the right answer 241.84 is my answer to that question |
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| 16. |
tent is cylindrical to a height of 4.8 m. and conical above it. The radius of the base is4.5m. and total height of the tehtis 10.8 m. Find the canvas required for the tent in squatremeters. |
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| 17. |
ihe uiameter of a closed cylinder is 21 cm and height is 10 cm. Find the total surface area oIf the ratio of radii of two cylinders of equal height is 1 :3, find the ratioFind the height of a cylinder hohr rncm and height is 10 cm. Find the total surface area of the cylinder.of their curved surface areas. |
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| 18. |
A shopkeeper sells a lamp for? 350 and gainsprice.6th of its cost price. Find its cost |
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| 19. |
with the following frequencies of differentcoins are tossed simultaneously 200 tiines with the followoutcomes.Compute theDutcomes 3 heads2 headsprobability1 headFrequencyof23727728coming up: (i) 2 heads (ii) At least 2 heads(iii) 2 tails (iv) 3 tailsSection |
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Answer» 36 g water |
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| 20. |
playground, mu uTwenty cylindrical pillars of the Parliament House are to be cleaned. If theeach pillar is 0.50 m and height is 4 m. What will be the cost of cleaning them atof Rs 2.50 per square metre?ihtu uie LONCERT |
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| 21. |
1. Construct the following quadrilaterals.(1) Quadrilateral DEARDE = 4 cmEA=5 cmAR=4.5 cmZE = 60°ZA=90° |
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Answer» (1)A rough sketch of this quadrilateral can be drawn as follows. (2) Draw a line segment DE of 4 cm and an angle of 60º at point E. As vertex A is 5 cm away from vertex E, cut a line segment EA of 5 cm from this ray. (3) Again draw an angle of 90º at point A. As vertex R is 4.5 cm away from vertex A, cut a line segment RA of 4.5 cm from this ray. (4) Join D to R. DEAR is the required quadrilateral |
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| 22. |
r sec, easin ) (1-sin θ)-k. then find the value of k.(01) |
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Answer» thanks |
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| 23. |
५ 100 m के दीड को 4 के 36 sec से 5 5 3 45se८से पूरा किया इस दोड 4 3 8 को कता ?- 249] 20 m 8] 25m ] 22 5m 279) |
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Answer» answer do was the right answer Time duration by which B defeated by A = 45-36 = 9 Sex length B defeated by A = ( 100/36 ) 9 = 25 metre ANS a) is the correct answer a. ). 20. is the right answer a) 20 is the correct answer |
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| 24. |
पा 3 झुक(0. 2पैसरा ** १ - EE13 |
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Answer» Tanx= tan 30° = π/6now we know thattan is positive in 3 rd quadrantsoπ+π/6= 7π/6 |
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| 25. |
ee, thens4-eIf xdx |
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| 26. |
36. A ABCHi DE AB, EE ACADE BC . a, |
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Answer» please give question in English. |
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| 27. |
Find the co-ordinates of mid point of line segment joining two points for the following(i) (5,4) and (3,-4) (ii) (6,0) and (0,7) |
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Answer» mid point of line segment joining points (x1 , y1) and (x2 , y2) isx=(x1+x2)/2y=(y1+y2)/2i)x=(5+3)/2=4y=(4+(-4))/2=0mid point is (4,0)ii)x=(6+0)/2=3y=(0+7)/2=3.5mid point is (3,3.5) |
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| 28. |
Write each ratio in its simplest form(i) 3.75 kg to 75 g(ii) 90 cm to 1.5 m(iii) 36 minutes to an hour(iv)125 ml to 2 l(v)60 paise to4 |
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Answer» 375/75=5/190/1.5=900/15=60/136/60=6/10=3/5125/2000=1/860/400=6/40=3/20 |
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| 29. |
36. The speed of a motor boat in still water is 15 km/hour. If it goes down thestream 30km and again returns to the starting point in a total time of 4 hours and30 minutes. Find the speed of the stream. |
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Answer» Let the speed of the stream be x km/hr. Then, Speed downstream = (15 + x) km/hr,Speed upstream = (15 - x) km/hr.Therefore,30/(15+x) + 30/(15-x) = 4(1/2)=> 900/(225-x^2) = 9/2=> 9x^2 = 225=> x^2 = 25=> x = 5 |
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| 30. |
2m2 =5m-5 |
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Answer» This equation has no real roots |
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| 31. |
g. 4.142, if AB丄BC, DC丄BC and DE丄AC, prove that Δ CED~ Δ ABC.Fig. 4.142 |
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| 32. |
34 के बीच बश्शेरee |
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| 33. |
Find the distance between the points(at12° 2 at) and B (at22, 2 at2) (ii) L (a cos α, a sin α) and M (a cos β, a |
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Answer» The distance between the points can be calculated by distance formula, root[(x2-x1)^2+ (y2-y1)^2] =root[(at^22-at^21)^2+ (2at2-2at1)^2] =root[a^2(t^22-t^21)^2+ 4a^2(t2-t1)^2] =root[a^2(t2-t1)^2(t2+t1)^2+ 4a^2(t2-t1)^2] =root[(t2-t1)^2{a^2(t2+t1)^2+ 4a^2}] a(t2-t1)root ((t2+t1)2+ 4) |
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| 34. |
at Wlhat should eeSimplify |
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Answer» thanks |
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| 35. |
2. Find the equation of line which passes through the following two points:() (at,2.2at).(at2 .2at2,(i)(a, b), (a + r cos a, br sin a). |
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| 36. |
what is the full form of hp |
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Answer» Ans :- Hewlett Packard |
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| 37. |
nd the eighteenth tcam af hP 17,3, 14 |
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| 38. |
machines would be required to produce the same number or artic es m7 taps of the same size fill a tank in 1 hour 36 minutes. How long will 8 taps of the sumetake to fill the tank? |
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| 39. |
the baby walked.the mother walked along |
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Answer» The baby walked along with the mother. If you find this answer helpful then like it. really thanks |
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| 40. |
combined this yarrThe baby walked.The mother walked along |
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Answer» The baby walked along with the mother. If you find this answer helpful then like it. tq |
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| 41. |
14. The area of a square field is 60025 m². A man cycles along its boundary at 18 km/h. In how much time will hereturn to the starting point? |
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| 42. |
A factory requires 13 machines to produce 1000 articles in 54 days. How many machines canproduce the same number of articles in 39 days? |
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| 43. |
The area of a square field is 60025 m2. A man cycles along its boundary at 18 km/. In howmuch time will he return to the starting point?me. |
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| 44. |
The area of a square field is 60025 m2. A man cycles along its boundary at 18 km/h. In howmuch time will he return to the starting point.19, |
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Answer» answer bhi bhej de bhaai |
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| 45. |
19. The area of a square field is 60025 m2. A man cycles along its boundary at 18 km/h. In howmuch time will he return to the starting point? |
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Answer» Thanks |
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| 46. |
paurabh has enough money to buy 72 machines worth 200 each. How manymachines can be bought with 'same amount of money, if he gets a discount of20% on each machine ? |
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| 47. |
8. A factory requires 42 machines to produce a given number of articles in 56 days. How manymachines would be required to produce the same number of articles in 48 days? |
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| 48. |
16. Saurabh has enough money to buy 72 machines worth 200 each. How manymachines can be bought with same amount of money, if he gets a discount of20% on each machine ? |
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| 49. |
Jyoti walked along the entire boundary of a square field, with each sideequal to 80 m. How much distance did she cover? |
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Answer» she covered the exact distance equal to the perimeter of the square fieldso distance covered will be 4*80m320m |
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| 50. |
a Five machines, when operated for 9 hours each day, can harvest a farm in 16 days. Hownsame farm, if each machine is now operateddays whours each day?ould 8 machines take to harvest thefor i |
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Answer» M * D * H =const M = Machine D = Days H = Hours so, 5 * 16 * 9 = 8 * D * 10 80 * D = 720 D = 9 so it takes 9 days |
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