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A tert des culind(vical to a height oke18rn and conical about 9t. The YadiustHhe cone m an total heightthe tont i na find the canvas undtos the tent ua d |
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Answer» Canvas required = CSA of cone+ CSA of cylindercsa of coneis 22/7 ×r ×lcsa of cyl. is 2× 22/7× r× h h of cone = 10.8 - 4.8l=√(4.5)²+(6 )²= 7.5canvas used= 22/7× 4.5×7.5 + 2×22/7× 4.5× 4.8 =742.5/7 + 950.4/7 =106.07 + 135.77 = 241.84 cm² |
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