This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
9 Using Euclid's division algorithm, find whether the pair of numbers 847, 2160 areco primes or not. |
|
Answer» a=2160,b=847By Euclid's lemma,a=bq+r, 0≤r<b 2160=847×2+466847=466×1+381466=381×1+85381=85×4+4185=41×2+341=3×13+23=2×1+12=1×2+0As1 is the HCF of 847 and 216.847 and 2160 are the co-primes |
|
| 2. |
Ifan article is sold for Rs. p, there is a loss of 15%. If however, the same article is sold for Rs. q, there is a profitof 15% then the ratio (q-p) : ( q + p) is:(a) 20: 23(b) 20:3(c) 3:20(d) 17: 23 |
|
Answer» suppose C.P. of article is xso p=0.85x and q=1.15x(q-p):(q+p)=(1.15-0.85):(1.15+0.85)=0.3:2=3:20 |
|
| 3. |
4. Use Euclid's division algorithm to find whether the pair of numbers 847 and 2160 are co-primeor not |
| Answer» | |
| 4. |
Find the smallest number by which the following numbers should be multiplied to get a perfectsquare. Also find the square root of the square number obtained.(a) 2925 (b) 847 (c) 4802 (d) 15488 (e) 2028() 768 |
| Answer» | |
| 5. |
oles ot height a metres and b metresre p metres apart. Prove that the heighthe point of intersection of the linesthe top of each pole to the foot ofosite pole is given by aabmetres.a + b |
|
Answer» Please don't post same question again and again. |
|
| 6. |
12. Two poles of height a metres and b metresare p metres apart. Prove that the heightof the point of intersection of the linesjoining the top of each pole to the foot ofthe opposite pole is given bymetres.a + b |
| Answer» | |
| 7. |
(2) Two poles of height a metres and b metres areP metres apart. Prove that the height h of thethepoint of intersection N of the lines joiningtop of each pole to the foot of the opposite poaba +bSmetres |
|
Answer» 2 3 Thanks |
|
| 8. |
12. Two poles of height a metres and b metresare p metres apart. Prove that the heightof the point of intersection of the linesjoining the top of each pole to the foot ofabthe opposite pole is given bymetres.a+bes[CBSE-11-560061] |
| Answer» | |
| 9. |
orem-15.4: The sum of three interior angles of a triangle is 180° |
|
Answer» FROMΔ ABCdraw aparallel line DE ║BC∠DAB +∠BAC +∠CAE = 180∠DAB =∠ABC (ALTERNATE ANGLES ARE EQUAL)∠CAE =∠ACB (ALTERNATE ANGLES ARE EQUAL)SO,∠ABC +∠ACB +∠BAC =180 |
|
| 10. |
on idy 6(b) s%(c)6%A,218, Aman sold two chairs for? 500 each. On one he gains 20% and on the other he(d) 2% lossHis net sgain or loss per cent is(a) 1.5% gain(b)2% gain(c)-1.5% loss |
| Answer» | |
| 11. |
42cmsides of a triangle are in the ratio of 12: 17:25 and its perimeter is 540cm. Find its area.u trianelt has perimeter 30 cm and each of the equal sides is 12 cm. Find |
| Answer» | |
| 12. |
youcanstoreintheEpleses,(iuWaterThe curved surface area ofthe cylinder is 1760 cm.2 and its volume is 12320 cm3,Fits hÄight.11. |
|
Answer» curved surface area of cylinder = 1760 cm² &volume of cylinder = 12320 cm³ we have to find:height of cylinder= ?. solution:-we know that ;curved surface area of cylinder = 2πrh &volume of cylinder = πr²h here,according to given;C.S.Area = 1760 => 2πrh = 1760 => πrh = 1760 / 2 = 880 andvolume = 12320 => πr²h = 12320 => πrh × r = 12320 => 880 × r = 12320 => r = 12320 / 880 => r = 14 cm now, putting the value of 'r' in 2πrh = 1760 => 2π × 14 × h = 1760 => h = 1760 / 28π => h = ( 1760 / 28 ) ×( 7/22 ) => h = 12320 / 616 => h = 20 cm Answer thank u |
|
| 13. |
The length of the minule hand of wall tA wire, in the shape of a square of side 1 1 em, is cut and rebent in the form of a circle. Find the area ensby the circular wire.isis 108 cm, then find the diameter of the protractor |
|
Answer» Perimeter of square=circumference of circle perimeter of square=side×4 =11×4 =44cm therefore circumference of the circle will also be 44cm 2πr=44cm 2×22/7×r=44cm 44/7×r=44cm r=44/1×7/44 r=7cm area of the circle=πr² =22/7×7×7 =22×7 =154cm² |
|
| 14. |
→"Nar isthe day on15 $plomber-1998. |
|
Answer» the day on the 15September 1998 was tuesday The day is Tuesday on that date. Tuesday on the day of 15 september 1998 explain in step |
|
| 15. |
2x-3 y in the form of ax + by +c 0 andfindthevalueofabrassion ofthe volume of a cylinder whose radius and height have |
| Answer» | |
| 16. |
Find the radius ofthe sphereif its volume is 904.32 cubic an(-3.14)3) Find the value of: cos 60x cos 30+sin 60'x sin 30 |
|
Answer» cos60cos30+sin60sin30=1/2*√3/2+1/2*√3/2=√3/4+√3/4=2√3/4=√3/2 |
|
| 17. |
12. The diameter of a wheel is 28 cm. How many revolutions will it make to travenar minute Find its speed in m/se |
|
Answer» where is the answere |
|
| 18. |
॥ चक्रवृद्धि ब्याज पर दिया गया कोई धन 2 वर्ष में 8820 रु० तथा 3 वर्ष में 9261 ९० हो जाता है. दरप्रतिशत तथा मूलधन ज्ञात कीजिए.।11।।।।।।nar001 |
|
Answer» ok wait some days This is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spamThis is spam 8000 is the right answer my camera is not running i am going to post the image of solution |
|
| 19. |
3. if p =-2, q=-1 and r=3,(i) p2 +q -r23 nar |
| Answer» | |
| 20. |
) If sec θ2 where θ is the measure of an acute positive angle , then |
| Answer» | |
| 21. |
o tan 23° tan 42° tan 67° = 1e N ही |
|
Answer» tan48*tan23*tan42*tan67 tan48 = tan(90-42) = cot42 tan23 = tan(80-67) = cot67 cot42*cot67*tan42*tan67 = 1*1 = 1 |
|
| 22. |
Find the area of a triangle two sides of which are 1 8cm and 10cm and the perimeter is42cm |
| Answer» | |
| 23. |
Construct a right-angle triangled whose perimeter isequal to 10 cm and one acute angle is 6015. |
| Answer» | |
| 24. |
Find the area of a triangle two sides of which are 1 8cm and 10cm and the perimeter is42cm4 |
| Answer» | |
| 25. |
Chapter 3 Understanding Quadrilateralsslovlig Home weißThe three interior angles of a quadrilateral measure 1289, 88° and 94. Find the fourth angle. |
|
Answer» the sum of interior angle is 360 128+88+94=310 360-310=50 sum of interior angle is 360, 128+88+94= 3 10; 360-310=50 let the fourth angle be-xthen, sum of all Angeles of a quadrilateral =360x+128+88+94=360x+310=360x=360-310x=50° |
|
| 26. |
d the area of a triangle two sides of which are 18cm and 10cm and the perimeter is42cmrimeteris 540cm Find its area. |
| Answer» | |
| 27. |
find the area of area of the triangle whose sides are 42cm ,34cm and 20cm in length. Hence find the height corresponding to the longest side |
| Answer» | |
| 28. |
Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is42cm |
|
Answer» thanks |
|
| 29. |
Prove that the sum of all three interior angles of a triangle is 180. |
|
Answer» I am winner winner winner winner |
|
| 30. |
The smallest angle 36°PLE 4. The sum of seven interior angles of anis 1000. Find the eighth angle.dagon ishe interior angles of an octagon |
| Answer» | |
| 31. |
Find the area of squares (in cm2) whose diagonals are of the following lengths:a 12 cmb 2.5 mc 0.18 dm(Hint: 1 m= 100 cm, 1 dm= 10 cm) |
| Answer» | |
| 32. |
If the radius ofthe cylinder is halved, then what is the change in its volume? |
|
Answer» बेलन। कायतान=πr^2hत्रिज्या आधी करने पर= π(r^2)/4h= 1/4(πr^2h)आयतन एक चौथाई रह जाएगाthanksplease like the solution 👍 ✔️👍 |
|
| 33. |
1. In the given figure, ABCD is a cyclicDquadrilateral whose diagonals intersect at Psuch that DBC = 60° and <BAC = 40°Find(i) <BCD,(ii) LCAD.40°60° |
| Answer» | |
| 34. |
Two cubes each of side 6cm are joined together. Name the new solid formed. Also find thevolume of new solid formed. |
|
Answer» New solid formed will be cuboid have length= (6+6)cm = 12 cm , breadth = 6m and height = 6m now volume of new solid = 2*(volume of cube) = 2*(6)³ = 216×2 = 432cm³ |
|
| 35. |
A large right circular cone is made out of a solid cube edge 9 cm. Find thevolume of the remaining solid.SECTION_D |
|
Answer» volume of cube=(9)^3 = 729 cm^3diameter of cone= 9r=9/2, h=9vol of cone=1/3π(9/2)^2×9remening vol=vol of cube - vol of cone=9×9×9-1/3×22/7(9/2)^9pls calculate |
|
| 36. |
If one acute angle of a right triangle is half of the other, find the measure of both the acuteangles |
| Answer» | |
| 37. |
3. One of the acute angles of a right triangle is 58e. Find the other acute angle |
| Answer» | |
| 38. |
(0 is a positive acute angle)W.B.M. 1962(a) Of the two acute angles the sine of one is equal to the cosine of the| |aifA+other. Find the sum of the two angles. |
|
Answer» The sine of an angle and the cosine of its complement are equal. 15º and 75º are complementary.sin(75º) = cos(15º) = 0.97cos(75º) = sin(15º) = 0.26 |
|
| 39. |
OrA building is in the form of a cylinder surmounted bya hemispherical dome (see figure). The base diameterof the dome is equal to 2 of the total height of thebuilding. Find the height of the building, if it contains67 1 m2 of air.321 |
| Answer» | |
| 40. |
determuhe thhe Dasell Preeti is painting the walls and ceiling of a hall whose dimenstions are 18 m x 15m x5m.From each can of paint 120 m2 of area is painted. How many cans of paint she needto paint the hall?m am r 14 m is rolled to form a cylinder of height 14 |
|
Answer» Area of walls and ceiling= 2lh + 2bh + lb= 2*18*5 + 2*15*5 + 18*15= 600 m²Number of cans = 600/120 = 5 Please hit the like button below if this helped you out |
|
| 41. |
On seling an exhaust fan forof the fa7350, a man gains 6 of its cost price. Find the cost price17, |
| Answer» | |
| 42. |
13-calculate all other trigonometric ratios.5.Given sec θ12 |
|
Answer» thanks |
|
| 43. |
1. If the perimeter of a semi-circular protractor is 36 cm, the its diameter is:(b) 12 cm(c) 14 cm(d) 15 cm.(a) 10 cm |
|
Answer» correct answer |
|
| 44. |
two side of a triangle are 12 cm and 14 cm the perimeter of the triangle is 36 cm what is its third side? |
| Answer» | |
| 45. |
ne 1 mibis whose diagonals are of lengths 8 cm and o el12. The area of a rhombus is 384 cm and one of its diagonals is 32 cm. Find its perimeter. 213. Find the area of a rhombus in which each side is 12 cm and height is 7.5 cmoTn |
| Answer» | |
| 46. |
(0 (प 2Xf+m-—nm+nf X ( z )n—rf—m 2 ( m )1 |
|
Answer» 1 2 |
|
| 47. |
IVi)ii)m3Add the following:unQuidandloSubtact : |
|
Answer» option b is the correct answer |
|
| 48. |
4. Simplity :XNEUNn |
|
Answer» a.)= 16/75 and e.)= 92/5 |
|
| 49. |
BUSbayo4 AB, 2 dop 12+%HomemGif ani besesVenfily that a(1) bu lo(11) Arbic bycia claraUn arbicarb) tcars]Find the produts10 q x262) 7-5CDC 642X C-63 46-3941) |
|
Answer» 1:A×b=b/a 1*1=1/1 1=12: a*b*c=b*c*a=c*a*b1*1*2=1*2*1=2*1*1 2=2=24 3: a*b+c=(a* b) +ca*c1*1+2=(1*1)+2a*21+2=1+2a*23-1=2a*22=2a*22a=2/22a=1a=1/2 |
|
| 50. |
Aman sold two cycles for 3000 each, gaining 20% on one and losing 20% onthe other. Find his gain or loss percentage on the whole transaction? |
|
Answer» give answer Gain = Rs.600selling price with 20% gain = Rs.3600 loss = Rs.720selling price with 20% loss = Rs.2880 cost price> selling priceloss = cost price - selling price = Rs.3000 - Rs.2880 = Rs.120loss% = 120/3000*100 = 4%he sold sold his cycle with 4% loss. |
|