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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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IRT |
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| 2. |
(a2 + b2)(-a2 + b2) |
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Answer» PLEASE LIKE THE SOLUTION |
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| 3. |
of calculators is not permitted.lators is not permitted,. our maihis cachSECTION-AFind the co-ordinate on X - axis where the abscissa is double than the irtDraw and define minor sector, |
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Answer» Abscissa means the x coordinate andordinatemeans the y coordinate. Here the abscissa is givenx= 2y1,2)(2,4) |
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| 4. |
Which is the first order lever?a) Coal tongsc) A wheel barrowb) A nut crackerd) A pair of scissorsWhat is the formula for volume of solid sphere?a)444 |
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Answer» Volume of cube=(4/3)πr³ |
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सोडवलनेली उदाहरणेaउदा (1) जर 2 - 2 तर 27 7* _ हे गुणोत्तर काढा.b 3 7b |
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Answer» Given a/b = 5/3 Then,(a + 7b)/7bDivide numerator and denominator by 'b'= (a/b + 7)/7= (5/3 + 7)/7= (5 + 21)/21= 26/21 |
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| 6. |
CtaJb) |
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Answer» from the equation. (a/b)^(x-1) = (a/b)^(x-3) so, x-1 = x-3 => 1=3..... ( which is not true..) so, no solution for x. |
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| 7. |
55 4013CT |
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Answer» Let 1/(x+y) = a and 1/(x-y) = b=> 44a + 30b = 10 and 55a + 40b = 13Solving, a = (10*40 - 13*30)/(44*40 - 55*30) = 10/110 = 1/11and b = (10 - 44/11)/30 = 1/5 => 1/(x+y) = 1/11 and 1/(x-y) = 1/5=> x + y = 11 and x - y = 5Adding 2x = 16 => x = 8 and y = 11 - 8 = 3 Answer:x = 8 and y = 3. |
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| 8. |
6a(a - 2b) +5b(a -2b) |
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| 9. |
theCt2 |
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Answer» correction in the second one ax²y+bxy²+cxyz = xy( ax+by+cz) |
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| 10. |
Looooo00eCT1-9997 |
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| 11. |
Solve CT/4log(1 + tanx) dx |
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Answer» Please like the solution thanks sir |
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| 12. |
8+7b+4(b =3) |
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Answer» b=3hence, put b value in equation8+7b+48+7(3)+48+21+412+2133 ans. |
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| 13. |
3. Simplify the following combining lilk(i) 21b -32 +7b - 20b |
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Answer» 21b - 32 +7b -20b= b(21+7-20) - 32= 8b - 32= 8(b-4)Please hit the like button if this helped you |
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| 14. |
32-32 |
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Answer» simple 32-32 =0 is the answer.... |
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| 15. |
What is the formula for (ar- b)2?a) a2 -b-2abc) a2 + b2-2abb) a? b+2abd)a2 + b2 + 2absthe first order lever? |
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Answer» (a-b)²= a²+b²-2ab |
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| 16. |
The ratio 2loBy4a-310927(a2,1)3- 2asimplifies to74log49a-a-1(A) a2-a-1(B) a2 + a-1(C) a2 _ a + 1(D) a + a + 1 |
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in θ(1 --a2 , 12, find the values of all T-ratiosa2-b2 |
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The length of the shortest chord of the circles x' + y2 + 2gx + 2fy + c = 0 which passes through thepoint (a, b) inside the circle is(A) 2(a2 +b+ 2ga + 2fb +c)12(C) [-2(a2 +b+ 2ga + 2fb +c)]2(B) 2 [-(a2 +b2+2ga +2fb +c)]'2(D) 2 [-(a2 + b2 + 2ga + 2fb-c)]1/21/2 |
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| 19. |
l+ a lb2 +c2 a22h2 c2+ a2INCERTI 9. |
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| 20. |
(+1)(n+2)]16.1.2 + 2.3 + 3.4+...+(2+1) = |
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| 21. |
If one zero of a polynomial \left(a^{2}+9\right) x^{2}+13 x+6a is reciprocal of the other, find the value of 'a'. |
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| 22. |
bx+ay=a-6b3(ax-by)= -(6a+b)find the value of x and y |
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| 23. |
2COOLCOOLILU.20.If one zero of p(x) = (a +9) x + 45x + 6a is the reciprocal of the other. Find thevalue of a |
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Answer» (a^2+3)x^2+45x+60,; let €+1/€, 1/6a/a^2+9;;a^2+6a+9==a^2+3a+3a+9=a(a+3)+3(a+3); (a+3)(a+3);,la=3,3 |
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| 24. |
,ufirlf a2 + b2 st 3ab, show thatog6lags+ logb)Ciy If a2 b2 7ab, prove that |
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| 25. |
4 then find the value of the ratio 3a2-7b2A+7b332. If3a+7b |
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| 26. |
(Ba+7b): | |
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| 27. |
(3a-7b-c)^2 |
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Answer» (3a-7b-c)(3a-7b-c) = 9a*a+49b*b+c*c-42ab+14bc-6ac |
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| 28. |
21b - 32 + 7b - 20b |
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Answer» 21b - 32 + 7b - 20b = 21b + 7b - 20b - 32 = 8b - 32 = 8(b - 4) |
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| 29. |
pefficients in eachEXERCISE 2.4 (Optional)*1. Verify that the numbers given alongside of the cubic polynomialsAlso verify the relationship between the zeroes and the coefficie(ii) x - 4x2 + 5x - 2; 2,1.1© 2x+x2–5x+2; -1, -2 |
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Answer» 2^3+x^2-5x+2=0; 2(1/2)^3+(1/2)^2-5(1/2)+2= 2(1/8)+(1/4)-(5/2)+2= (1/4)+(1/4)-10/2+2= 1/4 +1/4-10/2+2= 1+1-20+4/4=6-20/4=-14/4=-7/2; 2x^3+x^2-5x+2; in (1); 2(1)^3+(1)^2-5(1)+2 =2+1-5+2==0 2x^3+x^2-5x+2 in (-2); =2(-2)^3+(-2)^2-5(-2)+2; =2(-8)+(4)+10+2=-16+16=0 |
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| 30. |
iI2A+ 7B |
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Answer» 2A + 7B = 14........(1)6A + 3B = 18........(2)from equation (2),2A = 6 - Bput in equation (1)6 - B + 7B = 146B = 8B = 4/3then A = 7/3 |
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| 31. |
2 1 116. IfA-1-1 2-11-1 2Verify that A'-6A + 9A-41 = O and hence find A-1 |
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Answer» 👍👍👍 |
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| 32. |
9. If A-30°, verify that cos 2 A a -1-21- tan2 A1+tan2 A2sin A. |
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| 33. |
2 16-0 - ) - 6 +3) 6-).12+Example 9: Compute (4.5) - (1.5)Solution: We have) = (4.5+1.5)(4.5-1.5)= 6 x 3 =18Exercise 4.11. Resolve in to factors:(i) x + xy (ii) 3x – 6x (iii) (1.6)a- (0.8) a (iv) 5-10m - 20n2. Factorise:(i) a +ax +ab + bx (ii)3ac +7bc-3ad – 7bd (iii) 3xy - 6zy - 3xt +6zt(iv) y° - 3y +2y- 6- xy +3x3. Factorise:(i) 4a - 25 () x'- 16 (ii) x'-y civil?lo) - (2tb) (w) (0.7) - (0| (vi) (5a - 2b)-(2a - b)torisation of trinomialsinomials of the |
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Answer» 1) ii) 2) IV3) iii is the correct answer 4a^2 - 25= (2a)^2 - (5)^2= (2a + 5)(2a - 5) |
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| 34. |
/lfgb=300 verify that(1) jan29-_2an021- tan0 |
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| 35. |
Two ..ca be supplementary |
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Answer» as sum of two right angle is supplementary , so right angle is one of possible answer in space. |
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| 36. |
Verify that-[(729)^(-5/3)]^-1/2={(729)^[(-5/3)*(-1/2)] |
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Answer» OK |
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| 37. |
(iii) The nth term or the(iv) The 11th term of the AP (5a -x), 6a, (7a + 2),... |
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Answer» a=5a−x d=6a−(5a−x)⟹a+x a11=a+10d=5a−x+10(a+a)=5a−x+10a+10x=15a+9x Ans=15a+9x |
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| 38. |
changes from 45 'to 30°.find the height of the tower. (4)(b) By increasing the speed of a car by 10km/h, the time of journey for a distance of 72 km is reducedby 36 minutes .Find the original sped of the car. (3) |
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Answer» Let the speed of the car be xtime taken to cover 36 km = 36/x hrATQ36/x - 36/(x+10) = 18/60(36(x+10) - 36x)/x(x+10) = 3/10(36x + 360 - 36x)/(x^2+ 10x) = 3/10360x10 = 3(x^2 + 10x)3x^2 + 30x = 36003x^2 + 30x - 3600= 0x^2 + 10x - 1200=0x^2 + 40x - 30x - 1200=0x(x+40) - 30(x+ 40)= 0(x-30)(x+40)=0we get 2 answersBut x=30 is the correct onetherefore the speed of the car is 30 km/hr |
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| 39. |
Choose the correct answ40 m/s in kilometre per hoa) 12072 km/hr in m/s isa) 25ity Education Manage |
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Answer» 40 m/s=40*3600/1000 km/h=144 km/h72 km/h=(72*1000)/3600 m/s=20 m/s 1) 40 m/s = 144 kmph2) 72 kmph = 20 m/s P . S - Hope you are studying in Sri Chaitanya school as I am also studying in the same school but different branch. |
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ĺwhich ofthe following are APs ? If they form an AP, find the common difference d andwoite three more terms.e d0 24.8.16..5 3 7 |
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| 41. |
The first term of a Pir-t. Thecommon difference is 6 E the lastderm is 293 find the number of terms.- |
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Answer» the number of n terms is 51 |
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| 42. |
sin 25° cotl5cos65° tan 75 tan 10° tan 40° tan 50° tan 80°2cos43° cosec47°17.EvaluateI RORS formeri hy P (22 5) 97.10. R(12,11) and s(3,24) is not a |
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Answer» hit like if you find it useful |
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| 43. |
mounted by a hollovwcylinder. The diameter of the hemisphere is 21 cm and the total heightof the vessel is 14.5 cm. Find its capacity. |
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(a) We may first multiply 4 and 2 to get 8 andthen multiply by 7 to get the total productas 56.(b) We may multiply 2 by 7 to get 14 and thenmultiply by 4 to get 56.Thus, (4 x 2) * 7 = 4 x (2 x 7). This canbe done for any three numbers. Expressthis property in a general way by usingvariables a, b and c. |
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| 45. |
4) The largest 4 digit n5) The largest 4 digitr4. Multiply by multiple:1) 50 x 40=3) 157 ~ 70=5. Multiply by multipl |
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Answer» answer is 2000 is correct 1)50×40=20002)157×70=10990 Answer is 1)20003)10990 |
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| 46. |
Multiply: |
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Answer» (3a² + 5ab + 7b²) × (7a + 2b) 21a³ + 6a²b + 35a²b + 10ab² + 49ab²+14b³ |
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| 47. |
How many terns cf the AP 3, 5,7,9,... must be added to get the sum 120? |
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Answer» we have to find n Sn = 120a= 3d= 2Sn = n/2+(2a+(n-1)d120=n/2(2*3+(n-1)2)240= n(6+2n-2)240= 6n+2n^2-2n240= 4n+2n^2120= 2n+n^2n^2+2n-120=0n^2+(12-10)n-120=0n^2+12n-10n-120=0n(n+12)-10(n+12)=0n=10and n= -12number of terms is 10 |
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| 48. |
x2 + 6x-45x-126 = 0x2-39x-126 = 0x2-42x + 3x _ 126-0ă â(r-42)(r+3)0x 42 or x3x=42T: Speed cannot be negative]nce,the original average speed is 42 km/h.24 The sum of four consecutive numbers in an A.P. is 32 and the ratio of the product of theirst and the last term to the product of two middle terms is 7: 15. Find the numbers. |
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Answer» Solution:-Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d)So, according to the question.a-3d + a - d + a + d + a + 3d = 324a = 32a = 32/4a = 8 ......(1)Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/1515(a² - 9d²) = 7(a² - d²)15a² - 135d² = 7a² - 7d²15a² - 7a² = 135d² - 7d²8a² = 128d²Putting the value of a = 8 in above we get.8(8)² = 128d²128d² = 512d² = 512/128d² = 4d = 2So, the four consecutive numbers are 8 - (3*2)8 - 6 = 28 - 2 = 68 + 2 = 108 + (3*2)8 + 6 = 14Four consecutive numbers are 2, 6, 10 and 14Answer please like the solution 👍 ✔️👍✔️ |
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| 49. |
(3) 10a 20. If S, denotes the sum to n terms of an A.P. whoseirst term is a and common difference is d, then3S 2 3Sn1S is equal ton +(2) -a(4) 2a |
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Answer» options are wrong answer is 6 |
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| 50. |
lenth= 4,breadth =2,find the area |
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Answer» area=l*b =4*2 =8 sq cm |
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