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55 4013CT |
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Answer» Let 1/(x+y) = a and 1/(x-y) = b=> 44a + 30b = 10 and 55a + 40b = 13Solving, a = (10*40 - 13*30)/(44*40 - 55*30) = 10/110 = 1/11and b = (10 - 44/11)/30 = 1/5 => 1/(x+y) = 1/11 and 1/(x-y) = 1/5=> x + y = 11 and x - y = 5Adding 2x = 16 => x = 8 and y = 11 - 8 = 3 Answer:x = 8 and y = 3. |
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