x2 + 6x-45x-126 = 0x2-39x-126 = 0x2-42x + 3x _ 126-0ăâ(r-42)

1.	x2 + 6x-45x-126 = 0x2-39x-126 = 0x2-42x + 3x _ 126-0ăâ(r-42)(r+3)0x 42 or x3x=42T: Speed cannot be negative]nce,the original average speed is 42 km/h.24 The sum of four consecutive numbers in an A.P. is 32 and the ratio of the product of theirst and the last term to the product of two middle terms is 7: 15. Find the numbers.
Answer» Solution:-Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d)So, according to the question.a-3d + a - d + a + d + a + 3d = 324a = 32a = 32/4a = 8 ......(1)Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/1515(a² - 9d²) = 7(a² - d²)15a² - 135d² = 7a² - 7d²15a² - 7a² = 135d² - 7d²8a² = 128d²Putting the value of a = 8 in above we get.8(8)² = 128d²128d² = 512d² = 512/128d² = 4d = 2So, the four consecutive numbers are 8 - (32)8 - 6 = 28 - 2 = 68 + 2 = 108 + (32)8 + 6 = 14Four consecutive numbers are 2, 6, 10 and 14Answer please like the solution 👍 ✔️👍✔️

x2 + 6x-45x-126 = 0x2-39x-126 = 0x2-42x + 3x _ 126-0ăâ(r-42)(r+3)0x 42 or x3x=42T: Speed cannot be negative]nce,the original average speed is 42 km/h.24 The sum of four consecutive numbers in an A.P. is 32 and the ratio of the product of theirst and the last term to the product of two middle terms is 7: 15. Find the numbers.

Answer»

Solution:-Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d)So, according to the question.a-3d + a - d + a + d + a + 3d = 324a = 32a = 32/4a = 8 ......(1)Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/1515(a² - 9d²) = 7(a² - d²)15a² - 135d² = 7a² - 7d²15a² - 7a² = 135d² - 7d²8a² = 128d²Putting the value of a = 8 in above we get.8(8)² = 128d²128d² = 512d² = 512/128d² = 4d = 2So, the four consecutive numbers are 8 - (3*2)8 - 6 = 28 - 2 = 68 + 2 = 108 + (3*2)8 + 6 = 14Four consecutive numbers are 2, 6, 10 and 14Answer

please like the solution 👍 ✔️👍✔️

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