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Dimension of aquariumLength l = 80 cm,Width b = 30 cmHeight h = 40 cm

Area of paper to be covered= Area of base + 2*Area of side faces + Area of back= (l*b + 2*b*h + l*h)= (80*30 + 2*30*40 + 80*40)= (2400 + 2400 + 3200)= 8000 cm^2

speed=distance/time=160m/10s=16m/s

1m=0.001km360m=0.36km1 seconds=1/3600 hourso 120 seconds in 120/3600=1/30hourso speed=0.36/(1/30)=30×0.36=10.8km/h

Total distance covered by the train in 36 seconds=length of train + length of the platform (let be x m)=(200+x) m

As we know,

distance= speed× Time=>(200+x)=50×(5/18)×36=>200+x=500=>x=500-200=300 m

:. length of the platform=300 m

0.05 km is the right answer of the following

5000 cm is the right answer

50 meters is nothing but 500 cm and 0.05 km

5000 cm or 0.05 km is the correct answer

5000cm 0.05m50000 mm

5000cm 0.05 km

50000mm

Answer is, 8000-4970=370.

370 is correct answer.

8000-4970=370 is the right answer for this questions

Yes, 370is the right answer

Srry... Answer is 5370

In purse. = 8000spend money = 4970 therefore Remaining = 3070

For given AP 21, 18, 15....

a=21a+d=17d = -3

a(nth term)= a+(n-1)d-81 = a+(n-1)d-81 = 21+[n-1](-3)-81- 21 = - 3n + 3-102 - 3 = - 3nn = 105/3 = 35

a(nth term)= a+(n-1)d0 = a+(n-1)d0 = 21+[n-1](-3)n-1 = -21/-3n-1 = 7n = 8

Therefore 35th term is - 81 and 8th term is 0

Bro please solve from the formula of cross multiplication............

a b se 25% kam kamata hai

A B se 25% kam kamata hai

125-100÷125×100= 20% kam kamata hain B

(b) Mirror : Glass

Chair is made of wood.Mirror is made of glass.

Circumference of circle=2πrr is the radius herea) C=2π(7)cm=2(22/7)(7)=44cmb)C=2π(3.5)cm=2(22/7)(3.5)=22cmc) C=2π(14)cm=88cmd) C=2π(21)cm=110cm

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i think its wrong

No. of bricks = volume of wall÷volume of brick =(40*600*2400)/(25*16*10) =5760000/4000No. of bricks =1440.

When 76.65 is divided by 2.1 it equals 36.5

full question to send khar

Let the first angle =∠A =xthe second angle =∠B = 1/3xand the third angle =∠C = x + 26°∠A +∠B +∠C = 180° x + 1/3x + x+26° = 180°7x/3 + 26° = 180° 7x/3 = 180° - 26° 7x/3 = 154° x = 154° x 3/7x = 66°∠A = x= 66°∠B =1/3 x = 1/3 x 66° = 22°∠C = x + 26° = 66°+ 26° = 92°

option cboth a and b

Let diagonals be 5d and 6dArea of rhombus = 1/2(5d*6d)240*2 = 30d^2d^2 = 16d = 4

DIAGONALS : 20 CM AND 24CM

thanks

Given A. P is 5 , 9 ,13 , .... 185

Here first term = 5

Common difference = a2 - a1 = 9 -5 = 4

The A.p is 5 , 9 , 13 , ......., 181 , 185

We have find out the 9 th term from the end .

Now , rearrange the A. P

185 , 181 , ......, 13 , 9 , 5

First term = a = 185

Common difference = d = a2 - a1 = 181 - 185 = - 4

n th term in an A. P = an = a + ( n - 1 ) d

a = 185 ; d = -4 ; n = 9

9 th term = a9 = a + ( 9-1 ) d

= 185 + 8 × ( - 4 )

= 185 - 32

= 153

Therefore required 9 th term from the end = 153

40 is correct answer of following question

=5×{24÷(9+(-6)}=5×{24÷(9-6)}=5×{24÷3}=5×8=40 Answer

40 is correct answer of this question

40 is correct answer Yahi Hai Sahi

40 is the correct answer of the given question

40 is correct answer of this question

40 is the right answer

Hi your answer is here------->

(i) 1/9(ii) -1/16(iii) 32are the correct answers

Given A. P is 5 , 9 ,13 , .... 185

Here first term = 5

Common difference = a2 - a1 = 9 -5 = 4

The A.p is 5 , 9 , 13 , ......., 181 , 185

We have find out the 9 th term from the end .

Now , rearrange the A. P

185 , 181 , ......, 13 , 9 , 5

First term = a = 185Common difference = d = a2 - a1 = 181 - 185 = - 4

n th term in an A. P = an = a + ( n - 1 ) d

a = 185 ; d = -4 ; n = 9

9 th term = a9 = a + ( 9-1 ) d= 185 + 8 × ( - 4 )= 185 - 32= 153Therefore required 9 th term from the end = 153

wrong answer

what's answer.........

you need sum of all terms??

-180

please recheck the solution provided O got the answer -180

-180 is write answer

as volume of the cuboid will be samehence first find the volume of cubehencevolume of cube is side^3=12^3=1728cm^3hence volume of cuboid=lbhhenceh=1728/16*15=7.2cm

4 and 2 r the diameters not radius

a + 7d = a + d/22a + 14d = a + da = -13da +10d = 1/3(a +3d) + 1a +10d -1 = 1/3(a + 3d)3(a + 10d -1) = a +3d3a + 30d -3 = a+ 3d2a + 27d =32(-13d) + 27d =3(since a = -13d)-26d + 27d = 3d = 3a= -13da = -39a + 14d = -39 + 41 =3hence,15th term is 3.

thanks sir

A=40 b (Given)A=1/2× b×hEquating both,40b=bh/2h=80 cm.

differentiation or integration

Ans(1) 576 Ans(2) 1225 Ans(3) 3722 Ans(4) 5184

a + 7d = a + d/22a + 14d = a + da = -13da +10d = 1/3(a +3d) + 1a +10d -1 = 1/3(a + 3d)3(a + 10d -1) = a +3d3a + 30d -3 = a+ 3d2a + 27d =32(-13d) + 27d =3(since a = -13d)-26d + 27d = 3d = 3a= -13da = -39a + 14d = -39 + 42hence a15 =3

रीतिकालीन कवियों में देव को अत्यंत प्रतिभाशाली कवि माना जाता है। देव की काव्यगत विशेषताएँ निम्नलिखित हैं–1.देवदत्त ब्रज भाषा के सिद्धहस्त कवि हैं।2.कवित्त एवं सवैया छंद का प्रयोग है।3.भाषा बेहद मंजी, कोमलता व माधुर्य गुण को लेकर ओत-प्रोत है।4.देवदत्त ने प्रकृति चित्रण को विशेष महत्व दिया है।5.देव अनुप्रास, उपमा, रूपक आदि अलंकारों का सहज स्वाभाविक प्रयोग करते हैं।6.देव के प्रकृति वर्णन में अपारम्परिकता है। उदाहरण के लिए उन्होंने अपने दूसरे कवित्त में सारी परंपराओ को तोड़कर वसंत को नायक के रुप में न दर्शा कर शिशु के रुप मेंचित्रित किया है।