15/ A 200 m long train running at a speed of 50 kmh crosses a platform

1.	15/ A 200 m long train running at a speed of 50 kmh crosses a platform in 36 selength of the platform
Answer» Total distance covered by the train in 36 seconds=length of train + length of the platform (let be x m)=(200+x) m As we know, distance= speed× Time=>(200+x)=50×(5/18)×36=>200+x=500=>x=500-200=300 m :. length of the platform=300 m

15/ A 200 m long train running at a speed of 50 kmh crosses a platform in 36 selength of the platform

Answer»

Total distance covered by the train in 36 seconds=length of train + length of the platform (let be x m)=(200+x) m

As we know,

distance= speed× Time=>(200+x)=50×(5/18)×36=>200+x=500=>x=500-200=300 m

:. length of the platform=300 m