Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Set 3: Area of Parallelograms12. Find the area of the following parallelograms.A. base 11 cm, height 6 cm

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Area=b×h= 66 cm square.

2.

ler the following parallelograms. Find thD

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opp. angle in paralogm are equal then anlge y=100therefore X=z sum of four angle =360x+y+z+100=360x+100+x+100=3602x+200=3602x=160x=80or z=80y=100if u satisfied with the ans then like or cmmt.✌️

x=z=80,y=100 ,100 are the angles

80°,100° is the correct answer of the given question

80° ,100 °is the correct answer of the given question

80°, 100° is the correct answer

80°, 100° is the answer of the following

3.

Find the area of following parallelograms

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4.

1. 6 taps of equal capacity can fill a reservoir in 15 minutes. How many taps can fill in 9 minutes?

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capacity of the reservoir is not given please give the capacity of the reservoir

5.

5. Kushal can read 124 words per minute. How many words will he read in 6 days if he reads daily for3 hours 50 minutes ?

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As rate is given in words/minutes. We will convert everything in minutes to make our jobs easier. So, he reads 3hr 50 min daily.This means he reads 230 minutes daily.So, in 6 days he will read for 230 × 6 minutes = 1380 minutesIn 1 minute he reads 124 words.In 1380 minutes, he read 124 × 1380 words= 171120 words

6.

the following parallelograms, find thevalues of x,上2 g parallelo

Answer»

Given : x = 90°

Opposite side equal then opposite angle are equal .

2y = 90°

y = 45°

So, z° = 45°

x=90,y=60,z=60 y=z

7.

Find the area of each of the following parallelograms:

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8.

A. Find x and y in the following parallelograms.80100/

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y=80x=100 because opposite angles are equal in parallelogram

Not give your phone number in your profile

9.

EXERCISE 11.21. Findi the area of each of the following parallelograms:

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area of parallelogram=bha. b=7cm and h=4cm.. area=bh=28cmb. b=5cm and h=3cm and area=bh=5×3=15cm

10.

o any cday m ey Coplete the wOrk5. Saleem can type 30 words per minute and Ranjit can type 50 words per minute. If Saleemneeds 30 minutes to finish typing a piece of work, how long will Ranjit take to finish thesame work?

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Saleem types at 30 words per minute.Ranjit types at 50 words per minuteIf Saleem requires 30 minutes to finishtyping a job then he has 30 * 30 words

to type = 900 wordsRanjit, typing at 50 words per minuterequires 900/50 = 18 minutes to type the same piece of work.

11.

12. What per cent of 0.0169 is 0.0117 ?

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the correct answer is 9

9 is correct answer hope u like it

12.

0). 01109. W ०५४१. भै०् जी. ७७५| थ्व 3 उठाए - Find [०९8 W an s sesnairieg पिला:: mj 74{F~Lm &

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Like if you find it useful

thanks you help me in exam preparing

13.

5. Lauryn receives a discount on each book shepurchases. The original price of each book isx dollars. She purchase 4 books for a total of(4x - 12) dollars. Factor the expression.What can you conclude about the discount?

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Cost of one book = x dollarsCost of 4 books = (4x - 12) dollars = 4(x - 3) dollars

Discount on books= (4x - (4x - 12))= 12 dollars

14.

57. Having the same capacity 9 taps fillup a water tank in 20 minutes. Howmany taps of the same capacity arerequired to fill up the same watertank in 15 minutes ?

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15.

(2) The weight of a bucket is 15 kg when it is filled with water upto of its capacity & theweight is 19 kg, if it is filled with water uptosh of its capacity. Find the total weight ofthe bucket, if it is completely filled with water

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13ho sita kwowowkneneneo0snsnej3

The weight of bucket when filled with water is actually the weight of the bucket and the weight of the water together. In both 3/5 and 4/5 cases weight of the bucket is constant, let it be x.Weight wen filed till 3/5: x+ weight of 3 parts ( each part 1/5 of the total capacity) of water. Let that be x+3y. It is 15kg.Similarly in the 4/5 case, the equation would be x+4y=19kg.Now, to the solving part,x+3y=15x= 15-3y.Now substitute this in the second equation,x+4y= 15-3y+4y=19.15+y=19.y= 4.That is, one part of water weighs 4kg. Similarly frm the equation you'll get x, the weight of the bucket to be 3kg.Now when filled to capacity the weight will be weight of the bucket and weight of five parts (full is5/5) of water: 3+4*5=23.

Let the weight of container be X and 1/5 capacity of water be y

According to Givenx + 3y = 15kg _________(1)x + 4y = 19kg _________(2)

Subtract (1) from (2) x + 4y = 19kg - x + 3y = 15kg--------------------------- y = 4kg _________(3)

Total capacity of water = 1/5 * 5 = 5yTotal weight of container full of water = x + 5y= x + 4y + y. [ From (2) and (3) ]= 19kg + 4kg= 23kg

Ans : 23kg

according to aclasses's trick

bucket wt when. fill15kg. 3/5th19kg. 4/5th19-15=4. 4-3/5 = 1/5th

4+19=23. 1/5+4/5 =5/5 or fullanswer is 23kg

23 kg is the correct weight

67/12 is right answer hoga

the weight of bucket when filled with water is actually let it be x .

23 kg is the correct answer to this question .

y=4 3+4*5=23answer h

this question answer23 kg hoga

23kg your Questions answer

23kg is the correct answer of this question.

19 kg weight when filled 4/515 kg wt when filled 3/54 kg water wt = 4/5-3/5= 1/51/5 part wt = 4kg1 part water wt = 20 kg

let wt of bucket be x because in both case wt of bucket included4/5-3/5= 1/5 let 1/5 wt of water be yx+3y=15-----(1)x+4y=19--++(2)by substrate -y= - 4y=4total capacity = 1/5×5=5yso x+5y{since x+4y= 19)x+4y+y= 19+4= 23 kg

23kg is the right answer

answer is 23 kilogram

23kg is the right answer to this question

23 kg will be the correct answer

Let the weight of empty bucket be 'x' and the weight of the water the bucket can hold to its full capacity be 'y' According to the first condition, x +3/5 y=15 1)According to the second condition, x+4/5 y=19 2)Multiplying equation 1) by 5 as well as equation 2) by 5,we get 5x+ 3y=75 3)5x + 4y=95 4)Subtracting equation 3 and 4 we get 5x+3y=755x+4y=95___________y=20substituting this value of y in equation 35x+3y=755x+3(20)=755x+60=755x=75-605x=15×=15/5×=3for finding the weight of the water filled in the bucket we will have to add the value of x and ytherefore x+y=3+20=23kgTherefore the weight of the bucket when it is completely filled with water is 23kg

23kg is the right answer

23 kg is the correct weight

16.

divisorWorkedample 1: Divide : x2-4x +4 by x-2

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(x^2-4x+4)/(x-2)=((x-2)(x-2))/(x-2)=x-2

17.

5.If the volume of a cube is V em3,its surface area is Sen? and the length),Tndtheratiooftheiredges.ofa diagonalis d em, provethat V =--S . d.

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18.

The angles of a quadrilateral are 90°, 80º, 125° and x°. Find the value of x.TUL

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65 degree is the correct answer to this question

65 degree is 5he correct answer of this question

65° is correct answer.

65° is the right answer

65° is the right answer for this questions...

65 is the correct answer

65 degree is write answar

65 degree is the correct answer to this question

My answer is Value of x is 65°

90 + 80 + 125 + X = 360 295 + X = 360 X = 360 _ 295 X = 65

65 degree is correct answer

the value of x is = 85

x=360°-(90°+80°+125°) =360°-295° =65°

so, 65° is the correct answer of this question

quadrilateral is 360°then,90°+80°+125°+x=360295°+x=360°x=360°-295X=65°ans..

value of the x in quadrilateral is 65°

65 degree is the correct answer to this question

we know thatthe sum of all angles of quadrilateral is 360.first we add all the angle and then substract from 360

65 degree is the correct answer

65 is the right answer

65 degrees is the correct answer

the value of x is 65°

the answer of this question is 65°

t he correct Qns is 65degree

65 degree Is the correct answer of the given question

65 degree is the correct andwer

given angles are 90,80,125,x then the value of x=?. in a quadrilateral sum angles are=360 then 90+80+125+x=360.295+x=360.x=360-295.x=65. let the value of x is 65 that is 90+80+125+65=360

after solving we got that thevalue of x is equal to the 65°

sum of all angles of a quardilateral=l36090+80+125+x=360295+x=360x=360-295x=65

sum of angles of a quadrilateral is 360°90+80+125+x°=360°295+x°=360°x=360 - 295x=65

65 °. is the right answer

90+80+125+x = 360295=36065 ans

Sum of angles of quadrilateral = 360 degreeSo, x = 360 - (90+80+125) = 360 - 295 = 65 degree.

65 degree is correct and best answer 👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍👍 👍

65° is the correct answer

Let the 4th angle =x A/q90+80+125+x=360x=360-295x=65the value of x=65

photo sahi nahi aaya

x = 65 digree is correct answer

90+80+125+x=360or, x=360-90-80-125or, x=65

90°+80°+125°+x°=360°90°+80°+125°=295°360°-295°=65°x=65°

the value of X is =65 degree

19.

y U\5 Tul™- छू i< .‘&न L{0) ।Bt i w

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20.

24. Two cubes each of volume 512 cm are joined end to end. Find the surface area of the resulting cuboid

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21.

ITUS. , hell Wlal Is tulThe first three terms of a proportion are 100, 90 and 110. Find the fourth term.

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x=90*110/100x=99 ans

22.

I.Mohan purchases some mattresses for Rs. 7250. After some time he soldthem for Rs. 6090. Find out loss percentage.

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cp=7250sp=6090loss=7250-6090=1160loss %=1160/7250×100=16%

23.

9. In figure, prove that p ll m.nl880°>35450

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24.

1200 + 56८6 - 1 _ _ ८059 _secB—tanf+1 1-—sin®o»q | &Nl Al

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25.

You have prizes to reveal! Go to yoWhat is the missing length?4 mmarea = 14 mm2millimeters

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Hit like if you find it useful

26.

LM 4andthen construct Δ LOPLQ 74) Calculate the area of the shaded region in theadjoining figure where □ ABCD is a squarewith side 10cm each 3.14)

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27.

s. Apassenger walks a distance of 6 km in two hours. Then be sets loto a us to thenearby village travelling 10 kim and taking 1 howrs. Thereafter he walks a distanceaf 2 kilemetres in 30 minutes.ind his average speed during the whole jouey

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thank you

28.

1. Multiply the binomials:(G) 2a-9 and 3a+4(iii) kl+ lm and kㅚ(11) x-2y and 2x-y(iv) m2 -n and mtn

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i) (2a - 9)(3a + 4)6a² + 8a -27a -366a² -19a -36

ii) (x - 2y)(2x - y)2x² -xy -4xy + 2y²2x² -5xy + 2y²

iii)(kl + lm) ( k - l)k²l - kl² + kml - l²m

iv)(m² - n²)(m+n)m³ + m²n -mn² -n³

29.

6 cm, QR9 cm and area04 (an the given figure LM |OR, LM141AfOR108 cm2. Find the area of ΔΡΙ.Μ.0)

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Area of PQR=(1/2)*9* Height(108*2)/9=heightheight=24108=area of PLM+area of LMRQ108=(1/2)*6*x + (1/2)*(9+6)*(24-x)216=6x+15(24-x)216=6x+360-15x9x=144x=16So, area of triangle PLM =(1/2)*6*16=48cm^2

30.

2.The surface area of a cube is 1734sq.cm, find its volumea) 4913cm74193cm'c) 1493cmd) 3419cmworde..

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=6lsquare=1734sq.cmside*side=1734/6 cm =289cm side=sq. root289 =17cmV=s*s*s=17*17*17cm cube=4913cm cube

31.

If lm, n is a transversal (see figure) and 41427 5, then find all the angles.1438nl:find all the internal angles of AABC

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32.

4. As shown in the following figureΔ LMN and Δ PNM, LM = PNLN-PM. Write the test which assuresthe congruence of the two trianglesWrite their remaining congruent parts.Fig. 3.23

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33.

In figure, LM = LN = 46". Express x in terms of a, b, and cwhere a, b, c are lengths of LM, MN and NK respectively[CBSE 2009, 1995 (D.B) (C)]△48。46°

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34.

) In the figure, AC=12 cm, LABC 90°,LBAC-30°, LACB 60°Find the length of seg AB and seg BC.

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35.

Example 25Find all the points of local maxima and local minima of the function f piven byf(x)=x3-6x2 +12x-8.

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36.

ik से लग्न 7.ABCD & चतुधुंज है. जिसमें ०») « ४2 और2 DAB = £ CBA है (देखिए आकृति 7.17)। सिद्धकोज्णि कि~ AABD=ABAC BD=AC) ZABD=ZBAC ७ लता.आकृति 7.17

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37.

10 labours finish a task in 2 days . how many days will 2 labours take to finish the same task?

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38.

16. In AABC, if ADBC and AD2-BD x DC provethat LBAC = 90°.

Answer»

In triangle ABC , AD is perpendicular to BC and AD² = BD.DC

To prove : BAC = 90°

Proof : in right triangles ∆ADB and ∆ADCSo, Pythagoras theorem should be apply , Then we have , AB² = AD² + BD² ----------(1)AC²= AD²+ DC² ---------(2)

AB² + AC² = 2AD² + BD²+ DC²= 2BD . CD + BD² + CD² [ ∵ given AD² = BD.CD ] = (BD + CD )² = BC²Thus in triangle ABC we have , AB² + AC²= BC²

hence triangle ABC is a right triangle right angled at A

∠ BAC = 90°

39.

25 workers can complete a task in 150days. How many workers will berequired to complete the task in 125days?

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25 worker complete the work in 150 days 1 worker will complete in 150÷25 =5worker required to complete the work in 125 days = 125×5=750 so , 750 worker are required

40.

5. If 11 boys complete a task in 55 days, in howmany days will 17 boys complete the task.working at the same rate?

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41.

ProvethatMABCisisoscelesifanyoneofthefollowing holdsProvethatG) Bisector of 2BAC is perpendicular to BC(ii) AltitudeAD bisects LBAC(iii) Altitude BE-Altitude CF.

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Given: triangle ABCRequired to prove: ABC is isosceles, i.e. AB=ACProof: Using number 2) Median AD perpendicular to BC In triangle ADB and triangle ADCAD=AD ( given )Angle ADB=Angle ADC ( as AD is perpendicular to BC )BD=DC ( as D divides BC into two equal halves )Therefore, Triangle ADB congruent to Triangle ADC=> AB=AC ( CPCT ) Therefore Triangle ABC is isosceles. Hence proved.

42.

5. In parallelogram ABCD, E is the mid-pointof side AB and CE bisects angle BCD. Provethat:(i AE AD(i)DE bisects ZADC and(ili) Angle DEC is a right angle.

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43.

119TRIANGLESABCD is a quadrilateral in which AD BC andDAB- CBA (see Fig. 7.17). Prove thatBD ACZABD LBAC

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in ∆ ABD and ∆BACAB= AB ( common)AD = BC (given)DAB = CBAso ∆ ABD and ∆BAC are congurent.ii) by CPCT BD = ACiii) by CPT ABD = BAC

44.

wlequnateral thangle.JiZ In the given figure, ABAC, AD AE andLBACIDAE. Prove that ABADΔCAB.ICCE 2010112. In the given fitre

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is it correct

45.

. ABCD is a quadrilateral in which AD BC andDABCBA (see Fig. 7.17). Prove thatBD=AC(ii)(iii)ABD=LBAC.

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46.

State the solution to the system.y = x + 3y = -x + 1

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Red line is y = x + 3Blue line is y = -x + 1,Point of intersection is ( solution) (-1,2)

47.

(2)Four test tubes are arranged inhas basic solution. Two friends A and B are playing a game to picktesting it, so that they can get their desirable solution either acid or base. If A decided topick an acid solution and B decided to pick basic solution, then explain whose chancesare more to pick desirable solution.a test tube stand of which 3 contains acid, and I test tubeone test tube without

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The probability of A to pick an acid solution is ¾the probability of B to pick an acid solution is ¾

48.

6. In a fort, 360 men have provision for 21 days. If 60 more men join, then how long will tvision for 21 days. If 60 more men join, then how long will the provision last?

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total food available=360×21=7560now 60 more join so total 360+60=420so number of days=7560/420=18 days

49.

A garrison of 200 men had provisions for 45 days. After 15 days. 40 more men Join thegarrison. Find the number of days for which the remaining food will last.6.

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50.

1. A property decreases in value every year at the rate of 6- per cent of its value at the beginning of thatits value at the end of 3 years be 21093.75, what was its worth at the beginning of these threeyears ?

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hope it helps u