Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the LCM and HCF of the following pairs of integers and verify thatLCM x HCF product of the two numbers.(i) 26 and 9 ) 510 and 92336 and 54

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2.

In quadrilateral ABCD, side AB isparallel to side DC. If A : D = 1 : 2 andC : <B = 4 : 5.(i) Calculate each angle of the quadrilateral.(ii) Assign a special name to quadrilateralABCD.

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it can be named as trapezium because it's 2 sides are parallel

3.

A quadrilateral whose one pair of opposite sides is parallel iscalled)

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A quadrilateral whose one pair of opposite sides is parallel is called trapezium.

4.

A quadrilateral whose one pair of opposite sides is parallel iscalledv)

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A quadrilateralwith theopposite sidelinesparallel is known asa parallelogram

5.

2. The three sides of a cyclic quadrilateral are 4cm, 8 cm and 6cm. If the semi perimeter of aAns: 43.8 cmrilateral is 14 cm. Find the area of the quadrilateral.

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If semiperimeter is 14cmHence perimeter will be 2*14=28cmHencetotal side sum is perimeterhence4+8+6+X=28x=10cmHence fourth side is 10cmNow area is √(s-a)(s-b)(s-c)(s-dHencearea=√(14-10)(14-8)(14-6)(14-4)=43.8cm^2

6.

what's semi cricle

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In mathematics, a semicircle is a one-dimensional locus of points that forms half of a circle. The full arc of a semicircle always measures 180°. It has only one line of symmetry

7.

A quadrilateral having only one pair of opposite sides parallel is

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A quadrilateral with the opposite side lines parallel is known as aparallelogram.

8.

3.Show that in an isosceles triangle, the angle opposite to equal sidesare equal. (Hint: Draw perpendicular bisector of unequal side)

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9.

nesquareofnegativehubeThe square of odd number is

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The square of odd number is an odd number.

If you find this answer helpful then like it.

10.

find two consecutive odd positives integers,sum of whole square is 290

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11.

Show that square of one of Positive odd integerof the form 4m+ 1

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any odd positive number can written as form of 2n+1take sqaure of 2n+1(2n+1)² = 4n² + 4n +1= 4(n²+n) +1 let n²+n = m so form will be 4m +1

thanks

12.

3. Subtract:(i) – 7 from - 3

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subtract-7 ,-3-7-3____10

-7 from -3 -3 -7-10 ans

13.

1+ 28 + 2V ()D + 1 + 4V = 10~ 0 ~ A0~ DO+ O + O V)eV2 8F T 40 e OF T30 08 T Q0 a2 3 0 S} Hith ey 2xke % DHFY ‘g ykiie 12 12 61 I

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14.

38 A fraction is equivalent to its denominator and numerator add upto 91. What is thedifference between the denominator and numerator of this fraction?(a) 3(b) 13 () 19 (d)(d) 21

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15.

3. In each figure alongside, a letterof the alphabet is shown alongwith a vertical line. Take themirror image of the letter in thegiven line. Find which letters lookthe same after reflection (i.e.which letters look the same in theimage) and which do not. Canyou guess why?Try for O E M NPHLTSVX

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16.

(८)8.9.2-10.यदि A : B = 5:7 और B :C = 6:7 हो, तो A : B:C होगा?( 25:49:42

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answer is A:B:C=30:42:49

answer A:35,B:42,andC:49

A:B:C is equal to 5:7:7

A:B:C is equal to 5:7:7 right answer

A:B:C is equal to 5:7:7 correct answer

A:B:C is equal to 5:7:7 correct answer

A: B = 5 : 7;. B : C = 6 :7;. A: B: C= 35 : 42 : 49

a: b: c is equal to 5:7:7 is the right answer

A:B:C is equal to 5:7:7 correct answer

17.

30. Three coins are tossed together. Find the probability 49of getting at least two heads.k.3(C) 긁 (D)58g-(A)(B) 8

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Three coins are tossed so number of outcomes=2*2*2=8We are required to get probability if getting atleast two heads.Favourable possibilities areHHH,HHT,HTH,THH=4 in numbers.Hence probability of getting atleast two heads=4/8=1/2

hence probability of getting at least two head=4/8=1/2

18.

3 Subtract the sum of - 524 and 678 from -92

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19.

Diameter of a circe i 26 cm and length of achord of the circle is 24 m. Find the distanceof the chord from the centrs

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D=26c.m.r=13c.m.

If we draw a height to the cord from the center than the cord divided into two parts which are equal

let AB is the chord and the height touches the chord at point X

than AX = BXAX=24/2=12cm

OA is the radius which is equal to 13cm

in triangle OAX,measure of OXA =90degree

and OA is the hypotenuse(h)

AX and OX are touching the right angle v so the are p and b as to Pythagorean theorem,h^2=p^2+ b^2

OA^2=Ax^2+OX^2

13^2=12^2+OX^2

169= 144+ OX ^2

169-144=OX ^2

25=0X^2

OX = √25

OX = 5

like my answer if you find it useful!

20.

36 cm and MIn the figure, ABmid-point of AB. Three semi-circeare drawn on AB, AM and MBiameters. A circle with centre cheis53.ne

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21.

prove that the linesegment joining the mid point of two sides of a triangle is parallel to the third side

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22.

3.Subtract the sum of 8 and 4from 20

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Thanks

23.

1. Subtract the3 from

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Given subtraction is ( 5 / 6 ) - ( 3 / 4 ) = 1 / 12.

3/4 from 5/65/6 - 3/420-18/242/241/12

5/6-3/4=5*4-3*6/4*6=20-18/24=2/24=1/12

24.

340×670

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340 * 670 = 227800

is the answer

25.

What is the value of cos2 670 -sin2 23°

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26.

How many terms of the A.P 5, 8, 11,add upto 670?

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27.

49+13(5x+7)=8(5+x)-3x

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plz like my answer

x = -5/3 not 50/3

28.

A rifle of mass 3 kg fires a bullet ofass 0.03 kg. The bullet leaves the barrel of the rifle at a velocity of 100 m/s. If the bullet takes 0.003 second to moveout of the barrel, calculate the force experiencedby the rifle due to its recoil.

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29.

(1) Oh Rul (Vertical Line) :.

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Avertical lineis one the goes straight up and down, parallel to the y-axis of the coordinate plane. All points on thelinewill have the same x-coordinate. In the figure above, drag either point and note that thelineisverticalwhen they both have the same x-coordinate. Avertical linehas no slope.

30.

|(0.5 25600 चदू 5609— 2cosec?8 + coseco49 = cot*d — tan*d2

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LHS = 2 sec²A - sec⁴A - 2cosec²A + cosec⁴A

= 2 sec²A - 2cosec²A - sec⁴A + cosec⁴A

= 2(sec²A - cosec²A) -[(sec²A)² - (cosec²A)²] =2(sec²A-cosec²A)+[(sec²A-cosec²A)(sec²A+cosec²A)]

= (sec²A - cosec²A) [2 - (sec²A + cosec²A)]

= (sec²A - cosec²A) (2 - sec²A - cosec²A)

= (sec²A - cosec²A) (1 - sec²A + 1 - cosec²A)

= (sec²A - cosec²A) (tan²A - cot²A)

= (1 - tan²A - 1 - cot²A) (tan²A - cot²A)

= - (tan²A + cot²A) (tan²A - cot²A)

= - (tan⁴A + cot⁴A)

= cot⁴A - tan⁴A

= RHS

Hence Proved

31.

Duaus a circefouors Center sduuet the

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32.

Find the fourth term from the end in an A.P. -11, -8,-5,..,49.

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33.

find value of a for which point p (a,2) is midpoint of linesegment joining point Q (-5,4)R (-1,0)

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a=(-5-1)/2=-6/2=-3So, p is (-3,2)

34.

3 Subtract the following.(a) 2565 from 3989(d) 54.731 from 2.32.329 (e) 897 from 1234(b) 769 from 2500

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a)3989-2565 = 1424 b)2500-769 = 1731 c)232329-54731 = 177598 d)1234-897 = 337

35.

A boy standing at a distance of 48 meters from a building observes the top of thebuilding and makes an angle of elevation of 30°.Find the height of the building.

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36.

Ia Fig. 9.27,ABCDE is a pentagon. A line through8 parallel to AC meets DC produced at F. Showthat(i) ar (ACB) = ar (ACF)(ii) ar (AEDF) = ar (ABCDE)

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37.

WIthAB I DC intersect each other at O.n Fig. 9.27.ABCDE is a pentagon. A line throughB parallel to AC meets DC produced at F. Showthat(1) ar (ACB) = ar (ACF)(ii) ar (AEDF) = ar (ABCDE)Fig. 9.27

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38.

a carpenter makes a letter box which has a volume of 13407 cM cube the base as an area of 670 CM square what is the height of the letter box

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39.

y is at a distance of 60 m from a tree, makes an angle of elevation of 60 with the top of the tree.What is the height of the tree?

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Angle is 60° and base will be 60m Hence height that is perpendicular distance hence tantheta=perpendicular/basehencetan60=h/60h=60√3m

40.

L lhFig,9.27, ABCDE is a pentagon. A line throughB parallel to AC meets DC produced at F. Showthat0ar(ACB)-ar (ACF)inar(AEDF)-ar (ABCDE)Fig. 9.27ne

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41.

7. The enrolment in a school during six consecutive years was as follows:1555, 1670, 1750, 2013, 2540, 2820Find the mean enrolment of the school for this period.

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2058 is the answer of the following

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42.

\left(7^{2} s^{-2}\right)^{2} \times\left(49^{9 / 2} \div s^{3}\right)^{-2}

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43.

Draw a line segment of AB =6cm. find a point Q on it such that AQ =2/3QB

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let QB = x the AQ=(2/3)xx+(2/3)x=6x=3.3 cmQB =3.3cmAQ=2.2cm

44.

The area of the base of a cuboid is 45 cm2, itsheight is 6cm. Find the volume.

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The volume can be written as Area of base×height. Volume= 45×6 =270 cm^3

45.

Draw a line segment of AB=6cm . Find a point Q on it such that AQ=2/3QB

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let QB = x the AQ=(2/3)xx+(2/3)x=6x=3.3 cmQB =3.3cmAQ=2.2cm

46.

calculate 1-2+3-4+5-6+7-8+....+49-50

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calculate 1+3+5+7+,,,,,49=625, -2-4-6-8-12,,,,,,50=650, ; 650-625=-25

-25is the answer of this ques

-25 is the answer of your questions

-25 is the answer of this question

-25 is correct answer

we have to add positive and negative. answer is -25 is correct

47.

The dimensions of a cuboid are 10cm, 8cm,6cm. Find its volume, total surface areaand length of its diagonal.

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48.

UUULUquation (a + b)x2 – 2(ac + bd)x+(c? + d) = 0 are equal, prove that21. If the roots of the equation (a + b )x2 - 2(ac + bd)x+(2212asD2T

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49.

125Directions (Q. Nos. 10-11) A triangular plane ABC withcentroid (1, 2, 3) cuts the coordinate axes at A, B, C,respectively.10. What are the intercepts made by the plane ABCon the axes?(a) 3, 6, 9(b) 1, 2, 3(c) 1, 4, 9(d) 2, 4, 6> (a) We have, 1

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centroid for x-axis is given by (x1+x2+x3)/3

and here (x1+x2+x3)/3 = 1....

=> (x1+0+0)/3 = 1...... ( x2 and x3 are 0 as the co-ordinate cuts at y and z axis )

=> x1 = 3

similarly , y2 = 2*3 = 6

and z3 = 3*3 = 9

the intrrcepts are (x1,y1,z1) = (3,6,9)

50.

\frac { 9 } { 4 } a ^ { 2 } + \frac { 49 } { 9 } p ^ { 2 } - 7 a p

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(3a/2)² + (7p/3)² - 2× (3a/2) × (7p/3)so we get(3a/2+7p/3)²