Saved Bookmarks
| 1. |
Diameter of a circe i 26 cm and length of achord of the circle is 24 m. Find the distanceof the chord from the centrs |
|
Answer» D=26c.m.r=13c.m. If we draw a height to the cord from the center than the cord divided into two parts which are equal let AB is the chord and the height touches the chord at point X than AX = BXAX=24/2=12cm OA is the radius which is equal to 13cm in triangle OAX,measure of OXA =90degree and OA is the hypotenuse(h) AX and OX are touching the right angle v so the are p and b as to Pythagorean theorem,h^2=p^2+ b^2 OA^2=Ax^2+OX^2 13^2=12^2+OX^2 169= 144+ OX ^2 169-144=OX ^2 25=0X^2 OX = √25 OX = 5 like my answer if you find it useful! |
|