1.

Diameter of a circe i 26 cm and length of achord of the circle is 24 m. Find the distanceof the chord from the centrs

Answer»

D=26c.m.r=13c.m.

If we draw a height to the cord from the center than the cord divided into two parts which are equal

let AB is the chord and the height touches the chord at point X

than AX = BXAX=24/2=12cm

OA is the radius which is equal to 13cm

in triangle OAX,measure of OXA =90degree

and OA is the hypotenuse(h)

AX and OX are touching the right angle v so the are p and b as to Pythagorean theorem,h^2=p^2+ b^2

OA^2=Ax^2+OX^2

13^2=12^2+OX^2

169= 144+ OX ^2

169-144=OX ^2

25=0X^2

OX = √25

OX = 5

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