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Show that square of one of Positive odd integerof the form 4m+ 1 |
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Answer» any odd positive number can written as form of 2n+1take sqaure of 2n+1(2n+1)² = 4n² + 4n +1= 4(n²+n) +1 let n²+n = m so form will be 4m +1 thanks |
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