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5x+5=405x=40-55x=35x=35/5x=7

The outer surface area of the cylinder = 2πrh

= 2 x 3.14 x 0.7 x 2.4

= 10.55 cm²

slant height of the cone, L = √(h² + r²)

=√(2.4² + 0.7²)

= √6.25

= 2.5 cm

hence outer surface area of the cone = πrL

= 3.14 x 0.7 x 2.5

= 5.5 cm²

This outer surface area of the cone is equal to the inner surface area of the hollow portion of the cylinder left.

surface area of the cylindrical base = πr²

= 3.14 x 0.7²

= 1.54 cm²

Hence total surface area of the remaining solid = The outer surface area of the cylinder + inner surface area of the hollow portion of the cylinder left + surface area of the cylindrical base

= 10.55 + 5.5 + 1.54

= 17.59 cm²

= 18 cm² (rounded off to nearest cm²)

Hence the total surface area of the remaining solid will be 18 cm²

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5/(x+1) - 2/(y-1) = 1/2 10/(x+1) + 2/(y-1) = 5/2 Add both the equation 5/(x+1) - 2/(y-1) + 10/(x+1) + 2/(y-1) = 1/2 + 5/2 15/(x+1) = 6/2 x + 1 = 5 x = 4 From first equation 5/5 - 2/(y-1) = 1/2 2/(y-1) = 1 - 1/2 = 1/2 y - 1 = 4 y = 5

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9=638=487=356=244=12 is the correct answer

12 is the right answer

hsjsjskslalakkkjjjjj to be a part of the team and

correct answer 8

4= 8 is the best answer

9=638=487=356=244=12iis the correct answer

answer is 12.because 9=63 9/7=

answer is 12.because 9×7=63.8×6=48.7×5=356×4=24then, 4×3=12.

9*7=638*6=487*5=356*4=244*3=12 Answer is right

send with p (x,y )

i think the answer is 2x-3

I think the answer is 2x, _3

I think the answers is 2 x - 3

happy environment day

I think the answer is 2 x + 3

i think the answer is 2x-3

no! =;#= $!÷;×!÷!3*4!4!!3 ÷!=;÷ ÷:× =;#::×: ::× 2 ×3 × 3 ÷ ÷ ÷ 31 +;÷!

in first question you must subtract first equition to second .

Let the required number bex.−30−30-1÷x= 6-1⇒1/(−30)×1/x=1/6

1/(-30)×1/x=1/6

⇒1/(−30x)=1/6 1(-30x)=1/6∴x=6/(−30)=1/−5Hence, the required number is−1/5

hence required banswer is -1/5

36 it is right answers

51*51 - 50*50= 2601 - 2500= 101

Five rational numbers between 3/5 and 4/5

In order to find five rational numbers Multiply and divide each of these by 6. Then we get numbers3/5 = 3*6/5*6 = 18/304/5 = 4*6/5*6 = 24/30

Now five rational numbers between 18/30 and 24/30 are19/30, 20/30, 21/30, 22/30, 23/30

P(E) = 0.67P( not E) = 1-0.67 = 0.33

Minimum f(x) when denominator maximum4-sin2x maximumDifferentiate-2cos2x=0x=45Put x =451/(4-1)=1/3option 3 is correct

5x + 5 = 40

5x = 40 - 5

5x = 35

x = 35/5

x = 7

Given that, mth term=1/n and nth term=1/m.then ,let a and d be the first term and the common difference of the A.P.so a+(m-1)d=1/n...........(1) and a+(n-1)d=1/m...........(2).subtracting equation (1) by (2) we get,md-d-nd+d=1/n-1/m=>d(m-n)=m-n/mn=>d=1/mn. again if we put this value in equation (1) or (2) we get, a=1/mn.then, let A be the mnth term of the APa+(mn-1)d=1/mn+1+(-1/mn)=1 hence proved.

3x - 5 = 5x + 115x - 3x = - 5 - 112x = - 16x = - 16/2 = - 8

Value of x is - 8

Let the three numbers be

a-d,a,a+d

Sum of numbers=6

a-d+a+a+d=6

a+a+a=6

3a=6

a=2

Product of numbers=6

a-d×a×a+d=6

a-d×a+d×a=6

[a-b×a+b=a^2-b^2]

a^2-d^2×a=6

Substitute the value of a

2^2-d^2×2=6

4-d^2=6/2

4-d^2=3

-d^2=3-4

-d^2=-1

d^2=1

d=root over 1

d=+ or - 1

Therefore A.P will be

a=2 d=1

2,3,4,5,6...........

Or

a=2 d=-1

2,1,0,-1,-2..........

wrong ans is 3 4upon7

3.47

5x -3y +8 -2x+y-5= 3x -2y +3

3x-2y+3 is the answer

(5x+3y+8)- (2x+y+5)=5x+3y+8-2x-y-5= 5x-2x+3y-y+8-5= 3x+2y+3 should be substrate

5x -3y +8 -2x+y-5= 3x -2y +3

In 1.5m = 150cm60/150*100= 6000/15040 percentage

2) 40/600*100= 40/6= 6.6 percentage

multiply both numbers by 10 and write 5 rational number

let n=5we convert

By multiplying 10/10 to denominator and numerator30/50 and 40/50nowthe rational number31/50,32/50,33/50,34/50,35/50

5x-4x+14=6x-2+(7/2)5x=16-(7/2)5x=(32-7)/25x=25/2

x=5/2

Acosx - bsinx = c ------(1) take square both sides a²cos²x + b²sin²x -2absinx.cosx = c² ----(1)

asinx + bcosx = L --------(2) take square both sides a²sin²x + b²cos²x +2absinx.cosx = L² ----(2)

add equations (1)and (2) a²(sin²x + cos²x ) + b²( sin²x + cos²x ) = c² + L²

a² + b² = c² + L²

L² = a² + b² -c²

L = ±√( a² + b² - c²)

asinx + bcosx =±√(a² + b² - c²)

I can't see ur answer clearly

let me know if there is any doubt

please do it in a simple manner with out taking αβetc

Given that the kumarpays Rs 120000 in cash.Therefore, unpaid amount = Rs 240000 – Rs 120000 = Rs 120000According to the given condition, the interest paid annually is12% of 120000, 12% of 110000, 12% of 100000, …, 12% of 10000Thus, total interest to be paid = 12% of 120000 + 12% of 110000 + 12% of 100000 + … + 12% of 10000= 12% of (120000 + 110000 + 100000 + … + 10000)= 12% of (10000 + 20000+ 30000 + … + 120000)Now, the series 10000, 20000, 30000 … 120000 is an A.P. with both the first term and common difference equal to 10000.Let the number of terms of the A.P. ben.∴ 120000 = 10000+ (n– 1) 10000⇒ 1 + (n– 1) = 12⇒n= 12∴Sum of the A.P

=12[2(10000)+(12-1)(10000)]/2= 6[20000+110000]= 6(130000)= 780000Thus, total interest to be paid = 12% of (10000 + 20000 + 30000 + … + 120000)= 12% of 780000= Rs 93600Thus, cost of car= (Rs 240000 + Rs 93600) = Rs 333600

tq

Let the tens digit is x and unit digit is y

The number is 10 x + y

10 x + y +18 = 10 y + x

9 x - 9 y = -18

x - y = -2 ………(1)

x + y = 12….(2)

2 x = 10 Therefore x =5

From equation 2, 5 + y - 12 Therefore y = 7

The number is10*5+7= 57

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