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ORm, a conmical cavity of tcavityFromheight andthe nearest cm.a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conicalsame diameter is hollowed out. Find the total surface area of the reIni/4s105°. Now, construct a trianat |
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Answer» The outer surface area of the cylinder = 2πrh = 2 x 3.14 x 0.7 x 2.4 = 10.55 cm² slant height of the cone, L = √(h² + r²) =√(2.4² + 0.7²) = √6.25 = 2.5 cm hence outer surface area of the cone = πrL = 3.14 x 0.7 x 2.5 = 5.5 cm² This outer surface area of the cone is equal to the inner surface area of the hollow portion of the cylinder left. surface area of the cylindrical base = πr² = 3.14 x 0.7² = 1.54 cm² Hence total surface area of the remaining solid = The outer surface area of the cylinder + inner surface area of the hollow portion of the cylinder left + surface area of the cylindrical base = 10.55 + 5.5 + 1.54 = 17.59 cm² = 18 cm² (rounded off to nearest cm²) Hence the total surface area of the remaining solid will be 18 cm² Like my answer if you find it useful! |
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