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find the 2 nop in A.P whose sum and produeI are band 6 respectively |
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Answer» Let the three numbers be a-d,a,a+d Sum of numbers=6 a-d+a+a+d=6 a+a+a=6 3a=6 a=2 Product of numbers=6 a-d×a×a+d=6 a-d×a+d×a=6 [a-b×a+b=a^2-b^2] a^2-d^2×a=6 Substitute the value of a 2^2-d^2×2=6 4-d^2=6/2 4-d^2=3 -d^2=3-4 -d^2=-1 d^2=1 d=root over 1 d=+ or - 1 Therefore A.P will be a=2 d=1 2,3,4,5,6........... Or a=2 d=-1 2,1,0,-1,-2.......... |
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