Explore topic-wise InterviewSolutions in Current Affairs.

Let no. Of stamps Jay has = 3xSaurav has = 4xMayank has = 5xGiven 4x = 108 x = 27

Stamps Jay has = 3*27 = 81Stamps Mayank has = 5*27 = 135

wat u want plzz snd perticular

Crop only the question that you want a solution for. We will not be able to provide solutions to multiple questions.

if X+1 is a factorthenx=-1 will satisfy the equation a(-1)^3+(-1)^2-2(-1)+4a-9=0-a+1+2+5a-9=04a+3-9=04a-6=0a=3/2

Like if you find it useful

1. Radius of circle=10 cmarea of the circle=πr² = 22/7 x 100 = 314.28 cm²now area of minor sector= 100 cm²therefore, area of major sector= (314.28 - 100) cm² = 214.28 cm²

Like my answer if you find it useful!

Like if you find it useful

(6x + 1)/3 + 1 = (x - 3)/6

(6x +1 + 3)6 = 3(x - 3)

2(6x + 4) = (x - 3)

12x + 8 = x - 3

12x - x = - 8 - 3

11x = - 11

x = - 11/11 = - 1

6x+1÷3 +1=x-3÷66x+4÷3=x-3÷66(6x+4)=3(x-3)36x+24=3x-936x-3x=-9-2433x=-33x=-1..ans

Each angle of equilateral triangle is equal let them be a.As sum of angles in triangle is 180° So,a+a+a = 1803a = 180a = 180/3 = 60°

So each angle of equilateral triangle is 60°

in equalateral tringle sides are equal then sum of tringle is equal to 180 so let the angle of tringle be x then 3x =180 so x=60

p/q= (6/5)²×1=36/25(p/q)-²=(6/5) -⁴

(cotA -cosA)/(cotA + cosA)

((cosA/sinA)-cosA)/((cosA/sinA)-cosA) cotA=cosA/sinA

taking cosA common from numretor nd denominatr nd cancelling it we get

((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA

therfore

(cosecA-1)/(cosecA+1)

Like if you find it useful!

(cotA-cosA) /(cotA+cosA)

Four consecutive integers are following :-43444546

Please like my answer..

Please chose it the Best

Proof:

(i)Here, Parallelograms PQRS andABRS lie on the same base SR and between the same parallel lines SR and PB.

∴ ar(PQRS) = ar(ABRS) — (i)

(ii) In ΔAXS and parallelogram ABRS are lying on the same base AS and betweenthe same parallel lines AS and BR.

∴ ar(ΔAXS)= 1/2 ar(ABRS) — (ii)

From eq (i) and (ii),

ar(ΔAXS) = 1/2 ar(PQRS)

Given:

PQRS & ABRS both are parallelograms and Xis any point on BR.

To show:

(i) ar (PQRS) = ar (ABRS)

(ii) ar (AXS) = ar (PQRS)

Proof:

(i)Here, Parallelograms PQRS andABRS lie on the same base SR and between the same parallel lines SR and PB.

∴ ar(PQRS) = ar(ABRS) — (i)

(ii) In ΔAXS and parallelogram ABRS are lying on the same base AS and betweenthe same parallel lines AS and BR.

∴ ar(ΔAXS)= 1/2 ar(ABRS) — (ii)

From eq (i) and (ii),

ar(ΔAXS) = 1/2 ar(PQRS)

hit like if you find it useful

Parallelograms on the same base and betweenthe same parallels are equal in area.

If a parallelogram and a triangle are onthe same base and between the same parallels then area of the triangle is halfthe area of the parallelogram.

=========================================================

Given:

PQRS & ABRS both are parallelograms and Xis any point on BR.

To show:

(i) ar (PQRS) = ar (ABRS)

(ii) ar (AXS) = ar (PQRS)

Proof:

(i)Here, Parallelograms PQRS andABRS lie on the same base SR and between the same parallel lines SR and PB.

∴ ar(PQRS) = ar(ABRS) — (i)

(ii) In ΔAXS and parallelogram ABRS are lying on the same base AS and betweenthe same parallel lines AS and BR.

∴ ar(ΔAXS)= 1/2 ar(ABRS) — (ii)

From eq (i) and (ii),

ar(ΔAXS) = 1/2 ar(PQRS)

=========================================================

perimeter of equilateral triangle=3×side =3×0.5 =1.5cm Ans.

the answer is option Dplease like

We know that the sum of angle of triangle is 180°

if angle A is 90°

then,,180-90= 90.

AB=AC

Therefore,, angle B =angle C= 45°

1. A square has 4 sides. Length of each side = 30/4 = 7.5 cm. 2. An equilateral triangle has 3 equal sides. Length of each side = 30/3 = 10cm. 3. A hexagon has 6 sides. Length of each side = 30/6 = 5cm

Please hit the like button

Ans :- Global warming is the average temperature of earth has increase since 1950 until now the temperature continuing increasing. Global warming can also refer to climate change that caused an increase in temperature . However Global warming are causes By natural events and human that are believed to be contribute to increase in average temperature.

The effects of global warming are the environmental and social changes caused (directly or indirectly) by human emissions of greenhouse gases.

Let the three consecutive integers be x,x+1,x+2. x+(x+1)+(x+2) = 51 3x+3=51 3x=48 x=16. So the numbers are 16,17,18.

X+x+1+x+2+x+3=464x+6=464x=40x=10the integers areX=10x+1=10+1=11x+2=12x+3=13

thaxx

Three consecutive integers are x,x+1,x+2. x+x+1+x+2=51 3x=48 x=16 So the integers are 16,17,18.

please like the solution 👍 ✔️👍

d) of these, as between two numbers there are infinite rational numbers

When reflected about y axis the sign of x coordinate changes soNow A'(-2,6) B'(3,5) C'(-4,5)After reflection in the origin the sign of both coordinates change.Now A''(2,-6) B''(-3,-5) C''(4,-5).

Let the circle touches the sidesAB,BC andCA oftriangle ABCat D, E and F

Since lengths of tangents drawn from an external point are equal We have

AD=AF, BD=BE and CE=CF

Similarly EB=BD=r

Then we have c=AF+FC

⇒ c=AD+CE

⇒ c= (AB-DB)(CB-EB)

⇒c = a-r +b-r

⇒ 2r=a+b-c

r =( a+b-c)/2

Coordiante of the centroid of the triangle is:x=(x₁+x₂+x₃)/3 , y=(y₁+y₂+y₃)/3∴, According to the given question,(a+b+c)/3=0or, a+b+c=0 -----------------(1)

Now, (a+b+c)³=a³+3a²b+3ab²+b³+3a²c+6abc+3b²c+3ac²+3bc²+c³or, (a+b+c)³=a³+b³+c³+3a²(b+c)+3b²(c+a)+3c²(a+b)+6abcor, a³+b³+c³=(a+b+c)³-3a²(-a)-3b²(-b)-3c²(-c)-6abc [Using (1)]or, a³+b³+c³=3a³+3b³+3c³-6abcor, a³+b³+c³-3a³-3b³-3c³=-6abcor, -2a³-2b³-2c³=-6abcor, a³+b³+c³=3abc Ans.

vertices : L , M, Nsides : LM, MN, NL angles : <L , <M, <N

Let the circle touches the sidesAB,BC andCA oftriangle ABCat D, E and F

Since lengths of tangents drawn from an external point are equal We have

AD=AF, BD=BE and CE=CF

Similarly EB=BD=r

Then we have c=AF+FC

⇒ c=AD+CE

⇒ c= (AB-DB)(CB-EB)

⇒c = a-r +b-r

⇒ 2r=a+b-c

r =( a+b-c)/2