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गा (016 -- (668 (0620 A_(अ+.मि. 8 ह . .: |
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Answer» (cotA -cosA)/(cotA + cosA) ((cosA/sinA)-cosA)/((cosA/sinA)-cosA) cotA=cosA/sinA taking cosA common from numretor nd denominatr nd cancelling it we get ((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA therfore (cosecA-1)/(cosecA+1) Like if you find it useful! (cotA-cosA) /(cotA+cosA) |
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