1.

गा (016 -- (668 (0620 A_(अ+.मि. 8 ह . .:

Answer»

(cotA -cosA)/(cotA + cosA)

((cosA/sinA)-cosA)/((cosA/sinA)-cosA) cotA=cosA/sinA

taking cosA common from numretor nd denominatr nd cancelling it we get

((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA

therfore

(cosecA-1)/(cosecA+1)

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(cotA-cosA) /(cotA+cosA)



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