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.PQRS and ABRS are parallelograms and Xisany point on the side BR. Show that(i) ar(PQRS)-ar(ABRSY)(ii) ar(AAXS) 2ar(PQR)S- ar |
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Answer» Proof: (i)Here, Parallelograms PQRS andABRS lie on the same base SR and between the same parallel lines SR and PB. ∴ ar(PQRS) = ar(ABRS) — (i) (ii) In ΔAXS and parallelogram ABRS are lying on the same base AS and betweenthe same parallel lines AS and BR. ∴ ar(ΔAXS)= 1/2 ar(ABRS) — (ii) From eq (i) and (ii), ar(ΔAXS) = 1/2 ar(PQRS) |
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