81279 + Interview Questions in Mathematics QA in Mathematics

1.	ABCD is atraperium in which AB IDC. BD is a diagonal and Eisthe mid-printofALA line is drawn through E parallel to AB intersecting BC at F(see F 836)Sho tF is the mid-point of BC4.
Answer»

Discussion

2.	f AD. AABCD is a trapezium in which AB//DC, BD is a diagonal and E is the mid-pointoline drawn through E parallel to AB intersecting BC at F. Show that F is the midpoint oBC.2
Answer» Thx

Discussion

3.	1.Atowerstandsverticallyonthe ground. From apoint on the ground, 20 m away from the1. A tfoot of the tower, the angle of elevation of the top of the tower is 60°. What is the height ofthe tower?
Answer»

Discussion

4.	29. A tower stands Vertically on the ground. From a point on theground, which is 75m away from the foot of the tower, theangle of elevation of the top of the tower is found to be 60Â°Find the height of the tower.
Answer»

Discussion

5.	Example 1 : A tower stands vertically on the ground. From a point on the ground,which is 15 m away from the foot of the tower, the angle of elevation of the top of thetower is found to be 60o. Find the height of the tower
Answer»

Discussion

6.	Example 1 : A tower stands vertically on the ground. From a point on the groundwhich is 15 m away from the foot of the tower, the angle of elevation of the top of tetower is found to be 60Â°. Find the height of the tower.
Answer»

Discussion

7.	of(ii) telocity of a train changes from 20m/s to 25 mn when it accelentes dii2s Find the distance covered by the train
Answer» Use the formula: v^2=u^2+2as Where v is the final velocity = 25 m/s u is initial velocity = 20 m/s a is the acceleration = 2m/s^2 s is the distance traveled. Substitute the above values in the equation of motion to get s = (625 - 400)/4 = 56.25 m

7.

of(ii) telocity of a train changes from 20m/s to 25 mn when it accelentes dii2s Find the distance covered by the train

Answer»

Use the formula:

v^2=u^2+2as

Where v is the final velocity = 25 m/s

u is initial velocity = 20 m/s

a is the acceleration = 2m/s^2

s is the distance traveled.

Substitute the above values in the equation of motion to get s = (625 - 400)/4 = 56.25 m

Discussion

8.	ABCD is a trapezium in which AB I DC, BD is a diagonal and E is the mid-point ofine is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30).Show that F is the mid-point of BC.
Answer»

Discussion

9.	-49c^2 %2B 28(bc) %2B 25a^2 - 4*b^2
Answer»

Discussion

10.	1. The marks obtained by 20 students in an examination are as under:20, 35, 35, 20, 38, 40, 39, 38, 39, 38, 40, 39, 41, 42, 41, 42, 43, 48, 39, 42.Find the median and mode of the marks.
Answer»

Discussion

11.	: The scale of a map is given as 1:30000. Two cities are 4 cm apant on the mapFind the actual distance between them.
Answer»

Discussion

12.	1-sin?30° cos®60°+ cos®30°xS ~sin 60° tan 30°1+sin’45° cosec?90°—cot”90°
Answer» (1-sin30sin30)/(1+sin45sin45) × (cos60cos60+cos30cos30)/(cosec90cosec90-cot90cot90) ÷ sin60tan30 = (1-1/21/2)/(1+1/2) × (1/21/2 + 3/4)/(11-0*0) ÷ (√3/2 × 1/√3) = (1-1/4)/(3/2) × (1/4+3/4)/(1) ÷ 1/2 = (3/4)/(3/2) × (4/4)/(1) × 2 = 2/4 × 1 × 2 = 4/4 = 1 If you find this answer helpful then like it. Good effort vai....

12.

1-sin?30° cos®60°+ cos®30°xS ~sin 60° tan 30°1+sin’45° cosec?90°—cot”90°

Answer»

(1-sin30*sin30)/(1+sin45*sin45) × (cos60*cos60+cos30*cos30)/(cosec90*cosec90-cot90*cot90) ÷ sin60*tan30 = (1-1/2*1/2)/(1+1/2) × (1/2*1/2 + 3/4)/(1*1-0*0) ÷ (√3/2 × 1/√3) = (1-1/4)/(3/2) × (1/4+3/4)/(1) ÷ 1/2 = (3/4)/(3/2) × (4/4)/(1) × 2 = 2/4 × 1 × 2 = 4/4 = 1

If you find this answer helpful then like it.

Good effort vai....

Discussion

13.	.28From an aeroplane vertically above a straight horizontal plane, the angles of depression ofo consecutive kilometer stones on the opposite sides of the aeroplane are found to be α and βtan α tan βthat the height of the aeroplane istan α + tan β
Answer»

Discussion

14.	A tower stands vertically on theoint on the ground which is 25 mapot of the tower, the angie of elevation of the topf the tower is found to be 45e . Then, find theight (in metres) of the tower.ground. From aaway from
Answer»

Discussion

15.	25 a ^ 2 - 4 b ^ 2 %2B 28 b c - 49 c ^ 2
Answer»

Discussion

16.	limit X3X+2
Answer»

Discussion

17.	x3x-100(ii) 2x2 +x-60
Answer» x2-3x-10=0x2-(5-2)x-10=0x2-5x+2x-10=0x(x-5)+2(x-5)=0x=5,-2

Discussion

18.	25 a ^ { 2 } - 4 b ^ { 2 } + 28 b c - 49 c ^ { 2 }
Answer»

Discussion

19.	03. Beni opened his history book, and noticed that the product of the two pages in front ofhim was equal to 1122. What were the numbers of those pages?
Answer» two pages are x and x-1so x(x-1)=1122x*x-x-1122=0(x-34)(x+33)=0so x=34so pages are 33 and 34

Discussion

20.	9. What is the domain of the functionx3x+
Answer» thankss

Discussion

21.	Use the formula to findthe valve (52848
Answer» 2496 is the correct answer of the given question 2496 is the correct answer 2496 is the correct answer 2496 is the correct answer of the given question. please like my answer 2496 is the correct answer 2496 is the right answer

21.

Use the formula to findthe valve (52848

Answer»

2496 is the correct answer of the given question

2496 is the correct answer

2496 is the correct answer of the given question. please like my answer

2496 is the correct answer

2496 is the right answer

Discussion

22.	Where S is non empty subset ofove that: Lim (1+x)½-e-x->0
Answer»

Discussion

23.	If the difference between the probabilities of happening & nonhappening of an event E is3/7. Find the probability of happeningof the event E
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Discussion

24.	13.\)If the mean of 5 observations x, x + 2, x +4, x +6, x +8 is 11, then findthe value of x.3
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Discussion

25.	the Valve
Answer» Cos theta =4/5soAC=5BC=4By Pythagoreas theorem find another value.AB= 3tan theta = opposite of theta/ adjacent of theta=3/4

Discussion

26.	Find the valve
Answer» a^0 = 1 = 1+1/1 = 2 1+1 = 2 / 1 then answer is 2/1

26.

Find the valve

Answer»

a^0 = 1

= 1+1/1

= 2

1+1 = 2 / 1 then answer is 2/1

Discussion

27.	andthe valve1122
Answer» the answer is 1/81 correct or not the correct answer is 81 √(81)^(-2)9^(-2)81^(-1)1/81

27.

andthe valve1122

Answer»

the answer is 1/81 correct or not

the correct answer is 81

√(81)^(-2)9^(-2)81^(-1)1/81

Discussion

28.	sino + caste? Smarest valve
Answer» We Know that Sin^2x Also Cos^2x >= Cos^4x Add sin^2x both sides Cos^2x + sin^2x>= Cos^4x+sin^2x 1>= Cos^4x+sin^2x Therefore max of A is 1 Also both terms Cos^4x+sin^2x = (1 –sin^2x)^2 +sin^2x = 1 + sin^4x – 2sin^2x + sin^2x =Sin^4x – sinn^2x + 1 = (sin^2x – 1/2)^2 + 3/4 now Min =3/4 and Max = 1

28.

sino + caste? Smarest valve

Answer»

We Know that

Sin^2x

Also Cos^2x >= Cos^4x

Add sin^2x both sides

Cos^2x + sin^2x>= Cos^4x+sin^2x

1>= Cos^4x+sin^2x

Therefore max of A is 1

Also both terms

Cos^4x+sin^2x

= (1 –sin^2x)^2 +sin^2x

= 1 + sin^4x – 2sin^2x + sin^2x

=Sin^4x – sinn^2x + 1

= (sin^2x – 1/2)^2 + 3/4

now Min =3/4 and Max = 1

Discussion

29.	sove it100 - 2+206+ bor a +298b+bXb
Answer»

Discussion

30.	Ay आम >ANO100 ~ [) (रद ०2+ ड।il (vwm = (Vv;uw 1कप 2a0ly
Answer» L.H.S:1+tan^2A/1+cot^2A=(1+sin^2A/cos^2A)/(1+cos^2A/sin^2A)=((cos^2A+sin^2A)/cos^2A)/(sin^2A+cos^2A)/sin^2A=(1/cos^2A)/(1/sin^2A)=1/cos^2Asin^2A/1=sin^2A/cos^2A=tan^2A M.H.S:(1-tanA/1-cotA)^2=(1+tan^2A-2tanA)/(1+cot^2-2cotA)=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)=(sec^2A-2sinA/cos A)/(cosec^2A-2cosA/sinA)=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)=sin^2A/cos^2A=tan^2A R.H.S = tan^2A Hence L.H.S=M.H.S=R.H.S

30.

Ay आम >ANO100 ~ [) (रद ०2+ ड।il (vwm = (Vv;uw 1कप 2a0ly

Answer»

L.H.S:1+tan^2A/1+cot^2A=(1+sin^2A/cos^2A)/(1+cos^2A/sin^2A)=((cos^2A+sin^2A)/cos^2A)/(sin^2A+cos^2A)/sin^2A=(1/cos^2A)/(1/sin^2A)=1/cos^2A*sin^2A/1=sin^2A/cos^2A=tan^2A

M.H.S:(1-tanA/1-cotA)^2=(1+tan^2A-2tanA)/(1+cot^2-2cotA)=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)=(sec^2A-2*sinA/cos A)/(cosec^2A-2cosA/sinA)=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)=sin^2A/cos^2A=tan^2A

R.H.S = tan^2A

Hence L.H.S=M.H.S=R.H.S

Discussion

31.	C) Find the coordinative of the centroid of the triangle whose vertices are(x1 , yı, zı ) (X2,y2 , z2 ) and (x3 , уз-4).
Answer» Centroid of the triangle= [(x1+x2+x3)/3],[(y1+y²+y3)/3] Please hit the like button if this helped you

31.

C) Find the coordinative of the centroid of the triangle whose vertices are(x1 , yı, zı ) (X2,y2 , z2 ) and (x3 , уз-4).

Answer»

Centroid of the triangle= [(x1+x2+x3)/3],[(y1+y²+y3)/3]

Please hit the like button if this helped you

Discussion

32.	रक्त परिसंचरणBLOOD CIRCULATION)
Answer» blood are moving from one nerve to another nerves learn how blood circulation occur Thecirculatory system, also called thecardiovascular systemor thevascular system, is anorgan systemthat permitsbloodto circulate and transportnutrients(such asamino acidsandelectrolytes),oxygen,carbon dioxide,hormones, andblood cellsto and from thecellsin the body to provide nourishment and help infighting diseases,stabilize temperatureandpH, and maintainhomeostasis. Theblood circulatorysystem (cardiovascular system) delivers nutrients and oxygen to all cells in the body. It consists of the heart and thebloodvessels running through the entire body. The arteries carrybloodaway from the heart; the veins carry it back to the heart.

32.

रक्त परिसंचरणBLOOD CIRCULATION)

Answer»

blood are moving from one nerve to another nerves

learn how blood circulation occur

Thecirculatory system, also called thecardiovascular systemor thevascular system, is anorgan systemthat permitsbloodto circulate and transportnutrients(such asamino acidsandelectrolytes),oxygen,carbon dioxide,hormones, andblood cellsto and from thecellsin the body to provide nourishment and help infighting diseases,stabilize temperatureandpH, and maintainhomeostasis.

Theblood circulatorysystem (cardiovascular system) delivers nutrients and oxygen to all cells in the body. It consists of the heart and thebloodvessels running through the entire body. The arteries carrybloodaway from the heart; the veins carry it back to the heart.

Discussion

33.	If A =2 6find the matrix D such that3 -23A-2B + 2D0
Answer»

Discussion

34.	\begin{array}{l}{\text { 1) Solve this Question }} \\ {\frac{2^{50}}{(1-i)^{100}}+\frac{(1+\dot{t})^{100}}{2^{50}}}\end{array}
Answer» Plz post on complete answer Plz bhai post on complete ans. I donot understand

34.

\begin{array}{l}{\text { 1) Solve this Question }} \\ {\frac{2^{50}}{(1-i)^{100}}+\frac{(1+\dot{t})^{100}}{2^{50}}}\end{array}

Answer»

Plz post on complete answer

Plz bhai post on complete ans. I donot understand

Discussion

35.	1/2(3a/5+4)>1/3(a-6)
Answer» 3(3a/5+4)>2(a-6)9a/5+12>2a-1212+12>2a-9a/524>a/5so a<120

Discussion

36.	19. In the given figure PQ 11 ST, <POR= < 110Â°, and RST-130Â°find-QRS
Answer» Please like the solution 👍 ✔️ PQ \|\| ST, ∠PQR = 110° and ∠RST = 130° Construction, A line XY parallel to PQ and ST is drawn. ∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70° Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50° Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60°

36.

19. In the given figure PQ 11 ST, <POR= < 110Â°, and RST-130Â°find-QRS

Answer»

Please like the solution 👍 ✔️

PQ || ST, ∠PQR = 110° and ∠RST = 130°

Construction,

A line XY parallel to PQ and ST is drawn.

∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70°

Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50°

Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60°

Discussion

37.	ant is moving around a few food pieces of different shapes scaForoor5. or which food-piece would the ant have to take a longer roun2r,where rference of a circle can be obtained by using the expressionis the radius of the circle--2.8 cm(c)15 cm-2.8 cm-2.8 cm-
Answer»

Discussion

38.	Find the area bounded by the line y = x, the x-axis and the ordand x=2.]
Answer»

Discussion

39.	If x + y + z = 9, xy + yz + zx40, find the value of x2 + y2 + Z2
Answer» (x+y+z)² = x²+y²+z²+ 2(xy+yz+zx) putting all the values we get => x²+y²+z²= 9²-2(40) = 81-80 = 1. answer.

Discussion

40.	水x, y. z 3RTTสั ส27 Ilf x, y, z arc distinct and]PB Board 1991c](xyz) (xy + yz +び) = (x + y + z)
Answer»

Discussion

41.	Ifx + y _-z = 4 and x2 +y2 +Z2 = 30, then find thevalue of xy - yz - zx
Answer»

Discussion

42.	x2y2 + xyz + xy + z Factonise
Answer»

Discussion

43.	ORIf x = a secA CosB,y=bSecA SinB and z_cTanA, then Prove that atbix2 y2 z2-2'2-1
Answer» Like if you find it useful

Discussion

44.	9 x^2 + 12 xy + 4 y^2
Answer» 9x² + 12xy + 4y²(3x)² + 2× 3x × 4y + (2y)²(3x+2y)²

Discussion

45.	4(2) x xy(3) 2 (x x y)(4) xy
Answer» savvy कळाले नाही

45.

4(2) x xy(3) 2 (x x y)(4) xy

Answer»

savvy

कळाले नाही

Discussion

46.	19. In the given figure PQ II ST, <POR 110Â°, and RST-130 find <QRS
Answer» Interior angles on the same side of thetransversal: The pair of interior angles on the same side ofthe transversal are called consecutive interior angles or allied angles or cointerior angles. If a transversal intersects two Parallel Linesthen each pair of interior angles on the same side of the transversal is supplementary. If a transversal intersects two lines such thata pair of alternate interior angles is equal then the two lines are parallel. Given, PQ \|\| ST, ∠PQR = 110° and ∠RST = 130° Construction, A line XY parallel to PQ and ST is drawn. ∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70° Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50° Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60° Like my answer if you find it useful!

46.

19. In the given figure PQ II ST, <POR 110Â°, and RST-130 find <QRS

Answer»

Interior angles on the same side of thetransversal:

The pair of interior angles on the same side ofthe transversal are called consecutive interior angles or allied angles or cointerior angles.

If a transversal intersects two Parallel Linesthen each pair of interior angles on the same side of the transversal is supplementary.

If a transversal intersects two lines such thata pair of alternate interior angles is equal then the two lines are parallel.

Given,

PQ || ST, ∠PQR = 110° and ∠RST = 130°

Construction,

A line XY parallel to PQ and ST is drawn.

∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70°

Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50°

Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60°

Like my answer if you find it useful!

Discussion

47.	In the given figure, S and T are points on the sidesPQ and PR respectively of APQR, such thatPT-2 cm, TR 4 cm and ST 11 QR. Find the ratio ofthe areas of APST and ΔPQR.CBSE 2010
Answer»

Discussion

48.	Question 3and Bfind the matrix D such that-2 63A-2B+2D =0
Answer»

Discussion

49.	In the figure, BC is the diameterof a circle with centre O. IfABand CD are two chords suchthat seg ABprove that AB = CDc'<ーーーーーーーーフ/p11seg CD, thenContruction:Proof:
Answer» Join AD passing through O. Now in triangle ∆AOB and ∆ COD CO = OB ( radius) angle B = angle C ( Alternate angle) angle AOB = angle COD ( vertically opposite angle) By AAS rule ∆AOB and ∆ COD are congurent. By CPCT AB = CD

49.

In the figure, BC is the diameterof a circle with centre O. IfABand CD are two chords suchthat seg ABprove that AB = CDc'<ーーーーーーーーフ/p11seg CD, thenContruction:Proof:

Answer»

Join AD passing through O.

Now in triangle ∆AOB and ∆ COD

CO = OB ( radius)

angle B = angle C ( Alternate angle)

angle AOB = angle COD ( vertically opposite angle)

By AAS rule ∆AOB and ∆ COD are congurent.

By CPCT AB = CD

Discussion

50.	re, AB 11 CD. The line segments BC and AD intersect at O. Show that : z = x +y.
Answer» As AB \|\| CD BAO = x° ( corresponding angles)x+y + AOB = 180° ( sum of angles in traingle) z + AOB = 180°180° - z = angle AOBx+y + 180° -z = 180°x+y = z

50.

re, AB 11 CD. The line segments BC and AD intersect at O. Show that : z = x +y.

Answer»

As AB || CD BAO = x° ( corresponding angles)x+y + AOB = 180° ( sum of angles in traingle)

z + AOB = 180°180° - z = angle AOBx+y + 180° -z = 180°x+y = z

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

ABCD is atraperium in which AB IDC. BD is a diagonal and Eisthe mid-printofALA line is drawn through E parallel to AB intersecting BC at F(see F 836)Sho tF is the mid-point of BC4.

f AD. AABCD is a trapezium in which AB//DC, BD is a diagonal and E is the mid-pointoline drawn through E parallel to AB intersecting BC at F. Show that F is the midpoint oBC.2

1.Atowerstandsverticallyonthe ground. From apoint on the ground, 20 m away from the1. A tfoot of the tower, the angle of elevation of the top of the tower is 60°. What is the height ofthe tower?

29. A tower stands Vertically on the ground. From a point on theground, which is 75m away from the foot of the tower, theangle of elevation of the top of the tower is found to be 60Â°Find the height of the tower.

Example 1 : A tower stands vertically on the ground. From a point on the ground,which is 15 m away from the foot of the tower, the angle of elevation of the top of thetower is found to be 60o. Find the height of the tower

Example 1 : A tower stands vertically on the ground. From a point on the groundwhich is 15 m away from the foot of the tower, the angle of elevation of the top of tetower is found to be 60Â°. Find the height of the tower.

of(ii) telocity of a train changes from 20m/s to 25 mn when it accelentes dii2s Find the distance covered by the train

ABCD is a trapezium in which AB I DC, BD is a diagonal and E is the mid-point ofine is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30).Show that F is the mid-point of BC.

-49*c^2 %2B 28*(b*c) %2B 25*a^2 - 4*b^2

1. The marks obtained by 20 students in an examination are as under:20, 35, 35, 20, 38, 40, 39, 38, 39, 38, 40, 39, 41, 42, 41, 42, 43, 48, 39, 42.Find the median and mode of the marks.

: The scale of a map is given as 1:30000. Two cities are 4 cm apant on the mapFind the actual distance between them.

1-sin?30° cos®60°+ cos®30°xS ~sin 60° tan 30°1+sin’45° cosec?90°—cot”90°

.28From an aeroplane vertically above a straight horizontal plane, the angles of depression ofo consecutive kilometer stones on the opposite sides of the aeroplane are found to be α and βtan α tan βthat the height of the aeroplane istan α + tan β

A tower stands vertically on theoint on the ground which is 25 mapot of the tower, the angie of elevation of the topf the tower is found to be 45e . Then, find theight (in metres) of the tower.ground. From aaway from

25 a ^ 2 - 4 b ^ 2 %2B 28 b c - 49 c ^ 2

limit X3X+2

x3x-100(ii) 2x2 +x-60

25 a ^ { 2 } - 4 b ^ { 2 } + 28 b c - 49 c ^ { 2 }

03. Beni opened his history book, and noticed that the product of the two pages in front ofhim was equal to 1122. What were the numbers of those pages?

9. What is the domain of the functionx3x+

Use the formula to findthe valve (52848

Where S is non empty subset ofove that: Lim (1+x)½-e-x-&gt;0

If the difference between the probabilities of happening &amp; nonhappening of an event E is3/7. Find the probability of happeningof the event E

13.\)If the mean of 5 observations x, x + 2, x +4, x +6, x +8 is 11, then findthe value of x.3

the Valve

Find the valve

andthe valve1122

sino + caste? Smarest valve

sove it100 - 2+206+ bor a +298b+bXb

Ay आम &gt;ANO100 ~ [) (रद ०2+ ड।il (vwm = (Vv;uw 1कप 2a0ly

C) Find the coordinative of the centroid of the triangle whose vertices are(x1 , yı, zı ) (X2,y2 , z2 ) and (x3 , уз-4).

रक्त परिसंचरणBLOOD CIRCULATION)

If A =2 6find the matrix D such that3 -23A-2B + 2D0

\begin{array}{l}{\text { 1) Solve this Question }} \\ {\frac{2^{50}}{(1-i)^{100}}+\frac{(1+\dot{t})^{100}}{2^{50}}}\end{array}

1/2(3a/5+4)&gt;1/3(a-6)

19. In the given figure PQ 11 ST, &lt;POR= &lt; 110Â°, and RST-130Â°find-QRS

ant is moving around a few food pieces of different shapes scaForoor5. or which food-piece would the ant have to take a longer roun2r,where rference of a circle can be obtained by using the expressionis the radius of the circle--2.8 cm(c)15 cm-2.8 cm-2.8 cm-

Find the area bounded by the line y = x, the x-axis and the ordand x=2.]

If x + y + z = 9, xy + yz + zx40, find the value of x2 + y2 + Z2

水x, y. z 3RTTสั ส27 Ilf x, y, z arc distinct and]PB Board 1991c](xyz) (xy + yz +び) = (x + y + z)

Ifx + y _-z = 4 and x2 +y2 +Z2 = 30, then find thevalue of xy - yz - zx

x2y2 + xyz + xy + z Factonise

ORIf x = a secA CosB,y=bSecA SinB and z_cTanA, then Prove that atbix2 y2 z2-2'2-1

9 x^2 + 12 xy + 4 y^2

4(2) x xy(3) 2 (x x y)(4) xy

19. In the given figure PQ II ST, &lt;POR 110Â°, and RST-130 find &lt;QRS

In the given figure, S and T are points on the sidesPQ and PR respectively of APQR, such thatPT-2 cm, TR 4 cm and ST 11 QR. Find the ratio ofthe areas of APST and ΔPQR.CBSE 2010

Question 3and Bfind the matrix D such that-2 63A-2B+2D =0

In the figure, BC is the diameterof a circle with centre O. IfABand CD are two chords suchthat seg ABprove that AB = CDc'&lt;ーーーーーーーーフ/p11seg CD, thenContruction:Proof:

re, AB 11 CD. The line segments BC and AD intersect at O. Show that : z = x +y.

-49c^2 %2B 28(bc) %2B 25a^2 - 4*b^2

Where S is non empty subset ofove that: Lim (1+x)½-e-x->0

If the difference between the probabilities of happening & nonhappening of an event E is3/7. Find the probability of happeningof the event E

Ay आम >ANO100 ~ [) (रद ०2+ ड।il (vwm = (Vv;uw 1कप 2a0ly

1/2(3a/5+4)>1/3(a-6)

19. In the given figure PQ 11 ST, <POR= < 110Â°, and RST-130Â°find-QRS

19. In the given figure PQ II ST, <POR 110Â°, and RST-130 find <QRS

In the figure, BC is the diameterof a circle with centre O. IfABand CD are two chords suchthat seg ABprove that AB = CDc'<ーーーーーーーーフ/p11seg CD, thenContruction:Proof: