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19. In the given figure PQ 11 ST, <POR= < 110°, and RST-130°find-QRS |
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Answer» Please like the solution 👍 ✔️ PQ || ST, ∠PQR = 110° and ∠RST = 130° Construction, A line XY parallel to PQ and ST is drawn. ∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70° Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50° Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60° |
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